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Two workers a and b workingtogether completed a job in 5 days. if a worked twice as efficiently as he actually did and b worked 13 as efficiently as he actually did, the work would have been completed in 3 days. a alone could complete the work in? |
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Answer» let A can do alone the work in x DAYS let B can do alone the work in y days CASE-I A's 1 day work =1/x B's 1day work =1/y (A+B)'s 1day work =1/5 therefore,1/x+1/y=1/5 ------------(1) CASE-II A had worked as efficiently as he actually did nd B had worked 1/3 as he actually did A's 1day work =2/x B's 1day work =1/3y (A+B)'s 1 day work =1/3 therefore,2/x+1/3y=1/3 ----------------(2) solving eqn (1) nd (2) we GET x=6.25 there fore A can alone work in 6.25 days hope it HELPS you. . . . follow me. . . . . MARK as a brainlist. . . . . |
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