Saved Bookmarks
| 1. |
An organic compound has `% C = 68.85, % H = 4.92 and % O = 26.23` (by mass). Number of carbon atoms present in the Empirical Formula of it is ………….A. `5`B. `6`C. `7`D. `2` |
|
Answer» Correct Answer - C An organic compound has `% C` ……….. `C_((68.85)/(12)) H_((4.92)/(1)) O_((26.23)/(16)) or C_(3.5) H_(3)O` `implies EF is C_(7)H_(6)O_(2)` |
|