1.

The sum of a two digit no. and the no.formed by interchanging the digits is 132

Answer»

Let the digits be a and B,where b is the unit number and a is the TENTH PLACE number..

so according to the given CONDITION

(10a+b)+(10b+a) = 132

(11a+11b) = 132

a + b = 12....(1)

so better find combinations of a and b such that their digit sum is 12.. as shown in eq (1)

while we add the ORIGINAL two digit obtained number with the reversed number..the sum should b 132 ( given in the question)

so the two digit number will be either 75 or 57


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