1.

What is the energy (kJ/mol) associated with the de-excitation of an electron from n=6 to n=2 in He+ ion? a) 1.36×106 b) 1.36×103 c) 1.16×103 d) 1.78×103

Answer»

Answer: c) 1.16 x10 

n = 6 to n= 2

E = \(13.6\times Z_1^2[\frac{1}{4}-\frac{1}{36}]\)

\(=13.6\times 4\times[\frac{9-1}{36}]\)

\(=13.6\times4\times\frac{8}{36}\)

= 12.08 ev x 96kj/mol

=1.16 x 103



Discussion

No Comment Found

Related InterviewSolutions