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Match the colour of precipitate listed in column-I with the reagent(s) listed in column II. `{:(Column-I,Column-II),((A)Bi^(3+)"gives black precipitate with",(p)"Saturated solution of" H_2S "in water"),((B)Cu^(2+)"gives black precipitate with",(q)"Potassium thiocyanate soluion"),((C )Zn^(2+)"gives white precipitate with",(r)"Potassium iodide solution"),((D)Ag^+"gives white precipitate with",(s)"Potassium ferrocyanide solution"),(,(t)"Potassium chloride"):}` |
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Answer» Correct Answer - A`to`p,r ; B`to`p,q ; C`to`p,s ; D`to`q,s,t (A)`2Bi^(3+)+3H_2StoBi_2S_3darr(black)+6H^(+)` `Bi^(3+)to3I^(-)toBiI_3darr` (black) (B)`Cu^(2+)+H_2StoCuSdarr(black)+2H^(+)` `Cu^(2+)+2SCN^(-)toCu(SCN)_2darr`(black) which one standing slowly changes to white `2Cu(SCN)_2to2Cu(SCN)darr(white)+(SCN)_2` `Cu_2I_2` is white precipitate and `Cu_2[Fe(CN)_6]` brown precipitate (C )`Zn^(2+)+H_2StoZnSdarr(white)+2H^+` `2K^(+)+2Fe(CN)_6]^(4-)+3Zn^(2+)toK_2Zn_3[Fe(CN)_6]_2darr`(white) `ZnI_2to`soluble (D)`4Ag^(+)+[Fe(CN)_6]^(4-)toAg_4[Fe(CN)_6]darr`(white) `Ag^(+)+SCN^(-)toAgSCNdarr`(white) `Ag_2Sdarr` black , `AgIdarr` yellow |
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