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A chemist opened a cupboard and found four bottles containing water solutions, each of which had lost its label.Bottles 1,2,3 contanied colourless solution, while bottle 4 contained a blue solution.The labels from the bottles were lying scattered on the floor of the cupboard.They were: copper (II) sulphate, Hydrochloric acid lead nitrate , Sodium carbonate By mixing samples of the contents of the bottles, in pairs , the chemist made the following observations : Bottle 1 +Bottle 2 `to` White precipitate is formed. Bottle 1 +Bottle 3 `to` White precipitate is formed. Bottle 1 +Bottle 4 `to` White precipitate is formed. Bottle 2 +Bottle 3 `to` Colourless and odourless gas is evolved. Bottle 2 +Bottle 4 `to` No visible reaction is observed. Bottle 3 +Bottle 4 `to` Blue precipitate is formed. With the help of the above observations answer the following questions. Which one of the following bottles develops deep blue with aqueous ammonia ?A. Bottle 1B. Bottle 2C. Bottle 3D. Bottle 4

Answer» Correct Answer - D
Bottle 4 is `CuSO_4` and that give deep blue colouration with excess of ammonia solution.
`Cu^(2+)(aq)+4NH_3(aq)to[Cu(NH_3)_4]^(2+)` (intensive deep blue colour)(aq)


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