This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The sum of the first 10 terms of an arithmetic sequence is 583 |
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| 2. |
The sum of digit of a two digit number is 12. the number obtained by inter changing the digit exceeds the given number by 18 .find the number |
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Answer» LET the TENS digit be x and the UNITS digit be y. So the number=10x+y A.q. x+y=12 x=12-y (equation 1) After interchanging the number we get =10y+x Also, (10y+x)-(10x+y)=18 10y+x-10x-y=18 9y-9x=18 9(y-x)=18 y-x=18/9 y-x=2 From eauation 1 x=12-y So, y-(12-y)=2 y-12+y=2 2y=12+2 2y=14 y=14/2 y=7 And x=12-y =12-7 =5 Hence the number is 57. |
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| 3. |
The sum of a two digit no. and the no.formed by interchanging the digits is 132 |
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Answer» Let the digits be a and B,where b is the unit number and a is the TENTH PLACE number.. |
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| 4. |
2^250, 3^150,5^100,4^200 the smallest among these numbers |
| Answer» 100 is the SMALLEST these NUMBERS | |
| 5. |
20, - 18,-56,-91,-132,next |
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Answer» ACTUALLY it is an ARITHMETIC progression next term will be -150 |
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| 6. |
Fill in the blanks1) (2x-3y)³= ?2)(2x+y-z)² = ?3)(3a+b)³ = ? |
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Answer» X = 1+√2 + √3; then find 2X4 – 8x3 – 5x2 + 26x – 28. A) 6 √6 ... Now (x + 1/x) ² = 3 (given) => x + 1/x .... x³ – 8 – 6x(x – 2) = ( 21/3)³ + (22/3)³ + 3(21/3 x 22/3)(21 ... |
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| 7. |
There is a equilateral triangle in a circle then ratuo of diameter and triangle side will be |
| Answer» YES the ratio of the DIAMETER and the SIDES of that PARTICULAR triangle are same | |
| 8. |
The ratio of the two number is 3:4 and their hfc is 4 their lcm is |
| Answer» LCM of the NUMBERS is 4 | |
| 9. |
Find the difference between simple interest and compound interest for 3years at 10% per annum when the interest is compounded annually on 30000 |
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Answer» Here is your SOLUTION. |
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| 10. |
Try these from the digitas 3,0and 4,make five numbers each with 6digits .use comms |
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Answer» 300004,300040, 300400, 304000, 340000 , 400003, 400030, 400300, 403000 , 430000 . this is the ANSWER |
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| 11. |
What is Heron’s Formula? Why is it used for? |
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Answer» This formula is used for calculating Area of triangle with different SIDES the name Heron's TAKEN from the name : Now, the Heron's formula is:- where, a , b , c are the sides of the triangle And " S " is semi - perimeter for finding the VALUA of S = (a + b + c)/2 it's unit is cm² , m² Hope this help you |
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| 12. |
6. in parallelogram abcd above what is the measure of ?adc? (1) the measure of ?abc is greater than 90o. (2) the measure of ?bcd is 70o |
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| 13. |
five bad oranges are accidentally mixed with 20 good ones. if four oranges are drawn one by one successively with replacement then find the probability distribution of number of bad oranges drawn. hence find the mean and variance of the distribution. |
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| 14. |
there are 8 teachers in a school .when a 35 year old teacher was transfered and another teacher joined,the average age was increased 2 year .how old is t e new teacher? |
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Answer» Average = (Total Quantity)/ Number of quantity So, Let the average AGE of teachers be x Let y be the age of teacher that JOINED So, Total age of 8 teachers when 35 year old one did not LEAVE was, =8x When 35 year old leave and new one joined then, Total sum of ages = 8x -35 + y Now, The average of this increased by 2 SO, (8x -35 + y)/8 = x + 2 8x -35 + y = 8x +16 -35 + y = 16 y = 35 +16 y=51 So, A 51 year old teacher joined the SCHOOL |
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| 15. |
In a trapezium, if distance between parallel sides is 6 cm and lengths of the parallel sides are 7 cm and 8 cm respectively then find the area of the trapezium. |
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Answer» SOLUTION : Given the parallel sides 7 CM and 8 cm . distance between parallel sides i.e. HEIGHT = 6 cm Area of the trapezium = SUM of parallel sides × height ⇒ Area of the trapezium = (7+8)cm × 9 cm ⇒ Area of the trapezium = 15×6 cm² ∴ Area of the trapezium = 90 cm² . (answer) |
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| 16. |
An old book was bought for Rs 1520 and sold for 1444. Find the loss per cent |
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Answer» Loss = CP - SP |
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| 17. |
There is a loss of Rs 50 by selling a book at Rs 250. Find the cost price and loss per cent |
| Answer» 200 is the PRICE and 20% is the LOSS | |
| 18. |
Write the following number in expand form 205.45 |
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Answer» 205.45 = 200 + 00 + 5 + 0.40 + 0.05 |
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| 19. |
The mean of numbers a,b,c,d is 100. if c = 70 , then mean of the remaining number is |
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Answer» 73758358+555++85848493(8503)84949490/944932)₹&3(8482|π÷•÷|`×^=${¶^=√==•÷ו37847937504)(89993 |
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| 20. |
An article is bought for Rs 300 and zold for Rs 315.Find the profit and the profit per cent |
| Answer» PROFIT will be 5 % ...... | |
| 21. |
Find the number that logically completes the series : 3, 4, 6, 8, 12, 16, ..................., 32, 48, 64(a) 18 (b) 20 (c) 28 (d) 24 |
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| 22. |
If 5 x 4=12 and 8 x 7=42 then 9 x 8 ............(a) 24 (b) 48 (c) 40 (d) 36 |
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| 23. |
In the following number how many 1?s are there which are immediately followed by 0? and notimmediatelypreceded by 5?. 5210638215901210421(a) 0 (b) 2 (c) 3 (d) 1 |
| Answer» HEY MATE the ANS is C THREE | |
| 24. |
Write in the form of p/q :- 7.5bar |
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| 25. |
Area of a rhombus is 96 sq cm. One of the diagonals is 12 cm find the length of its side. |
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Answer» The area of the side of the rhombus WOULD be 10 CM. You can use the formula to FIND the area of the rhombus to find the length of the other diagonal and side. I HOPE this helps! |
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| 26. |
Two workers a and b workingtogether completed a job in 5 days. if a worked twice as efficiently as he actually did and b worked 13 as efficiently as he actually did, the work would have been completed in 3 days. a alone could complete the work in? |
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Answer» let A can do alone the work in x DAYS let B can do alone the work in y days CASE-I A's 1 day work =1/x B's 1day work =1/y (A+B)'s 1day work =1/5 therefore,1/x+1/y=1/5 ------------(1) CASE-II A had worked as efficiently as he actually did nd B had worked 1/3 as he actually did A's 1day work =2/x B's 1day work =1/3y (A+B)'s 1 day work =1/3 therefore,2/x+1/3y=1/3 ----------------(2) solving eqn (1) nd (2) we GET x=6.25 there fore A can alone work in 6.25 days hope it HELPS you. . . . follow me. . . . . MARK as a brainlist. . . . . |
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| 27. |
The hcf of two numbers is 145 and their lcm is 2175 phone no. is 125 find the other no. |
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Answer» Heya !! |
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| 28. |
Pls provide the answer for the attached question(spam answers will be reported) |
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| 30. |
A length of 7 micro millimetre is :(a) 0.000000007 mm (b) 0.00000007 mm (c) 0.0007 mm (d) 0.000007 mm |
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Answer» HEY MATE , HERE IS YOUR ANSWER.✌✌ ANSWER IS OPTION ( B ) 0.00000007 mm HOPE IT HELPS U.✌✌ #BE BRAINLY. THNKS.❤❤ |
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| 31. |
2101 -2100 -299 is equal to :(a) 299 (b) 298 (c) 2100 (d) 3 (298) |
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| 32. |
.What is the rational number equal to 0.712712712.................a(a) 712/10 (b) 712/1000 (c) 712/999 (d) 7127/9999 |
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Answer» The RATIONAL number equal to 0.712712712 is C. 712/999. This is because, after DIVIDING to find the decimals of these FRACTIONS, the answers are: a. 712/10= 71.2 b. 712/1000= 0.712 c. 712/999= 0.712712... d. 7127/9999= 0.71277 The ANSWER is c. I hope this helps! :) |
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| 33. |
If each of the dimensions of a rectangle is increased by 200%, then the area is increased by :(a) 300% (b) 200% (c) 800% (d) 600% |
| Answer» OPTION (C) is CORRECT | |
| 34. |
4 2/3x125 -2/3 x3 5/5 |
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Answer» 4 2/3x125 -2/3 X3 5/5 = 1750- 70/15 = 1750- 14/3 = 5250-14/3 = 5236/3 =1745.33 |
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| 35. |
If Area of a parallelogram is 112 sq cm and base of it is 10 cm then find its height |
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Answer» HELLO MATE ☺ _____________________________⭐⭐⭐ Area of Parallelogram = 112 cm^2 Base of Parallelogram = 10cm HEIGHT (h) = ???? As we KNOW that : Area of PARALLEGRAM = Base×Height 112 = 10 × Height 112 /10 = Height Height = 11.2cm SO , HEIGHT OF PARALLELOGRAM IS 11.2cm ✔ ______________________________⭐⭐⭐ HOPE IT HELPS U✌✌ ^_^ |
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| 36. |
The difference between the digit of a two digit number is 4 .the sum of the number and the number formed by reversing its digits is 110. find the two digit number |
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Answer» Let the TENS digit be x and the UNITS digit be y. |
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| 37. |
The cost of packaging of the oranges is 20% the cost of fresh oranges themselves. the cost of oranges increased by 30% but the cost of packaging decreased by 50%, then the percentage change of the cost of packed oranges, if the cost of packed oranges is equal to the sum of the cost of fresh oranges and cost of packaging |
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Answer» Answer: The percentage CHANGE of the cost of packed oranges is 16.6%. Step-by-step explanation: Given : The cost of packaging of the oranges is 20% the cost of FRESH oranges themselves. The cost of oranges increased by 30% but the cost of packaging DECREASED by 50%. To find : The percentage change of the cost of packed oranges, if the cost of packed oranges is equal to the sum of the cost of fresh oranges and cost of packaging? Solution : Let the cost of oranges be Rs.100. The cost of packaging of the oranges is 20% the cost of fresh oranges themselves. Packaging cost is Initial total cost = Cost of oranges + Packaging cost Initial total cost = 100 + 20 Initial total cost = Rs.120 The cost of oranges increased by 30% but the cost of packaging decreased by 50%. i.e. the cost of the oranges = The cost of packaging = Fresh total cost = 130+10=Rs.140. Increased cost = Fresh total cost - Initial total cost Increased cost = 140-120 Increased cost = 20 Percentage increased cost is THEREFORE, The percentage change of the cost of packed oranges is 16.6%. |
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| 38. |
Sin2x=1/5 then sinx + cosx = |
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Answer» |
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| 39. |
Find the largest 2 numbers and the smallest 2 numbers in the given array |
| Answer» 99 is the largest 2 DIGIT number & 10 is the SMALLEST 2DIGIT number | |
| 40. |
Find the sum of all numbers of 4 digits without repetition using 1 2 0 0 |
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| 41. |
P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD show that ar(ΔAPB)=ar Δ(BQC). |
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Answer» If a parallelogram and a triangle are on the same base and between the same parallels then area of the triangle is half the area of the parallelogram. ========================================================== Given: In parallelogram ABCD, P & Q any two POINTS lying on the sides DC and AD. To show: ar (APB) = ar (BQC). Proof: Here, ΔAPB and ||gm ABCD stands on the same base AB and lie between same parallel AB and DC. Therefore, ar(ΔAPB) = 1/2 ar(||gm ABCD) — (i) Similarly, Parallelogram ABCD and ∆BQC stand on the same base BC and lie between the same parallel BC and AD. ar(ΔBQC) = 1/2 ar(||gm ABCD) — (II) From eq (i) and (ii),we have ar(ΔAPB) = ar(ΔBQC) HOPE this will help you... |
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| 43. |
What is the median of the following data? 23,32,24,35,36,37,27(a) 27 (b) 35 (c) 32 (d) 30 |
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| 44. |
The sum of two number is 97 and their difference is 37. of the product |
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Answer» SEE the ATTACHED file for answer HOPE MY ANSWER SATISFIED YOU AND IF IT THEN MARK IT AS BRAINLIEST ANSWER |
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| 45. |
The area of a rectangle be x^2+7x+10 sq cm,then one of the possible perimeter of it is |
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Answer» See the answer in the attached FILE |
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| 46. |
How many terms are their in the AP 2,9,16,.....,261? |
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| 47. |
A principal amounts to ₹13924 in 2 years by compound interest at 18 p.c.p.a. Find the principal. |
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Answer» Given, amount, A = ₹ 13924 |
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| 48. |
What is the percentage increase in the area of a rectangle if the sides are increased by 25%. |
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| 49. |
Sum of two number is 576,their sum exceeds their difference 36 ,then what is the sum of two number |
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Answer» a+b=576 a+b=(a-b)+36 hence, a=558, b=18 |
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| 50. |
Sum of two consecutibe odd numbers is 56 then numbers are |
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Answer» |
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