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The FRACTION is RECIPROCAL of 17/6 that is 6/17

LET z = 100
Then x = 80
y = 72
Yis LESS by x = 8
% = 8*100/80
= 10%

2^1 (mod 10) = 2

2^2 (mod 10) = 4

2^3 (mod 10) = 8

2^4 (mod 10) = 6

2^5 (mod 10) = 2

It's clear that the units DIGITS of the POWERS of TWO repeat in this pattern. Thus, no power of two will have a units DIGIT of 6.

Sum of other TWO SIDES = 30 - 13 = 17 cm

Then, let the sides as ( x ) and ( 17 - x )

By PYTHAGORAS theorem,

( x )² + ( 17 - x )² = 13²

x² + 289 + x² - 34x = 169

2x² + 120 - 34x = 0

x² - 17x + 60 = 0

x² - 12x - 5x +60 = 0

x( x - 12 ) + 5( x - 12 ) = 0

( x - 12 )( x + 5 ) = 0

By Zero Product Rule,

x = 12 [ positive value ]

Other side = 17 - 12 = 5 cm

.

Other sides = 12 cm and 5 cm

I THINK the ANSWER is
-√6sin65
I HOPE it HELPS U

If 2 and 5 are solutions to the polynomial, the polynomial must be divisible by

(x - 2) and (x - 5). Since it's a quadratic, the polynomial must then be

a(x - 2)(x - 5)

Where "a" is some constant. EXPANDING, we get:

a(x - 2)(x - 5) = ax^2 -7ax + 10a

This is supposed to be EQUIVALENT to the original:

ax^2 -7ax + 10a = px^2 - 7x + 5f

From this, it becomes OBVIOUS that a = 1, p = 1, and F = 2.

We know Max VALUE is TAKEN out by underroot of (a^2+B^2). So by keeping a=1 and b= (ROOT3) we get Max value as underroot 4 i.e equal to 2.
Thank you

Hey DUDE see the ANSWER in the ATTACHED file
IF MY ANSWER SATISFIED YOU MARK IT AS BRAINLIEST ANSWER

Let PRINCIPAL is P
interest rate , r = 10 % PER annual
time PERIOD , n = 3
Amount , A = 6655

USE formula , A = P(1 + r/100)ⁿ
6655 = P(1 + 10/100)³
6655 = P(1 + 1/10)³ = P(11/10)³
6655 = P(1331/1000)
6655 × 1000/1331 = P
P = 6655 × 1000/1331 = 5000

HENCE, principal is ₹ 5000

Let the NUMBERS are ( x ) and ( 5x )

Given, their product = 320

x × 5x = 320



SUM of numbers [ taking NEGATIVE values ]

x + 5x
=> ( - 8 ) + 5( - 8 )
=> -48

Sum of numbers [ taking positive values ]

=> x + 5x
=> 8 + 5(8)
=> 48





Neglect negative value, their sum = 48



Option ( B ) is correct

Answer is d =149
because 149 is divided by 12 than 12*12 =144 leaves a REMINDER 5
149 is divided by 16 than 16*9=144, leaves a reminder 5
149 is divided by 18 than 18*8=144,leaves a reminder 5

Average = ( SUM of quantities ) / ( number of quantities )



Now,

15 = ( sum of 30 ages ) / 30

450 = sum of 30 ages





When the AGE of TEACHER is included, average increases by 1

ATQ,


16 = ( 450 + age of teacher ) / 31

496 = 450 +age of teacher

46 = age of teacher





Option is correct.

OPTION c

60 DEGREE should be your ANSWER

The ANSWER of QUESTION is 13.7519

Given data:

The fraction 24/64 is in the ratio 24:64

Solution:

DIVIDING the ratio by 8, we GET the RESULT as 3:8

To get the numerator as 15, let’s multiply the ratio by 5

So, we get the ratio as 15:40

Hence, the EQUIVALENT fraction of 24/64 is 15/40.

Initial AMOUNT = 60,000
falling rate per year = 20%
DECREMENT of amount in 1st year =20 % of 60,000
= 20 × 60,000/100 = 20 × 600 = 12,000
now, rest amount = 60,000 - 12,000
= 48,000

decrement of amount in 2nd year = 20% of 48,000
= 20 × 48,000/100 = 20 × 480
= 9,600
now, rest amount = 48,000 - 9,600
= 38,400 Rs

hence, price of scooter after TWO YEARS = 38,400 Rs.

The population of a city increases at compounding rate of 8 %
e.g., interest rate , r = 8 %
period , n = 2012 - 2010 = 2 YRS
population in the YEAR 2010 was 2,50,000
e.g., P = 2,50,000

USE formula,
A = 2,50,000 × (1 + 8/100)²
= 2,50,000 × (1.08)²
= 2,50,000 × 1.08 × 1.08
= 2,91,600

hence, population in the year 2012 = 2,91,600

40/56...............

Here is your solution :

If,

Case 1,

⇒ 9 × 3 + 8 = 24

Just change ( × into ÷ ) and ( + into × )

⇒ 9 ÷ 3 × 8 = 24

⇒ 3 × 8 = 24

•°• 24 = 24

Case 2,

⇒ 10 × 2 + 7 = 35

⇒ 10 ÷ 2 × 7 = 35

⇒ 5 × 7 = 35

•°• 35 = 35

Case 3,

⇒ 80 × 40 + 3 = 6

⇒ 80 ÷ 40 × 3 = 6

⇒ 2 × 3 = 6

•°• 6 = 6

In all three cases we got that if we convert the sign of Multiplication in Division and sign of Addition in Multiplication then it satisfies the given equation.

So,

= 12 × 4 + 3

= 12 ÷ 4 × 3

= 3 × 3

= 9

Hence , the required answer is 9.

Your ANS is here MISSING NUMBER is 76

Let TOTAL MARKS be x
Passing Marks = 112-32= 80
Now
80+70 = 75% of x
x= 150 * 100/75
x= 200

Now
Pass % Marks = 80*100/200
= 40%

(C) 560
3/4 of 560 is 420
4/7 of 560 is 320
The difference between 420 and 320 is 100 so THEREFORE (c) MUST be the answer

No. of roads by which he can go = 5

No. of roads by which he can return=4
(since it is GIVEN he cannot COME back from the same ROAD)

total no. of POSSIBILITIES = 4×5
= 20

Ans: (d) 20


Hope it HELPS

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(d) 47
The two DIGITS in the number 47 is 4 and 7. The SUM of those two digits is 11. If 27 was added to 47 it would equal 74. The digits 4 and 7 changed places as the 4 moved to the ones SPOT while 7 moved to the tens spot.

The answer is 1100 because when we divide 2 by 1100 we GET 550 ,by 5 we get 220,by 10 we get 110 and by 11 we get 100

When increasing your multiplying x>1 because 45 times 1 is 45 to get 75 you MULTIPLY by approximately 1.65

when you DECREASING your multiplying x<1 because 72 times 0.6 is 45.

Hi ,

In simple interest the principal remains the

same throughout the period.

Some times the interest is added to principal

and the TOTAL amount is takes as principal

for the next year. Thus both principal and

interest on SUCCESSIVE years keep on

INCREASING . This KIND of calculation is named

as Compound Interest.

************************************************

A = P( 1 + R/100 )ⁿ

where ,

P = Principal ,

A = amount

R = rate of interest for the period of one

computation

n = Number of times that interest has to be

computed

Formula for Compound Interest

C.I = A - P

= P( 1 + R/100 )ⁿ - P

****************************************************

I hope this helps you.

: )

55.56 is MOLARITY of WATER 1000 / 18

Here is your ANSWER..
HOPE this HELPS you

These are the postulates of congruency under which, if two TRIANGLES have the below as congruent then the two triangles are congruent.

(1) S-A-S teststands for SIDE Angle Side according to which if two sides and angle of one triangle is congruent to that of the other than the two triangles are congruent to each other.

Similarly, (2) S-S-S teststands for Side Side Side and (3) A-S-A test stands forAngle Side Angle and (4) A-A-S test stands forAngle Angle Side and (5) Hypotenuse - side test MEANS we can say that two triangles are congruent if the hypotenuse and any one side of the triangle are respectively congruent to that of the other triangle.