A body starts with an initial velocity of 10m/s and is moving along a straight line with constant acceleration. When the velocity of the particle is 50m/s the acceleration is reversed in direction. The velocity of the particle when it again reaches the staring point is:

A body starts with an initial velocity of 10m/s and is moving along a

1.	A body starts with an initial velocity of 10m/s and is moving along a straight line with constant acceleration. When the velocity of the particle is 50m/s the acceleration is reversed in direction. The velocity of the particle when it again reaches the staring point is:
Answer» The VELOCITY of the particle is 70 m/s.Explanation:Given that,Initial velocity u = 10 m/sFinal velocity V = 50 m/sWhen the BODY acceleratedUsing equation of motion....(I)Now,The acceleration is reversedFinal velocity = 0Initial velocity = 50 m/sUsing equation of motion again.....(II)The body starts moving in OPPOSITE direction from that point. after coming to the initial point.The total distance s'' = s+s'Let the velocity of the body is v'Using equation of motion again,Hence, The velocity of the particle is 70 m/s.

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A body starts with an initial velocity of 10m/s and is moving along a straight line with constant acceleration. When the velocity of the particle is 50m/s the acceleration is reversed in direction. The velocity of the particle when it again reaches the staring point is:​

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A body starts with an initial velocity of 10m/s and is moving along a straight line with constant acceleration. When the velocity of the particle is 50m/s the acceleration is reversed in direction. The velocity of the particle when it again reaches the staring point is: