1.

If 9* 3 + 8 = 24, 10 * 2 + 7 = 35 and 80 * 40 + 3 = 6, then find the value of 12 * 4 + 3(a) 7 (b) 9(c) 12 (d) 16

Answer»

Here is your solution :

If,

Case 1,

⇒ 9 × 3 + 8 = 24

Just change ( × into ÷ ) and ( + into × )

⇒ 9 ÷ 3 × 8 = 24

⇒ 3 × 8 = 24

•°• 24 = 24

Case 2,

⇒ 10 × 2 + 7 = 35

⇒ 10 ÷ 2 × 7 = 35

⇒ 5 × 7 = 35

•°• 35 = 35

Case 3,

⇒ 80 × 40 + 3 = 6

⇒ 80 ÷ 40 × 3 = 6

⇒ 2 × 3 = 6

•°• 6 = 6

In all three cases we got that if we convert the sign of Multiplication in Division and sign of Addition in Multiplication then it satisfies the given equation.

So,

= 12 × 4 + 3

= 12 ÷ 4 × 3

= 3 × 3

= 9

Hence , the required answer is 9.


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