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Correct option is: C. 2

Correct option is: D. (400 - 100π) sq. m

Correct option is: D. \(\frac{5}{12}\)

Van – Arkel method

The answer is XeF₆.

Correct option: (1)

Explanation:

[M(AA) a₂b₂] shows optical activity in cis-arrangement.

The correct option (1) Rb   

Explanation:

Rb(s) + O₂(g) → RbO₂(s)

2RbO₂(s) + 2H₂O(l) → 2RbOH + H₂O₂ + O₂. 

On combustion in excess of air, lithium forms mainly the oxide, Li₂O, Sodium form the peroxide Na₂O₂ whilst K, Rb, Cs form the superoxides MO₂.

For an ellipse or hyperbola distance between foci = 2ae = √(19²+5²) = √(386)  

 For an ellipse, sum of focal radii = 2a. For a hyperbola difference of focal radii = 2a   

Focal radii are √(24²+7²) = 25 and √(5²+12²) = 13   

∴ for ellipse 2a = 25+13 = 38 and so e = 2ae /2a = √(386) / 38   

And for a hyperbola 2a = 25−13 = 12 and so e = 2ae / 2a = √(386) / 12

Electric potential energy, is a potential energy (measured in Joules) that results from conservative coulomb forces and is associated with the configuration of a particular set of point charges within defined system.

The most common procedure for the enumeration of bacteria is the viable plate count. In this method, serial dilutions of a sample containing viable microorganisms are plated onto a suitable growth medium.

1. Air pollution can be controlled by the following ways. 

• Exhaust to oxidize CO to CO₂ . 

• CO₂ level can be maintained by planting trees. 

• Hydrogen gas is looked upon as pollution less future fuel. 

• The large amount of nitrogen oxides emitted from power plant can be removed by scrubbing it with H2SO₄ . 

2. It occurs due to 

• Indiscriminate use of fertilizers, pesticides etc. 

• Dumping of waste materials. 

• Deforestation

Photosynthesis is the process used by plants, algae and certain bacteria to harness energy from sunlight and turn it into chemical energy.

Oxides of Sulphur and Nitrogen, mist of HCI and Phosphoric acid, etc. present in polluted air dissolve in rain water making it more acidic. This is known as acidic rain. SO₂ and NO₂ present in polluted air are the major contributors of acid rain.

2SO₂ (g) + O₂(g) +2H₂O(l) → 2H₂SO₄ (aq) 

4NO₂ (g) + O₂(g) + 2H₂O(l) → 2HNO₃(aq)

Heavy Flood in Kerala (By XYZ) 

An unprecedented flood ravaged three villages of Alappuzha district in Kerala in the month of august. At least seven people lost their lives and many more were reported missing. Heavy rainfall was the cause of this great natural calamity. All the mud houses had collapsed and at least 3000 people became homeless. Besides, huge quantity of crops had been destroyed as the agricultural fields were under deep water and the cattle were washed away. A large area of the state became inaccessible. Tele communication system was also damaged. The government took various steps of relief work. Packets of dry food and bottles of pure drinking water were sent to the affected areas or thrown from helicopter. Various voluntary organisations and medical teams were busy in relief work. 

1. Gases such as CO and SO₂ 

2. Compounds of metals like lead, mercury, zinc. 

3. Radioactive substance

1.(i) When the pH of the rain water drops below 5.6, it is called acid rain.

(ii) Oxides of nitrogen and sulphur mist of hydrochloric acid and phosphoric acid etc.

2. Such as carbon dioxide, methane, ozone, chlorofluorocarbon compounds (CFC).

Van Mahotsav - 2019 

Ajmer, March 07, 2019 

The ‘Van Mahotsav’ was celebrated in Royal Rajasthan Public School, Ajmer with a lot of enthusiasm on March 06, 2019. In an age where the jungles are more asphalt than natural, the staff and students came together to plant saplings all along the roads of the campus after breakfast. The sky was completely overcast and there was a light drizzle. One could not have asked for a better weather to plant trees in the rainy season. 

The event started shortly after ten o’clock in the morning where the boys of the Junior School with their staff members came out to plant saplings with the gardeners. This was followed with the boys of the Senior School with their house staff. The boys displayed great enthusiasm in wanting to learn how saplings are planted and were constantly asking intelligent questions to the gardeners about the plants. It was heartening to see the senior functionaries of the school along with the staff, the students and the gardeners work hand-in-hand together as a team. There was frolic and laughter and cheerful faces as everyone was hard at work. The trees planted today will serve as a beautiful memory left behind by the students. For when they come back, they will have indeed a story to tell of how the little sapling they planted grew with them just as they have. 

(a) 2C₂H₆ (g) +7O₂ → 4CO₂ (g) + 6H₂ O(v) 

(b) 2C₂H₆ (g)+5O₂ → 4CO(g) + 6H₂O(v)

NO Super sonic jet planes not contribute to zone depletion by introduction of the gas straight to the stratosphere

Methenoglobinemia

The difference between the amounts of dissolved oxygen in a sample of water saturated with oxygen and that after incubation for a period of 5 days is known as BOD

Focus of hyperbola are (8,4) and (0,4).

Hence,

Focus of hyperbola lie on line y = 4,

(Parallel to x-axis)

∴ Centre of the hyperbola is mid-point of both focus = (\(\frac{8+0}{2}\),\(\frac{4+4}{2}\)) 

= (4,4)

∵ Eccentrictiy of hyperbola is e = 2.

We know that,

Focus one at a distance of ae from the centre.

∵ Distance of focus (0,4) and centre (4,4) = ae

⇒ ae = 4

⇒ a = \(\frac{4}{e}\)

= \(\frac{4}{2}\) = 2.

We also know that in hyperbola,

e = \(\sqrt{1+\frac{b^2}{a^2}}\)

⇒ \(1+\frac{b^2}{a^2}\) = e²

⇒ b² = (e² - 1)a²

⇒ b² = (2² - 1) x 2² = (4 - 1) x 4 = 12

⇒ b = \(\sqrt{12}\).

Since,

Centre of the hyperbola is (4,4) & a² = 4,b² = 12 and focus of hyperbola lies on a line parallel to x - axis.

∴ Equation of hyperbola is \(\frac{(x-4)^2}{a^2}\) - \(\frac{(y-4)^2}{b^2}\) = 1

⇒ \(\frac{(x-4)^2}{4}\) - \(\frac{(y-4)^2}{12}\) = 1

It helps living organisms in water. They inhale dissolved oxygen in water.

Answer: c) Tectona grandis

The city will be destroyed due to acid rain caused by industrial pollution. The Govt, order was to protect the environment (or the city).

Given,

y₁ = 10 sin (3πt + \(\frac{\pi}{4}\))

y₂ = 5 (3 sin3πt + \(\sqrt 3\) cos3πt)

y₂ = 15 sin3πt + \(5\sqrt 3\) cos3πt

Amplitude of y₁ is A₁ = 10

Amplitude of y₂ is A₂ = \(\sqrt{(15)^2+(5\sqrt3)^2}\)

A₂ = \(\sqrt{225+(8.6)^2}\)

A₂ = \(\sqrt{225+73.96}\)

A₂ = \(\sqrt{298.96}\)

A₂ = 17.29

Then ratio of amplitude is :

\(\frac{A_1}{A_2}\) = \(\frac{10}{17.29}\)

\(\frac{A_1}{A_2}\) = \(\frac{1}{\sqrt 3}\) 

Hence, 

Option (b) is correct.

Dispersion of white light is defined as splitting white light into seven constituent colours when passed through the prism. When white light is passed through a glass prism it splits into its spectrum of colours (in order violet, indigo, blue, green, yellow, orange and red) and this process of white light splitting into its constituent colours is termed as dispersion.

• When white light is made to pass through a prism, a spectrum of seven colours is formed which shows that white light is a mixture of seven different colours.
• Prism only acts as a medium for the separation of the seven colours.
• When light falls on the glass prism, refraction takes place. Since the wavelength of different components of light is different and the frequency is constant, each component gets deviated by a different angle due to the difference in velocity in the glass medium.
• The red colour having the maximum wavelength deviates the least and forms the upper part of the spectrum whereas violet having the least wavelength deviates the most.
• White light dispersion occurs because, as they pass through a prism, different colours of light bend through different angles with respect to the incident ray. The red light bends the least while the violet bends most.

(i) By electric discharge of O₂ during lightning. 

(ii) UV radiations enter to the earth surface and it causes skin diseases.

(d) Longitudinal and shear

(d) None of the above