Saved Bookmarks
| 1. |
If (5, 12) and (24, 7) are the foci of a conic, passing through the origin then the eccentricity of conic is |
|
Answer» For an ellipse or hyperbola distance between foci = 2ae = √(19²+5²) = √(386) For an ellipse, sum of focal radii = 2a. For a hyperbola difference of focal radii = 2a Focal radii are √(24²+7²) = 25 and √(5²+12²) = 13 ∴ for ellipse 2a = 25+13 = 38 and so e = 2ae /2a = √(386) / 38 And for a hyperbola 2a = 25−13 = 12 and so e = 2ae / 2a = √(386) / 12 |
|