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Question is wrong because TANA × cot A = 1

the right question is
(COSECA - sinA)(secA-cosA) = (1/(tanA+cotA)

SOLUTION:
LHS = (cosecA-sinA)(secA-cosA)
LHS = ((1/sinA)-sinA)((1/cosA)-cosA)
LHS = ((1-sin²A)/sinA)((1-cos²A)/cosA)
[NOTE: 1-sin²A = cos²A and 1-cos²A = sin²A]
LHS = (cos²A/sinA)(sin²A/cosA)
LHS = (cos²A sin²A)/(sinA cosA)
LHS = cosA sinA/1
[note : 1 = sin²A+cos²A]
LHS = cosA sinA/(sin²A+cos²A)
LHS = 1/((sin²A/cosA sinA)+(cos²A/cosA sinA))
LHS = 1/((sinA/cosA)+(cosA/sinA)
[note : sinA/cosA = tanA and cosA/sinA = cotA]
LHS = 1/(tanA + cotA)

LHS=RHS
Hence proved

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Use the IDENTITY: a³ - b³ = (a - b)(a² + AB + b²)

(2X+3Y)³ - (2x-3y)³

= [(2x + 3y) - (2x-3y) ][(2x-3y)² + (2x - 3y)(2x + 3y) + (2x + 3y)² ]

= [ 2x + 3y - 2x + 3y ][(4x² + 9y² - 12xy) + (4x² - 9y²) + (4x² + 9y² + 12xy) ]

= [6y][ 4x² + 9y² - 12xy + 4x² - 9y² + 4x² + 9y² + 12xy ]

= [6y][ 4x² + 4x² + 4x² + 9y² + 9y² - 9y² - 12xy + 12xy ]

= [6y][ 12x² + 9y²]

= 6y×3×(4x² + 3y²)

= 18y(4x² + 3y²)

After 34 COMES 36
After 58 comes 60
After 52 comes 54

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11.10.......... .............

24 , 10 ,26 is the PYTHAGOREAN triplet because

( 24)^2+(10)^2 =(26)^2
676= 676

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12345444 is the EIGHT DIGIT NUMBER which is DIVISIBLE by 4

X4-y4

= 4(x-y)

is your SOLUTION

plzz MARK as brain LIST

If the ARC's shape and size is equal

plz MARK as BRAIN list

Α²+β²=(α+β)²-2αβ

Hope This HELPS You!✌

In the attachments I have answered this problem.

Concept:

Pythagoras THEOREM:

In a right angle triangle, SQUARE on

the hypotenuse is equal to SUM of the

SQUARES on the other TWO sides.

See the attachment for detailed solution.

1.Prove that
ROOT 5 +root 7 is irrational


2.solve LOG 343 to the base49

Yes
Graph of a LINEAR EQUATION
in TWO variable
plzzzzzz give me SOLUTION on
this POINT

SOLUTION :-

Euler's formula for any polyhedron that doesn't intersect itself,

the Number of Faces + Number of VERTICES - the Number of EDGES = 2

This can be written : F + V - E = 2

Some examples are as follows.

Name Faces Vertices Edges F + V - E

Tetrahedron 4 4 6 2

Cube 6 8 12 2

Octahedron 8 6 12 2

Dodecahedron 12 20 30 2

Icosahedron 20 12 30 2

10 m 857 mm= 10857 mm
15m 87mm = 15087 mm
The hcf of the 2 NUMBERS is 141
(i.e) 141 mm.

The PRIME NUMBER is DIVISIBLE by 1 and its own

It will HELP you......

It is UR ANSWER PLEASE MARK it as BRAINLIST

Ar.of equi. TRIANGLE is under root 3|/4 ×a^2
and HEIGHT is under root 3 /2 ×a

5^4^1 = 20 because in last we have to take only 5

I HOPE it is helpful for U
PLZZ mark it in BRAINLIEST

Cloth for 1 trouser = 1m 30 cm = 130cm
Total cloth = 15m = 1500cm

No. of trouser
= total cloth/ cloth required for 1 trouser
= 1500/130
= 11.53

Therefore,
11 TROUSERS can COMPLETELY be MADE out of 150m cloth

Ans: 11


Hope it helps...!!

Here is the formula.Now PUT the VALUE from questions.Here the value of π=3.14 or 22/7.

According to the question,

diameter = 1m or, radius(r) = diameter/2 = 1/2 = 0.5m

height(h) = 2m.

Now, we know that surface area of a cylinder is given by 2πr(h+r)

or, 2 x π x 0.5(2 + 0.5) = 2 x 3.14 x 0.5 x 2.5 = 7.85 square metre.

Since the TANK is to be painted both from inside and outside, so it is quite SURE that the surface area will be simply twice i.e. Total surface area = 2 x 7.85 = 15.7 square metre.

Now, if the rate of painting is ₹ 80 per sqm then, for painting 15.7 sqm the COST incurred = RS 80 x 15.7 = Rs 1256.(Ans)

The FACEBOOK GROUP and ROOT CAUSE the IMAGE is the

Final Answer : True

Explanation :
Let us make a circle of any RADIUS with some centre A.
=>We observe that when distance between centre and any CHORD increases,then Chord LENGTH decreases.
=> Maximum chord length :- Minimum distance between Centre and Chord = 0
=> When distance between centre and chord is 0,then that chord is of max. length.
=> Unfornutalety, we observe that chord (max) is our DIAMETER.

Hii
Good MORNING........!!!!;)
Here'si have ANSWER for this QUESTION...
2*3+5-4=7
7 is the answer.
have a marvelous day.... DEAR.....

Which CLASS QUESTION ..

111101=61--------------------------------------32 16 8 4 2 1

1 1 1 1 0 1

1001=9-----------------------------------------8 4 2 1

1 0 0 1

61/9=7 is the remainder.

Let the third number is x.
then FIRST number = (100-30)% of x
= 70% of x = 7x/10

Second number is (63x/100)

DIFFERENCE = 7x/10 - 63x/100 = 7x/10

So required PERCENTAGE is, difference is what percent of first number

=> (7x/100 * 10/7x * 100 )% = 10%

The SMALLER NUMBER is 45

It's TRUE; no DOUBT....

FALSE!!! It DIVIDES the CIRCLE EQUALLY!!

Hi ,

Dimensions of the CUBOIDAL fish tank :

length = l = 1 m = 100 cm

breadth = b = 40 cm

height = h = 50 cm

Volume of the tank ( V ) = lbh

V = 100 cm × 40CM × 50 cm

V = 200000 cm³

V = 200000 × 1/1000 litres

V = 200 litres

Therefore ,

Capacity of the WATER tank = 200 litres

I HOPE this helps you.

: )

Have you seen your notebook has length , width and height ? Have you see circket BALL it occupies some space on your hand if you take it. what are these ? of course , solid .


for EXAMPLE :- volume of cylinder is given by .
where r is the radius of base of cylinder and h is height of cylinder.
similarly volume of CUBE is

True :

EXPLANATION :
1) LET us consider a circle in x-y plane.
Then, it DIVIDES that plane into THREE different regions.
= Circular part
= Outer part of Circle
= Interior part of circle.

Blue REGION : Interior Part
Dark Red : Circular Part
Light Red : Outer Part.

Let no. = a

2/3 x 3/5 x 1/4 x a = 24

6a/60 = 24

a = 24 x 60/6 = 240

Now,

40 of 240 = 40 x 240 = 9600

hope it help u

plz MARK as a brainliest & follow me

Let the present age of SAMEER be x year.
And, the present age of his father be y years.
A/q
x + y = 54 .............(i)
SIX years AGO,
Sameer's age = x - 6
His father's age = y - 6
Therefore, 6 ( x - 6 ) = ( y - 6 )
====> 6x - 36 = y - 6
====> 6x - y = 30 ..................(ii)
By adding eq. (i) and (ii). We have,
====> x = 12 ..............Answer
Put the value of x = 12 in eq. (i)
====> x + y = 54
====> 12 + y = 54
====> y = 42 .......................Answer
Hence, The present age of Sameer is 12 years.
And, His father's present age is 42 years.