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The motion of a particle executing simple harmonic motion is DESCRIBED by the displacement function, X(t)=Acos(ωt+ϕ). ... If INSTEAD of the cosine function we CHOOSE the sine function to describe the SHM:x=Bsin(ωt+α), what are the amplitude and initial PHASE of the particle with the above initial conditions.

I THINK OPTION 4!!!!!!!!!!!!!!!EXPLANATION:option 4

no because RAIN WATER contains DISSOLVE salts which can easily CONDUCT electricity

gular BODY has more than 1 CENTRE of GRAVITY.

because the ATTRACTION of those objects are more towards the EARTH Explanation:Because the attraction of those objects are more towards the earth that's why they we are not ABLE to SEE there attraction power.

.VOLTAGE is the other NAME for POTENTIAL DIFFERENCE

Given : h = 720 CMV = √ ( 2 G h ) V = √ ( 2 × 980 × 720 ) V = 4 litres / secAdditional pressure = 16 kg / cm² = 16000 g / cm²Now : 16000 g / cm² = ( 16000 × 980 ) / ( 980 ) cm of water= > 16000 cm of water .Pressure HEAD = h₁ = 16000 + 720 = 16720 cmNew VELOCITY : v₁ = √ ( 2 g h₁ ) v₁ = √ ( 2 × 980 × 16720 ) V = a v₁ and V₁ = a v₁= > V₁ = V ( v₁ / v ) V₁ = √ ( 16720 / 720 ) V₁ =  √ ( 1672 / 72 ) litres / secV₁ = 19.28 litres / secTherefore ,  rate of escape of water is 19.28 litres / SEC

Given : P₁ = 30 MM of Hg= > 3 cm of Hg = 3 × 13.6 × 980ρ₁ = 13.6 G / ccV₁ = 0.20 m / secWe are asked to find P₂ : From Bernoulli's THEOREM we know : ρ₁ + 1 / 2 ρ V₁² = ρ₂ + 1 / 2 ρ V₂²= > On solving further we get : ρ₂ = 3298 dyne / cm²= > 32984 / ( 13.6 × 980 ) ρ₂ = 2.475 cm of HgTherefore , PRESSURE at a point where velocity 1.2 m / sec is 2.475 cm of Hg

The Maxwell-Boltzmann equation, which forms the basis of the kinetic theory of GASES, defines the DISTRIBUTION of SPEEDS for a gas at a CERTAIN temperature. From this distribution function, the most probable speed, the AVERAGE speed, and the root-mean-square speed can be derived.

a material or device USED to prevent HEAT, ELECTRICITY or sound from escaping from something

If the power of sound from a ROCK band's AMPLIFIER is 85W, how FAR are you STANDING from the speaker if you are damaging ...Image

ntensity Distance mTo FIND:How MUCH POWER does a sound source generate.From the EQUATION of intensity in TERMS of power,    Where power       WTherefore, the power generated by source is W

V=IR. I=v/R 1/e =1/15+1/5 SOLVE it, it will be the ANSWER

alpha *beta*t /(alpha+betaExplanation:we know that the car will be moving with is MAXIMUM speed at the end of the time when it was moving with constant acceleration (say @)..let it accelerate for t1 time ..let it accelerate for t1 time ..so,it will DECELERATE in (t-t1) time...now,v after time t1(v max)[email PROTECTED]=>v [email protected]now,it decelerate for (t-t1) time with CONST. retardation (beta)...=>[email protected] - (beta)*(t-t1)=>t1=beta*t/(alpha +beta)so, maximum velocity=alpha *beta*t /(alpha+beta)

re two external forces on the bob: Gravity and teñsion.The teñsion does no work as DISPLACEMENT is always PERPENDICULAR to stŕing.Total mechànical energy of the system is consèrved Energy = EGravity = mgTēnsion = TTaking potențial energy of the system to be at zēro at loweśt point A, THENAT A, From Newton's second law,TA(tenšion at A) - mgAt highest point C, the string slaćks as tension at C becomes zero.C,Let Vc be velocity at C THENFROM Newtons second law, from iv we get From iiiUsing I,orAT B, orThusThe ratio of KINETIC energy at B and C is━━━━━━━━━━Now checking the options we get

(In PHYSICS).I HOPE IT WILL HELPS YOU.

The VELOCITY of the particle is 70 m/s.Explanation:Given that,Initial velocity u = 10 m/sFinal velocity V = 50 m/sWhen the BODY acceleratedUsing equation of motion....(I)Now,The acceleration is reversedFinal velocity = 0Initial velocity = 50 m/sUsing equation of motion again.....(II)The body starts moving in OPPOSITE direction from that point. after coming to the initial point.The total distance s'' = s+s'Let the velocity of the body is v'Using equation of motion again,Hence, The velocity of the particle is 70 m/s.

les.So BASICALLY when u draw u realise u have the hypotenuse as 20 and an ANGLE of 30 DEGREES. to get the horizontal component u simply TAKE cos30 =x/20so x = 20*cos30 which is 17.3 miles.hope this helps

body is projected VERTICALLY UPWARDS...it's velocity decreases since it's motion is opposite to direction of gravity.The equations of motion are the equation for the DISTANCE covered in nth second is ━━━━━━━━━━━━━━━━Maximum height ish=TIME of ascent and time of descent IST=

hithe value of I and value of r BECOME 90° this is CALLED as CRITICAL anglel hope it's HELPING to YOUTHANK you ❤❤

IT WILL HELPS YOU.

re the quantities which are independent of other quantities. EX- Mass, length These are the quantities which are derived from fundamental quantities.━━━━━━━━━━━━━━━━━━━━★☆°Dimensional CONSTANT (Ex Gravitational constant)These quantities have constant values but they posses DIMENSIONS.★☆°Dimensional variables( ex-Volume)These quantities have VARIABLE values★☆°Dimensionless constant( ex-1,2,3...)These quantities have constant values but they LACK Dimension★☆°Dimensionless variables.(ex-Angles)They are variables and don't have dimensions

tion:R1>R2R2 has more current and LESS VOLTAGE but R1 has more voltage and less current.Therefore,by ohms law,R =V/ISo, R1 has more RESISTANCE than R2.Hope it helps you.

re essential in understanding a result. They’re also very helpful in determining whether a calculation is correct; and they can also be used to give back-of-the-envelope CALCULATIONS. Another definition of unit is an INDIVIDUAL thing or person regarded as single and complete but is also part of a whole or group. We also use the word unit while referring to the unit price of an ITEM. It means the cost per item, per LITER or per kilogram.WHAT ARE UNITS FOR?Units accomplish at least three things.1.They provide the context of the measured quantity.2.They provide the scale of the measured quantity.3.They establish a common framework amongst scientists by which physical RESULTS are expressed.

length = 7.5 cmExplanation:let ' Ri ' be the resistance of iron wire ,' Rs ' be the resistance of silver WIREAND ' A ' be the area of both the wires.( they have equal area because they have equal thickness )Given, Ri = Rs _________________ (i)SINCE the length is given as 12cm = 0.12mRi = rho × length / area = 10 × 10^-8 × 0.12 / ARi = 1.2 × 10^-8 / A _________________ (ii)let length of silver wire be ' l ' m .Rs = rho × length / areaRs = 16 × 10^ -8 × l / A _______________ (iii)from (i),(ii) and (iii) ,1.2 × 10^-8 / A = 16 × 10^-8 × l / A10^-8 and A can be cancelled on both sides,=> 1.2 = 16l=> l = 1.2 / 16 = 0.075 m = 7.5 cmHope this will HELP you.If so please mark me brainliest.

it's HARD can't UNDERSTAND and ANSWER!

this is your REQUIRE ANSWER ❤

s a ROUND WIRE ASSUME it's AREA to be area of a CIRCLE

Explanation:f net =mxa so here the external force is tension t=malet the string connected in b/w M2 and M3 is t' and the m1 and pulley is TSO the EQUATIONS are m3,40-t'=4a'm2,t'-2t =2am1,t=a by solving we get a+a'=10 =>a=10-a' by further solving we will get ACCELERATION

3Explanation:

A 2.50 L flask was used to collect a 5.65 g SAMPLE of propane GAS, C3H8. After the sample was COLLECTED, the gas pressure was found to be 741 mmHg. What was the temperature of the propane in the flask.Explanation:P= 741 mmHg(1 atm/760 mmHg)= .975 atmV= 2.50 Ln= 5.65 g C3H8 (1 mol/44 g)= .128 molR= 0.0821T= ?.975(2.50)= .128(0.0821)(T)2.4375 = .0151(T)ANSWER:161.4238 = T

e, Here's the ANSWER . . . GivenDensity of wood = 0.8Let V be the volume of wooden block, the volume of liquid displaced= 4V/5If the density of liquid is d thenThe WEIGHT of liquid displaced =4/5 Vdg.The weight of the block = V×0.8×1000×gAs the block floats,Hope it helps! ! ! ! MARK my answer as brainliest! ! ! Regards, ABHINAY.

.....UNPOLARISED ....

ปืนตารางการกระทำผิดกฎหมายเคราExplanation:ฮาร์ดแวร์ตารางเวลาการกระทำผิดกฎหมายเคราปืนสื่อสารออนไลน์ออฟไลน์ทุกวันฟรีทุกวันและบูม

tion:The depth of water at which AIR BUBBLE of radius 0.4 MM REMAINS in equilibrium is

Hey!In the theory of general RELATIVITY, the equivalence principle is the equivalence of gravitational and inertial mass, and Albert Einstein's observation that the gravitational "force" as experienced locally while standing on a massive BODY (such as the Earth) is the same as the pseudo-force experienced by an OBSERVER in a non-inertial (accelerated) FRAME of reference.hope it will be HELPFUL ✌️