This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 9901. |
Why color-coding is necessary for resistor? |
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Answer» A wide variety of resistors are physically large enough to have their resistance value printed on them. However, carbon composition resistors are too small for this method of identification so a color coding system is used. Four bands are printed on one end of the resistor and are read from the band closest to the end of the resistor toward the center. Each color represents a numerical value as indicated below. |
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| 9902. |
What is the Indian color coding of the wiring for main flex/lead cables |
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Answer» Active-Red, Neutral-Black/Blue, Earth-Green |
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| 9903. |
An organic compound has `% C = 68.85, % H = 4.92 and % O = 26.23` (by mass). Number of carbon atoms present in the Empirical Formula of it is ………….A. `5`B. `6`C. `7`D. `2` |
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Answer» Correct Answer - C An organic compound has `% C` ……….. `C_((68.85)/(12)) H_((4.92)/(1)) O_((26.23)/(16)) or C_(3.5) H_(3)O` `implies EF is C_(7)H_(6)O_(2)` |
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| 9904. |
The flex in the smelting of copper isA. `P_(2)O_(3)`B. `CaO`C. `SiO_(2)`D. `MnO` |
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Answer» Correct Answer - c Durig smelting the roassrted ore is mixed with coke and silica and tranfered to a small blast farunce .The mixture is heated in the processs of axcess of air most of the iron suplhide is oxidiacad to feroms oxide ` 2FeS + 3O_(2) rarr 2FeO+ 2SO_(2)` ferrrous oxide conninace with slice and forms femous slicate by this reaction mass of the iron is reamoved as slag `FeO + SiO_(2) rarr FeSiO_(3)` Thus sillicu is added to raction copper ore during smelting to removes femous oxide (obtained from iron ore, `FeS` as a slag and the is `FeSiO_(3)` Since fe has greater affinality its oxygen than copper the copper oxide formad during smelting rearts with unclanged irons sulphaide to form oxide and reproshare copper sulphide `FeS + cu_(2)O rarr FeO + Cu_(2)S` Thus it is diffcuit to oxide copper sulphide cotil whete of the irons sulphide is oxidoesed |
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| 9905. |
`Mn_(3)O_(4)` when heated with AI powered, gets reduced to produced Mn metal and `AI_(2)O_(3)`. If at least `612 g of AI_(2)O_(3) and 825g of Mn` are to be produced, the minimum amount of `Mn_(3)O_(4)` and AI required is respectively :A. `1030.5g, 324g`B. `1145g, 360g`C. `1030.5g, 406.5 g`D. `1145g, 234g` |
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Answer» Correct Answer - B `Mn_(3)O_(4)` when heated with `AI` powder ……………. `3Mn_(3)O_(4)+8AI rarr 9 Mn+4AI_(2)O_(3)` Minimum moles of `AI_(2)O_(3)` to be produced `= (612)/(102) = 6` & minimum moles of `Mn` to be produced `= (825)/(55) = 15` To produce 6 mole of `AI_(2)O_(3)`, mole required : `n_(Mn_(3)O_(4) = (6xx3)/(4) = 4.5` `n_(AI) = (8xx6)/(4) = 12` To produce 15 moles of Mn, moles required : `n_(Mn_(3)O_(4) = (15xx3)/(9) = 5` `n_(AI) = (15xx8)/(9) = 13.33` `:.` Minimum moles of reactant required : `n_(Mn_(3)O_(4)) = 5& n_(AI) = 13.33` `:. m_(Mn_(3)O_(4)) = 5xx229 = 1145g & m_(AI) = 13.33xx27 = 360 g` |
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| 9906. |
Determine which of the following reactions at constant pressure represent surrounding that do work on the system environment : (P) `4NH_(3)(g) + 7O_(2)(g) to 4 NO_(2)+ 6H_(2)O(g)` (Q) `CO.O(g)+ 2H_(2)(g) to CH_(3)OH(l)` (R) `C("s,graphite")+H_(2)O(g) to CO(g)+H_(2)(g)` (S) `H_(2)O(s) to H_(2)O(l)`A. III,IVB. II and IIIC. II,IVD. I and II,IV |
| Answer» Correct Answer - D | |
| 9907. |
What is the energy (kJ/mol) associated with the de-excitation of an electron from n=6 to n=2 in He+ ion? a) 1.36×106 b) 1.36×103 c) 1.16×103 d) 1.78×103 |
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Answer» Answer: c) 1.16 x103 n = 6 to n= 2 E = \(13.6\times Z_1^2[\frac{1}{4}-\frac{1}{36}]\) \(=13.6\times 4\times[\frac{9-1}{36}]\) \(=13.6\times4\times\frac{8}{36}\) = 12.08 ev x 96kj/mol =1.16 x 103 |
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| 9908. |
8. \( 5.5 g \) of sodium hydroxide is dissolved in \( 175 mL \) of water. Using a coffee-cup calorimeter, the temperature change of the water is measured to be \( +2.10^{\circ} C \). The specific heat capacity of water is \( 4.184 J / g ^{\circ} C \). What is the thermochemical equation for this process? (A) \( NaOH (s) \rightarrow NaOH ( aq )+1.54 kJ \) (B) \( NaOH ( s )+1.54 kJ \rightarrow NaOH ( aq ) \) (C) \( NaOH (s) \rightarrow NaOH ( aq )+11.2 kJ \) (D) \( NaOH ( s )+11.2 kJ \rightarrow NaOH ( aq ) \) |
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Answer» We have given----- Mass of NaOH = 5.5 g Volume of water = 175 ml Temperature change of water = +2.10°C specific Heat capacity of water = 4.184 J/g°C \(\because\) Temperature of water increases, it means, dissolution of NaOH in water is a exothormic process. We know that, density of water = 1 g/ml at STP \(\therefore\) Mass of water = 175 ml x 1g/mL = 175 g Heat absorbed by water Q = m x s x Δt where, m = mass of water S = specific Heat of water = 4.18 J/g°C Δt = change in temperature \(\therefore\) Q = 175 g x 4.18 4J/g°C x 2.10°C = 1.537 KJ = 1.54 KJ \(\therefore\) The correct Thermochemical equation will be---- NaOH(s) → NaOH(aq) + 1.54 KJ Hence, Option (A) is right answer. |
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| 9909. |
Write the three whole numbers occurring just before 10001.Which is the smallest whole number?How many whole numbers are there between 32 and 53? Write the successor of:(a) 2440701 (b) 100199 (c) 1099999 (d) 23456705. Write the predecessor of:(a) 94 (b) 10000 (c) 208090 (d) 76543216. In each of the following pairs of numbers, state which whole number is on the left of the other number on the number line. Also write them with the appropriate sign (>, <) between them.(a) 530, 503 (b) 370, 307 (c) 98765, 56789 (d) 9830415, 10023001 |
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Answer» (1) 10,000, 9,999, 9,998 (2) 0 (3) No of whole numbers between 32 and 53 = 53 - 32 - 1 = 20 (4) (a) 2440702 (b) 1,00,200 (c) 11,00,000 (d) 2345671 (5) (a) 93 (b) 9999 (c) 208089 (d) 7654320 (6) (a) 530 > 503 503 appears on the left side of 530 on the number line. (b) 370 > 307 307 appears on the left side of 370 on the number line. (c) 98765 > 56789 56789 appears on the left side of 98765 on the number line. (d) 10023001 > 9830415 10023001 appears on the left side of 9830415 on the number line. |
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| 9910. |
Which gas in the Atmosphere is essential for respiration? |
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Answer» Oxygen gas present in the atmosphere is essential for respiration. |
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| 9911. |
Write any 2 characterstics of ideal gas. |
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Answer» The two characteristics of ideal gas are:
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| 9912. |
I suggest that we all watch the movie ‘TIGER’. It has been suggested that we watch the movie 'TIGER' together. The two given statements can be differentiated by drawing students’ attention to the1. Use of ‘by’ in the passive form2. The arrangement of words3. Change in the verb forms4. The roles of the subject and object in both sentences |
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Answer» Correct Answer - Option 4 : The roles of the subject and object in both sentences Subjects and objects have the opposite functions in a sentence.
Thus, it is concluded that The two given statements can be differentiated by drawing students’ attention to the roles of the subject and object in both sentences. |
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| 9913. |
Antibodies are: carbohydrates,Lipids,Proteins,Enzymes |
| Answer» Correct answer is protiens ..... | |
| 9914. |
The purpose of 'rapid reading' is1. Extended reading2. Seeking information3. For interest4. For specific detail |
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Answer» Correct Answer - Option 3 : For interest Reading is a process whereby a reader brings meaning to and gets meaning from print. This implies that readers bring their experiences as well as their emotions into play in order to derive meaning from text.
Purpose of rapid reading:-
Thus, from the above-mentioned points, it is clear that the purpose of 'rapid reading' is for interest. Skimming and scanning are methods of rapid reading.
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| 9915. |
Speaker 1 : Can I borrow your pencil, please ?Speaker 2 : Why not ?During this exchange, while assessing students' speaking - listening skills, mark/s would be deducted for1. the first speaker, as the question is framed incorrectly2. the second speaker, as the response is framed incorrectly3. both, since it is a meaningless exchange4. neither, as the context justifies this exchange |
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Answer» Correct Answer - Option 1 : the first speaker, as the question is framed incorrectly CCE (Continuous and Comprehensive Evaluation) the flagship project of CBSE has clearly outlined the significance of speaking and listening skills as part of co-scholastic areas of achievement by every learner and also stresses the clear integration of assessment of speaking and listening skills as a part of the curriculum transaction. During this exchange, while assessing students' speaking - listening skills, mark/s would be deducted for the first speaker, as the question is framed incorrectly.
Thus, it is concluded that Speaker 1: Can I borrow your pencil, please? Speaker 2: Why not? During this exchange, while assessing students' speaking-listening skills, mark/s would be deducted for the first speaker, as the question is framed incorrectly. |
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| 9916. |
Human chorionic gonadotropin hormone is produced by a) Placenta b) embryo |
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Answer» a) Placenta The placenta is a cushion like tissue which supports the embryo and facilitates the supply of oxygen and nutrients to the embryo and also the removal of carbon dioxide and excretory waste materials produced by the embryo. It also acts as an endocrine tissue and produces several hormones like human chorionic gonadotropin, human placental lactogen, estrogens, progesterone, and relaxin etc. |
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| 9917. |
Write the name of the source organism of Cocaine. |
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Answer» Leaves and young shoots of coca plant. |
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| 9918. |
Speaker 1 : Where are you from ?Speaker 2 : Kashmir.During the assessment of students' speaking- listening skills, mark/s would be deducted during this exchange for1. the first speaker2. the second speaker3. both4. neither |
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Answer» Correct Answer - Option 2 : the second speaker CCE (Continuous and Comprehensive Evaluation), the flagship project of CBSE has clearly outlined the significance of speaking and listening skills as part of co-scholastic areas of achievement by every learner and also stresses the clear integration of assessment of speaking and listening skills as a part of the curriculum transaction. During this exchange, while assessing students' speaking - listening skills, mark/s would be deducted for Speaker II as:
Thus, it is concluded that during the assessment of students' speaking-listening skills, mark/s would be deducted during this exchange for the second speaker. |
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| 9919. |
What is cryopreservation? |
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Answer» The word cryo comes from the Greek word "kayos" meaning "frost". It means preservation in a "frozen state". It is the process of cooling and storing cells, tissues, or organs at very low temperatures to maintain their viability. Cryopreservation is a technique in which low temperature is used to preserve the living cells and tissue. In this technique, tissues can be preserved for a very long time. The science that deals with cryopreservation is known as “cryobiology”. |
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| 9920. |
Read the following examples of dangling modifiers used in sentences by some students. Indicate how you will assess them. [Max. 1 mark]Student 1: Having arrived late for practice, a written excuse was needed.Student 2: Without knowing his name, it was difficult to introduce him.Student 3: The experiment was a failure not having studied the lab manual carefully.1.Student 1: -1-Student 2: -1-Student 3: -0-2.Student 1: -1-Student 2: -0-Student 3: -0-3.Student 1: -0-Student 2: -1-Student 3: -0-4.Student 1: -0-Student 2: -1-Student 3: -1- |
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Answer» Correct Answer - Option 1 : Student 1: -1- Student 2: -1- Student 3: -0- A modifier describes, clarifies, or gives more detail about a concept.
Hence, student 1 and student 2 provide correct examples of dangling modifiers used in these sentences. Thus, the score for both of them is 1 and for student 3 is 0. |
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| 9921. |
Write short notes on cryopreservation. |
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Answer» Cryopreservation – Cryopreservation is in vitro conservation technique useful for preserving vegetatively propagated crops eg, potato, seeds of plants and preserving sperms, eggs, cells and embryonic tissues of animals at –196°C temperature. |
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| 9922. |
Why are cancer patients given biological modifiers like interferons? |
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Answer» Interferons activate immune system and helps in destroying the tumor. |
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| 9923. |
What is radiation pollution? What are the effects of it? |
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Answer» When in atmosphere harmful changes happen due to different types of radiations and radioactive materials then it is called radiation pollution. It is the physical pollution of air, water and soil with radioactive materials. It is natural as well as man made. The effect of radioactive pollutants depend on (i) strength of radiation, (ii) rate of diffusion and deposition of the pollutants, (iii) the length of time for which the tissue is exposed to radiation, and (iv) half life of pollutants. Environmental factors also influence their effects. Effect of radiation pollution:– (1) Due to radiation pollution, body becomes weak and life becomes short. (2) Radiation pollution is harmful for DNA, RNA, Protein, Spleen, etc. (3) Radioactive radiations cause sterility, defect vision, tumour of lungs, loss of tissues, etc. (4) Long time exposure in ultraviolet radiations causes skin related diseases. (5) For long time or time-to-time radiation of radioactive materials may cause blood cancer or leukaemia. (6) Cells vary in their sensitivity to injury by radiation. (7) Chances of depletion of ozone layer in stretosphere by nuclear explosions. |
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| 9924. |
Mention any two methods used for the detection of cancer. |
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Answer» Biopsy, CT Scan and MRI. |
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| 9925. |
What is deforestation ? Write its causes and effects. |
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Answer» Deforestation is the conversion of forest areas to non-forest ones. It is a serious threat to the quality of life, national economy and future of environment. According to an estimate, almost 40 percent forests have been lost in the tropics, compared to only one percent in the temperate region. The present-scenario of deforestation is particularly grim in India. The main cause of decrease in forest cover in India is deforestation due to expansion of agriculture, urbanization, industrialization, excessive commercial use of timber, fuel, wood etc. The causes of deforestation are population explosion, fires, pests, grazing and gnawing mammals, weather, jhum cultivation, etc. Effects of deforestation are as follows– (1) Soil erosion has increased; (2) Flood and droughts have become more frequent; (3) Pattern of rainfall is changing; (4) Landslides and avalanches are on the increase; (5) Climate has become warmer; (6) Forest dwelling species are becoming extinct; (7) Consumption of CO2 and production of O2 are getting adversely affected. |
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| 9926. |
What are the major features of embryonic development during various months of pregnancy. |
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Answer» The human pregnancy lasts 9 months. After one month of pregnancy, the embryo’s heart is formed. By the end of the second month of pregnancy, the foetus develops limbs and digits. By the end of 12 weeks (first trimester), most of the major organ system are formed. The limbs and the external genital organs are well developed. The first movement of the foetus and appearance of hair on the head are usually observed during the fifth month. By the end of 24 weeks (second trimester) the body is covered with fine hair, eye lids separate and eyelashes are formed. By the end of 9 months of pregnancy, the foetus is fully developed and is ready for delivery. |
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| 9927. |
Mention the various test methods of cancer? |
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Answer» The fatal disease like cancer must be identified in its early stage so that it can be easily diagnosed properly and well in time. Following test methods are employed for the identification of cancer– (a) Through biopsy of cancerous tissue. (b) Blood and bone marrow test for growth of cancerous cells. (c) Cancer of internal organ identified by radiography, CT-computed Tomography and MRI (Magnetic Resonance Imaging). (d) Use of antibody angainst specific cancer antigens. (e) By identification of oncogens through bio-molecular technique. |
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| 9928. |
B-lymphocytes are produced in(A) Bone marrow(B) Thymus(C) Blood(D) Lymph |
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Answer» Answer (A) Bone marrow |
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| 9929. |
Pisciculture is related culture of(A) Aquatic plants(B) Aquatic animals(C) Silk worm(D) Lack worm |
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Answer» Answer (B) Aquatic animals |
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| 9930. |
What is the role of animal husbandry in human welfare ? Explain it. |
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Answer» Animal husbandary is related to animal stocks such as Buffalo, Cow, Pig, Horse, Camel, Goat etc and their reproduction and care which is necessary for production of food for human. The increasing global population, increase in food production is a essential demand. This animal husbandry provide milk, meat and woolen for clothing for humanity. Animal husbandry, animal reproduction and growth of animal stocks is a system in agriculture. To fulfil the increasing demand of food for humanity, animals and animal products are essential. Therefore animal husbandry is important for human welfare. Utilizing various scientific principles, care of domestic animals & their reproductive processes in context of human welfare are reformed. |
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| 9931. |
Pisciculture is related culture of- (A) Aquatic plants (B) Aquatic animals (C) Silk worm (D) Lac worm |
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Answer» (B) Aquatic animals |
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| 9932. |
What is the role of animal husbandry in human welfare? Explain with examples. |
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Answer» Animal husbandry is the agricultural practice of breeding and raising livestock. As such it is vital skill for farmers and is as much science as it is art. It deals with the care and breeding of livestock like buffaloes, cows, pigs, horses, cattle, ship camels goat etc that are useful to humans. It also includes farming and fisheries. Since time, animals like bees, silkworm, prawns, crabs, fishes, birds, pigs, cattle, sheep and camels have been used by human for products like milk, eggs, meat, wool, silk, honey, etc. Breeding of animals is also an important aspects of animals husbandry which aims at increasing the yield of animals and improving the desirable qualities of the produce. |
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| 9933. |
Pyrimidines present in DNA are(a) Thymine and Cytosine(b) Adenine and Guanine(c) Cytosine and Uracil(d) Thymine and Uracil |
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Answer» Answer (a) Thymine and Cytosine |
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| 9934. |
The phenotypic ratio for F2 generation in incomplete dominance is(A) 3 : 1(B) 2 : 2(C) 1 : 2 : 1(D) None of these |
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Answer» Answer (C) 1 : 2 : 1 |
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| 9935. |
The phenotypic ratio for F2 generation in Incomplete dominance is- (A) 3:1 (B) 2:2 (C) 1:2:1 (D) None of these |
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Answer» The phenotypic ratio for F2 generation in Incomplete dominance is 1:2:1 |
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| 9936. |
What are the types of biofertilizers? How does the soil benefit from them? |
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Answer» Biofertilizers are micro-organisms which bring about nutrient enrichment of soil by enhancing the availability of nutrients to crops. The micro-organisms which act as Bio-feretilizers are bacteria, cyano bacteria and mycorrhizal fungi. bacteria and cyanobacteria have the property of Nitrogen fixation while mycorrhizal fungi withdraw minerals from organic matter for the plant with which they are associated. Rhizobium fix atmospheric nitrogen into organic forms through nodules on the roots of leguminous plants, which is used by plant as nutrient. Fungi are also known to form symbiotic associations with plants (i.e. mycorrhiza) Cyanobacteria are auto trophic microbes widely distributed in aquatic and terresterial environments, many of which can fix atmospheric nitrogen, e.g., Anabana, Nostoc etc. Biofertilizers are Biological in nature and so are biodegradable. They do not spoil the quality of the soil. It supplies organic matter and additional nitrogen like Rhizobiom, Azotobactor etc. |
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| 9937. |
Water holding capacity is one of the qualities of(A) Soil(B) Plants(C) Water(D) Animals |
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Answer» Answer (A) Soil |
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| 9938. |
Number of deaths during a limited time period and place of a particular population is known as (A) Natality (B) Mortality (C) Migratory (D) Integrity |
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Answer» (B) Mortality |
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| 9939. |
What do you understand by the following?(a) Micro mutation(b) Macro mutation(c) Chromosomal mutation |
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Answer» (a) Micro-mutation: It is also called point mutation or single base mutation is a type of mutation that causes the replacement of a single base nucleotide with another nucleotide of genetic material, DNA or RNA. (b) Macro-mutation: A mutation that has profound effect on the resulting organism, as a change in a regulatory gene that controls the expression of many structural genes. (c) Cromosomal mutation: Any event that changes genetic structure any alternation in the inherited nucletic acid sequences of the genotype of an organism. |
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| 9940. |
Find the zeros of the quadratic equation 3x2 + 2√2 x - 2 = 0. |
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Answer» 3x2 + 2√2 x - 2 = 0 ⇒ 3x2 + 3√2 x - √2x - 2 = 0 ⇒ 3x(x + √2) - √2(x + √2) = 0 ⇒ (3x - √2) (x + √2) = 0 ⇒ x + √2 = 0 or 3x - √2 = 0 ⇒ x = -√2 or x = √2/3. Hence, -√2 and √2/3 are zeros of the quadratic equation 3x2 + 2√2 x - 2 = 0 |
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| 9941. |
Describe the beek-keeping in brief. |
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Answer» Apiculture or Bee-keeping is the rearing of honey bees for the production of honey. It has been an age-old cottage industry. Honey is a food of high nutritive value and also finds use in the indigenous systems of medicine. Honeybee also produces beewax, which finds many uses in industry, such as in the Preparation of cosmetics and polishes of various kinds. The increases demand of honey has led to large scale bee-keeping practices. It has become an established income generating industry, whether practiced on a small or on a large scale. Bee-keeping can be practiced in any area where there are sufficient bee postures of some wild shrubs, fruits orchards and cultivated crops. Apis indica is the most common species which is domesticated easily. The following points are important for successful bee-keeping: (a) Knowledge of the nature and habits of bees (b) Selection of suitable location for keeping the beehives (c) Catching and hiving of swarms (group of bees) (d) Management of beehives during different seasons and (e) Handling and collection of honey & beewax |
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| 9942. |
Explain properties of genetic code in brief |
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Answer» Properties of genetic code- (i) It is triplet: The three nucleotides of mRNA which code for one amino acid represent codon. Complementary matching triplet of tRNA from the anticodon. The codon which intiates protein synthesis is called as initation codon. (ii) The code is degenerate: For a particular amino acid more than one codon can be used. One amino acid often has more than one code triplet. (iii) The genetic code is universal: Given codon in DNA and mRNA specifies same amino acid in all organisms like prokaryotes virus. (iv) The code is non-overlapping: It meals that same letter cannot be used for two different codons. Each nitrogenous base is present in one codon only. (v) Co-linearity: The genetic code represents the sequence of mRNA codons and the corresponding amino acid residues of a polypeptide chain are arranged in the same linear sequence. |
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| 9943. |
What is Geological time scale? It is classified into eras. Name the eras. |
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Answer» Geological time scale: GTS is chronological measurement that relates stratigraphy to time, and is used by geologists, paleontologists, and other earth scientist to describe the timing and relationships between events that have occurred throughout earth's history. The name of eras are following: (i) Cenozoic (ii) Mesozoic (iii) Paleozoic (iv) Neo-proterozoic (v) Meso-proterozoic (vi) Paleoproterozoic |
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| 9944. |
A chemist opened a cupboard and found four bottles containing water solutions, each of which had lost its label.Bottles 1,2,3 contanied colourless solution, while bottle 4 contained a blue solution.The labels from the bottles were lying scattered on the floor of the cupboard.They were: copper (II) sulphate, Hydrochloric acid lead nitrate , Sodium carbonate By mixing samples of the contents of the bottles, in pairs , the chemist made the following observations : Bottle 1 +Bottle 2 `to` White precipitate is formed. Bottle 1 +Bottle 3 `to` White precipitate is formed. Bottle 1 +Bottle 4 `to` White precipitate is formed. Bottle 2 +Bottle 3 `to` Colourless and odourless gas is evolved. Bottle 2 +Bottle 4 `to` No visible reaction is observed. Bottle 3 +Bottle 4 `to` Blue precipitate is formed. With the help of the above observations answer the following questions. Which one of the following bottles develops deep blue with aqueous ammonia ?A. Bottle 1B. Bottle 2C. Bottle 3D. Bottle 4 |
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Answer» Correct Answer - D Bottle 4 is `CuSO_4` and that give deep blue colouration with excess of ammonia solution. `Cu^(2+)(aq)+4NH_3(aq)to[Cu(NH_3)_4]^(2+)` (intensive deep blue colour)(aq) |
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| 9945. |
A chemist opened a cupboard and found four bottles containing water solutions, each of which had lost its label.Bottles 1,2,3 contanied colourless solution, while bottle 4 contained a blue solution.The labels from the bottles were lying scattered on the floor of the cupboard.They were: copper (II) sulphate, Hydrochloric acid lead nitrate , Sodium carbonate By mixing samples of the contents of the bottles, in pairs , the chemist made the following observations : Bottle 1 +Bottle 2 `to` White precipitate is formed. Bottle 1 +Bottle 3 `to` White precipitate is formed. Bottle 1 +Bottle 4 `to` White precipitate is formed. Bottle 2 +Bottle 3 `to` Colourless and odourless gas is evolved. Bottle 2 +Bottle 4 `to` No visible reaction is observed. Bottle 3 +Bottle 4 `to` Blue precipitate is formed. With the help of the above observations answer the following questions. Bottle 3 contains :A. Copper (II) sulphateB. Hydrochloric acidC. Lead nitrateD. Sodium carbonate |
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Answer» Correct Answer - D As bottle 2+ bottle 3 gives colourless and odourless gas, it may be carbon dioxide. Generally carbonates are decomposed by acids giving `CO_2` gas.It suggests that bottle 2 and 3 contains sodium carbonate and HCl. Bottle 3+4 gives blue precipitate which confirms the `Cu^(2+)` in either of bottles, `CuSO_4 , CuCl_2 and Cu(NO_3)_2` are soluble and `CuCO_3` is insoluble in water as evident from the reaction. `Cu^(2+)+CO_3^(2-)toCuCO_3 darr` (blue).Thus blue precipitate must be of copper carbonate. Hence, bottle 4 is `CuSO_4` , 3 is `Na_2CO_3`, 2 is HCl (from above ) and 1 is `Pb(NO_3)_2` as it gives white precipitate of `PbCl_2` with bottle (2). |
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| 9946. |
A chemist opened a cupboard and found four bottles containing water solutions, each of which had lost its label.Bottles 1,2,3 contanied colourless solution, while bottle 4 contained a blue solution.The labels from the bottles were lying scattered on the floor of the cupboard.They were: copper (II) sulphate, Hydrochloric acid lead nitrate , Sodium carbonate By mixing samples of the contents of the bottles, in pairs , the chemist made the following observations : Bottle 1 +Bottle 2 `to` White precipitate is formed. Bottle 1 +Bottle 3 `to` White precipitate is formed. Bottle 1 +Bottle 4 `to` White precipitate is formed. Bottle 2 +Bottle 3 `to` Colourless and odourless gas is evolved. Bottle 2 +Bottle 4 `to` No visible reaction is observed. Bottle 3 +Bottle 4 `to` Blue precipitate is formed. With the help of the above observations answer the following questions. Which of the following bottles will give white precipitate with bottle 1?A. Bottle 2B. Bottle 3C. Bottle 4D. All of these |
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Answer» Correct Answer - D `Pb^(2+)+CO_3^(2-) to PbCO_3 darr` (white) `Pb^(2+)+2Cl^(-)toPbCl_2darr`(white) `Pb^(2+)+SO_4^(2-)toPbSO_4 darr`(white) |
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| 9947. |
Column(I) contains some reagents which when taken in excess produce precipitate with radical given in column (II).Accordingly match the column (I) with column (II). `{:(underset(("Reagent"))(Column-I),underset(("Radical"))(Column-II)),((A)KCN(aq),(p)Pb^(2+)),((B)NaOH(aq),(q)Ag^(+)),((C )Kl(aq),(r)Hg_2^(2+)),((D)K_2CrO_4(aq),(s)Cu^(2+)):}` |
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Answer» Correct Answer - A`to`p,r ; B`to`q,r,s ; C`to`p,q,r,s ; D`to`p,q,r (A)`Pb (CN)_2darr` white , not soluble in excess to reagent. `AgCNdarr` white soluble in excess of reagent `Hg+Hg(CN)_2darr` black, not soluble in excess reagent, `Cu(CN)_2darr` (yellow) `overset("Excess")toK_3[Cu(CN)_4]` (soluble complex) (B)`Pb(OH)_2darr` white `overset("Excess")(Na_2)[Pb(OH)_4]`(soluble complex ) `Ag_2Odarr` brown, `Hg_2Odarr` black, `Cu(OH)_2darr` blue (C )`Pbl_2darr`yellow `overset("Excess")to [Pbl_4]^(2-)` soluble complex only with concentrated solution of KI(4M). `AgIdarr`yellow `overset("excess")to` No reaction `Hg_2l_2darr"Green"overset("Excess")to[Hgl_4]^(-)+Hgdarr`black `ubrace(Cu l darrwhite+I_3^(-))to`white ppt in brown coloured solution (D)`PbCrO_4darr`yellow `Ag_2CrO_4darr`(brick red/brownish red) `Hg_2CrO_4darr` red (with hot soluton of `K_2CrO_4`) In cold, brown precipitate is obtained |
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| 9948. |
`{:("Column I","Column II"),((A)"Yellow ppt of "PbCrO_4,(p)"Blue or green colour to flame"),((B)"Sodium nitroprusside",(q)"Brown ring test"),(( C)"Nitrate ion",(r)"Chromyl chloride test"),((D)Cu"salt and "BO_3^(-3) "ion",(s)"Voilet colour with"Na_2S):}` |
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Answer» Correct Answer - A`to`r ; B`to`s ; C`to`q ; D`to`p (A)`to` chromyl chloride test (B)`to` violet colour with `Na_2S` (C )`to` brown ring test (D)`to` blue or green colour to flame |
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| 9949. |
Match the precipitate of the compounds listed in (I) with the solvent(s) listed in column(II). `{:(Column-I,Column-II),((A)Zn(OH)_2"precipitate dissolves in",(p)"Potassium cyanide"),((B)Cr(OH)_3"precipitate dissolves in",(q)"Ammonia"),((C )AgCl"precipitate dissolves in",(r)"Sodium hydroxide"),((D)CuS "precipitate dissolves in",(s)"Sodium peroxide"),(,(t)50% HNO_3):}` |
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Answer» Correct Answer - A`to`q,r,t ; B`to`r,s,t ; C`to`p,q ; D`to`p,s,t (A)`Zn(OH)_2darr+4NH_3(aq)to[Zn(NH_3)_4](OH)_2` (colourless soluble complex) `Zn(OH)_2darr+2NaOH(aq)toNa_2[Zn(OH)_4]` (colourless soluble complex) `Zn(OH)_2 darr + 2H^(+)(aq)toZn^(2+)(aq)+2H_2O(l)` (B)It is slightly soluble in red `Cr(OH)_3darr+6NH_3(aq)to[Cr(NH_3)_6]^(3+)`(pink or violet soluble complex ) +`3OH^-`(aq) `Cr(OH)_3darr+OH^(-)(aq)to[Cr(OH)_4]^(-)`(green soluble complex) `2Cr(OH)_3darr+3Na_2O_2(s)to2Na_2CrO_4`(yellow solution) + 2NaOH (aq) +`2H_2O`(l) `Cr(OH)_3darr+3H^(+)(aq)toCr^(3+)(aq)+3H_2O(l)` (C )`AgCldarr+2NH_3(aq)to[Ag(NH_3)_]Cl`(colourless soluble complex) `AgCldarr+2CN^(-)(aq)to[Ag(CN)_2]^(-)`(colourless soluble complex )+`Cl^-` (aq) Does not dissolve in NaOH, `Na_2O_2` and 50% `HNNO_3` (D)`2CuSdarr+8CN^(-)(aq)to2[Cu(CN)_4]^(3-)` (colourless soluble complex )+`S_2^(2-)` `CuSdarr+Na_2O_2(s)overset(H_2O)toCuSO_4(aq)+NaOH(aq)` CuS `darr`+ `H_2O `(l)`toCuSO_4(aq)` `3CuSdarr+8HNO_3(aq)to3Cu^(2+)(aq)+6NO_3^(-)(aq)+3Sdarr+2NOuarr+4H_2O(l)` |
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| 9950. |
Match the reactions listed in column (I) with the colour of the precipitate(s) listed in column (II). `{:("Column I","Column II"),((A)Cu^(2+)(aq)overset("allow to stand for sometime")to,(p)"Brown"),((B)"Hot" Bi^(3+)(aq)+C_6H_3(OH_3)to,"(q)Brownish-red"),(( C)Ag^+(aq)+AsO_4^(3-)(aq.)to,"(s)Yellow"),((D)Mn^(2+)(aq.)+2OH^(-)(aq.)overset("air")to,"(s)White"),(,"(t)Green"):}` |
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Answer» Correct Answer - A-s ; B-r ; C-q ;D-p (A)`Cu^(2+)+2SCN^(-)toCu(SCN)_2darr`(black) `2Cu(SCN)_2darrto2CuSCNdarr("white")+(SCN)_2uarr` (B)`"Hot"Bi^(3+)(aq)+C_6H_3(OH)_3overset(H^+)toBi(C_6H_3O_3)darr("yellow")+3H^(+)` (C )`2Ag^(+)(aq)+AsO_4^(3-)(aq)toAg_3AsO_4darr`(brownish-red) (D)`Mn^(2+)(aq.)+2OH^(-)(aq)toMn(OH)_2darr`(white) `Mn(OH)_2darr+O_2to2MnO(OH)_2darr`(brown) |
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