This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The air pressure inside a soap bubble of diameter 3.5 mm is 8 mm of water above the atmosphere. Calculate the surface tension of soap solution. |
| Answer» E = 2T÷rdiameter ÷ 2 =radiusr=3.5÷2 =1.75pressure ×r =TT= 4.5 × 1.75 = 7.875 where T is the SURFACE TENSION | |
| 2. |
The Earth is 150 000 000 km from the Sun. It takes light 500s to reach the Earth from the Sun. Calculate the speed of light in km/s. |
| Answer» SPEED =distance/timespeed=150000000/500speed=300000km/s | |
| 3. |
What amount of energy will be liberated if 1000 droplets each of diameter 10^-6 cm coalesce to from a bigger drop Surface tension of water is 75 x 10-3 N/m. |
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Answer» tion: I don't mine is from there anything is in reference accordance a private server IP in their WORK together soon enough so please advise whether in error while but when is there were very very HELPFUL advice please confirm you need immediate for an error number from all my first place but then that they said about an appointment tomorrow evening around this to a certain conditions is my INVOICE number one from Windows MEDIA you think they want more for it up so many OTHERS may just for |
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| 4. |
What is luminous intensity |
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Answer» In photometry, luminous intensity is a measure of the wavelength-weighted power emitted by a light source in a particular direction PER unit SOLID angle, BASED on the luminosity function, a standardized model of the sensitivity of the human eye. The SI unit of luminous intensity is the CANDELA (cd), an SI base unit. |
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| 5. |
Soap bubble is blown to a diameter of 7 cm. If36960 ergs of work is done in blowing it further, find the new radius, if surface tension of the soap solution is 40 dynes/cm. |
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Answer» nRadius of the expanded BUBBLE is 7 CM GivenInitial Diameter (D) = 7 cm Initial RADIUS (R) = 7/2 cm Work Done (W) = 36960 ErgsSurface Tension (S) = 40 Dyne/cm To finDNew Radius of the Bubble Let r be the new radius of the bubble Using the Relation, SUBSTITUTING the VALUES, |
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| 6. |
Electric and magnetic wave oscillating in a straight line is what kind of wave |
| Answer» ELECTROMAGNETIC WAVES | |
| 7. |
Calculate the work done in breaking a drop of water of 2 mm diameter into one thousand million droplets all of the same size. Surface tension of water is 72 x 10-3 M/m. |
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| 8. |
(vi) মানুষের চোখের দীর্ঘদৃষ্টি প্রতিকারে কী ধরনের লেন্স ব্যবহার করা হয়? |
| Answer» SAMAJ me NAHI AARA konsi LANGUAGE HAI | |
| 9. |
Find the work done in breaking a water drop of radius Imm into 1000 droplets.surface tension of water = 72 x 10-3 N/m] |
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| 10. |
Calculate the work done in blowing out a soap bubble of diameter 1 cm. Given that the surface tension of soap solution is 28 x 10-3 N/m. |
| Answer» TION:Calculate the WORK DONE in blowing out a soap bubble of DIAMETER 1 cm. given that the surface tension of soap SOLUTION is | |
| 11. |
A square wire frame of side 10 cm is dipped in a liquid of surface tension 28 x 10-3 N/m. On taking out, a membrane isformed. What is the force acting on the surface of wire frames. |
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Answer» F = 2.24 × 10⁻² NExplanation:Given : Side of square = 10 cm = 0.1 mSurface tension = 29 × 10⁻³ N / mWe KNOW : The surface frame has two free surface.= > Perimeter of square = 4 L= > Total length of the frame = 4 lWe have expression for surface tension .Surface tension = FORCE / Length= > F = S × L= > F = 8 × 0.1 × 28 × 10⁻³ N= > F = 224 × 10⁻⁴ N= > F = 2.24 × 10⁻² NTherefore we GET required answer. |
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| 12. |
A body floats in water with 40% of its volume out side the water. When the body floats in oil, 60% of its volume remainsoutside oil. What is the relative density of oil? |
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Answer» Let : V = volume of bodyρ = DENSITY of liquidρ₀ = density of water.= > Weight of body = Upthurst . Weight of body = ( 100 - 40 ) V ρ₀ G / 100= > ( 100 - 60 ) V ρ g / 100Now RELATIVE density : R.D. = ρ / ρ₀= > R.D. = 0.6 / 0.4= > R.D. = 1.5Therefore , relative density of water is 1.5 . |
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| 13. |
A cubical block of wood of 10 cm side floats on a side at the interface between oil and water, with its lower surfacehorizontal and 4 cm below the interface. What is the mass ofthe block? The density of the oil is 0.6 g/cm'. |
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Answer» 760 G EXPLANATION:Volume of the block = 10 × 10 × 10 = 1000 cm³Volume of block in water = 10 × 10 × 4 = 400 cm³= > Volume of the block in oil = 100 - 400 = 600 cm³Now block WEIGHT : Weight of block = WT. of water displaced + wt. if oil displaced.= > m g = 400 × 1 × g + 600 × 0.6 × 6= > 400 + 360 g= > 760 gTherefore , mass of the block is 760 g . |
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| 14. |
A piece of brass weighs 12.9 g in air. Brass is an alloy of Zinc and copper. When completely immersed in water it weighs11.3 g. What is the mass of copper contained in the alloy?Specific gravity of zinc and copper are 7.1 and 8.9respectively. |
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Answer» 7.61 gExplanation:LET : Mass of copper in the alloy = m= > Mass of zinc = ( 12.9 - m ) g= > Volume of copper = m / 8.9 Volume of zinc = ( 12.9 - m ) / 7.1Total volume of the alloy = m / 8.9 + ( 12.9 - m ) / 7.1 .... ( i ) = > Apparent loss of weight of alloy = 12.8 - 11.3 = 1.6 g wtVolume of water DISPLACED by alloy = 1.6 / 1 = 1.6 cm³ ..... ( II ) From ( i ) and ( ii ) we get : m / 8.9 + ( 12.9 - m ) / 7.1 = 1.6= > 7.1 m + 8.9 ( 12.9 - m ) = 1.6 × 8.9 × 7.1= > m = 7.61 gTherefore , mass of copper contained in the alloy is 7.61 g. |
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| 15. |
A piece of iron floats in mercury. Given that the denisty of iron is 7.8 x 103 kg/m3 and that of mercury is 13.6 x 10 kg m. Calculate the fraction of the volume of iron piece that remains outside the mercury. |
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Answer» Let : V = Total VOLUME of the piece of iron.v = The volume of the portion of iron outside mercury.= > The piece of iron will FLOAT if weight of iron piece = wt. of mercury displaced by immersed portion of iron.= > ( V × 7.8 × 10³ × G ) = ( V - v ) × 13.6 × 10³ × g= > ( V × 7.8 × 10³ ) = ( V - v ) × 13.6 × 10³= > ( V × 7.8 ) = ( V - v ) × 13.6 = > v / V =0.43Therefore , FRACTION of the volume of iron piece that remains outside the mercury is 0.43. |
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| 16. |
A cylinder has a radius 10 cm. To what height should it be filled with water so that the thrust in its walls is equal to that on its bottom? |
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Answer» Let : ρ = density of waterh = height of water in cylinder= > Thrust at the bottom = F= > F = PRESSURE × AreaWe KNOW : Pressure = ρ H gArea = π r²= > Thrust on walls = Average pressure × Area= > F' = ( ρ h G / 2 ( 2 π r h ) When F = F' then= > ( ρ h g × π r² ) = π r ρ h² g [ h = r ] Therefore we get answer. |
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| 17. |
Resistivity between substance of 1 metre long and 1square main cross section It is given that resistivity is 1cube m how |
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Answer» resistivity is constExplanation:resistivity is ALWAYS const for a MATERIAL and does not depend on its length and other DIMENSIONS |
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| 18. |
The volume of an air bubble becomes 8 times the original volume in rising from the bottom of a lake to its surface. If the barometric height is 0.76 m of Hg (density of Hg is 13.6g/cm3 and g=9.8 m/s2), what is the depth of the lake?Aylinder hand |
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Answer» 72.35 mExplanation:SINCE volume of bubble become 8 times on reaching the surface.Therefore pressure on surface of lake 1 / 8 times pf pressure at the bottom.By BOYLE's law pressure at bottom of the lake = 8 P [ P = pressure at surface. ] = > Pressure due to column of liquid = 8 P - P = 7 PP = 7 × 0.76 × 13.6 × 10³ × 9.8 N / m²Now we know : P = ρ h gDensity of mercury ρ = 13.6 × 10³ kg / m³= > h = ( 7 × 0.76 × 13.6 × 10³ × 9.8 ) / ρ G= > h = ( 7 × 0.76 × 13.6 × 10³ × 9.8 ) / 10³ × 9.8= > h = 72.35 mTherefore , depth of the lake is 72.35 m. |
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| 19. |
What is the meaning of phulcritudinous?? |
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Answer» Pulchritudinous is a way to describe great physical beauty. A person who is very beautiful WOULD be described as pulchritudinous. EXPLANATION:HOPE IT HELPS YOU AND IF IT THEN PLEASE MARK IT BRAINLIEST |
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| 20. |
A water tank is 20 m deep. What is the pressure at thebottom of the tank in atmosphere? |
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Answer» 3 atmExplanation:Pressure at the bottom of tank = ATMOSPHERIC pressure + pressure due to the LIQUID column.i.e.P = P₀ + ρ h GP = ( 1 + ρ h g / P₀ ) atmWe have given : HEIGHT h = 20 mPutting value here we getP = ( 1 + 20 ρg / 10⁵ ) P = 3 atmTherefore , pressure at the bottom of the tank in atmosphere is 3 atm. |
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| 21. |
Plz Help ASAP. Step by step explanation plz. A man drags a sack of flour of mass 50 kg at constant speed up an inclined plane to a height of 5 m. The plane makes an angle of 30 degrees with the horizontal and a constant frictional force of 200N acts on the sack down the plane. Calculate the work that the man does against: 1. Friction 2. Gravity |
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| 22. |
What is refraction and write its cause |
| Answer» TION:Refraction is the phenomenon of bending of LIGHT at the boundary of two mediums. Refraction is caused due to the CHANGE in speed of light when it enters from one medium to another. ... when light goes from WATER to air it BENDS away from the normal because three is an increase in speed of light.HOPE IT HELPS UH ❤ | |
| 23. |
What is potential energy of any body on the surface of the earth???.... |
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Answer» The energy stored in an object due to its POSITION above the Earth's surface is called gravitational potential energy. This energy is due to the force of GRAVITY acting on an object. When a stone falls from a height then potential energy is CONVERTED to kinetic energy when it comes on the surface of earth. |
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| 24. |
Define:Electrostatic force |
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Answer» The triboelectric effect causes an ELECTROSTATIC charge to build up on the surface of the fur due to the cat's motions. The electric field of the charge causes polarization of the MOLECULES of the STYROFOAM due to electrostatic induction, resulting in a slight attraction of the light plastic pieces to the charged fur. This effect is also the CAUSE of static cling in CLOTHES..... |
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| 25. |
the coordinate of a moving particle at time is given by X=5sin10t and Y=5cos 10t.the speed of particle is? |
| Answer» EY your answersee attachmentExplanation:V is OBTAINED by DIFFRENTIATION of xthanks | |
| 26. |
Find the length of transerverse&conjugate axes of the hyperbolax²/4-y²/12=1 |
| Answer» COMPARE the EQUATION x^2/a^2+y^2/b^2=1 then a=2 b=2√3 LENGTH of TRANSVERSE 4 and conjugate 12 | |
| 27. |
Is it necessary that all electric circuits contain conducting wire. If yes why? |
| Answer» TION:yes it is NECESSARY because conducting wires conduct ELECTRICITY if there is not conducting wire there is no movement of electrons and electric current does not flow | |
| 28. |
What is a pull and give some daily life examples |
| Answer» PULL means to use force to move somebody/ something TOWARDS yourself.Some daily life examples are: 1. OPENING a drawer.2. Drawing a bucket of water from well.Hope it helps you........Plz mark it as the BRAINLIEST answer. | |
| 29. |
Two bodies of different masses ma and mb are dropped from two different heights |
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Answer» Need full QUESTION BCZ INADEQUATE of information |
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| 30. |
A light of intensity 16 mw?? |
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Answer» what to do in this QUESTION |
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| 31. |
Two identical charges are placed an a separation of 1m.What should be the magnitude of each charge, so that each one repel the other with a force 36kgwt. (g = 10m/s^2) |
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Answer» Magnitude of each CHARGE, q = 0.63 × 10^-4 C EXPLANATION:Refer the attached picture. |
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| 32. |
What was Newton's Law of universal gravitation? |
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Answer» tion:Newton's law of universal gravitation is usually stated that every particle ATTRACTS every other particle in the universe with a FORCE which is directly PROPORTIONAL to the PRODUCT of their masses and inversely proportional to the square of the distance between their centers. .hope this will help you.thank you |
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| 33. |
Find charge on each capacitor |
| Answer» STORED electric charge in a capacitor, Q (in coulombs, abbreviated C) is EQUAL to the product of the capacitance C (in Farads, abbreviated F) of the capacitor, and the voltage V (in volts, abbreviated V) across its TERMINALS. That is, Q = C٠V. For EXAMPLE, if C = 33uF and V = 20V, then Q = (33٠10^-6)٠(20) = 660uC.Explanation: | |
| 34. |
What is Kepler's law.?????? |
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Answer» tion:Definition of KEPLER's law. 1 : a statement in ASTRONOMY: the orbit of each planet is an ellipse that has the SUN at one focus. 2 : a statement in astronomy: the RADIUS vector from the sun to each planet generates equal orbital areas in equal times.hope it's helpful for you ☺️be brainly ☺️please Mark as brainlist ☺️ |
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| 35. |
Is magnetic force a contact or non contact , justify the above one |
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Answer» Magnetic FORCES are non contact forces; they pull or PUSH on objects without touching them. Magnets are only attracted to a few 'magnetic' METALS and not all matter. Magnets are attracted to and REPEL other magnets. |
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| 36. |
State laws of motion |
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Answer» The First LAW of Motion STATES, "A body at REST will REMAIN at rest, and a body in motion will remain in motion unless it is ACTED upon by an external force." This simply means that things cannot start, stop, or change direction all by themselves.Explanation:mark as Brainliest |
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| 37. |
13. A square surface of side L meme is in the plane of the paper. A uniform electric field E voltalso in the plane of the paper is limited onlythe lower half of the square surface. seeFigure. The electric flux in SI units associatedwith the surface is1)zero2)EL^23)EL^2/2€4)EL^2/2 |
| Answer» 4)Explanation:HALF the area of the SQUARE and multiply it with the electric FIELD magnitude | |
| 38. |
Where laser can be used in scientific investigation? |
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Answer» nce, LASERS are used in MANY ways, including: A wide variety of interferometric TECHNIQUES.Holographic techniques employing lasers also contribute to a NUMBER of measurement techniques. Laser based lidar (LIght raDAR) technology has application in geology, seismology, remote sensing and atmospheric physics.hope it helps you....PLEASE mark it BRAINLIEST Dude.... |
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| 39. |
21. A particle is moving with uniform accelerationalong a straight line AB. Its speed at A and B are2m/sec and 14 m/sec respectively. Then its speedat the midpoint of AB is -(1) 10 m/sec(2) 8 m/sec(3) 12 m/sec(4) 6 m/sec |
| Answer» TION:hiyour ANSWER is 2) 8m/sl hope it's helping to YOUTHANK you | |
| 40. |
Find the change in the entropy of helium when heated from 300 K to 1000 K at constant pressure. (Helium content = 1 kg) |
| Answer» TION: | |
| 42. |
Given, A= i+3j–k and B= 2i–j+k determine the unit vector parallel to A×B |
| Answer» TION:HOPE it is useful as i had GIVEN a simple SOLUTION | |
| 43. |
Four potential forces can act on the ball. Which combination of forces will keep the ball in static equilibrium? The length of the arrows represents the magnitude of the force. A) A and B B) A and C C) B and D D) B, C, and D |
| Answer» C (B and D)EXPLANATION:because they both have more MAGNITUDE | |
| 44. |
9. Is magnetic force a contact or non-contact force? Justify. |
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| 45. |
Draw a labelled ray diagram to locate the image of an object formed by a convex lens of focal length 20 cm when the object is placed 20 cm away from the lens. |
| Answer» TION:MARK me as BRAINLIEST... HOPE HELPS | |
| 46. |
5. When 0.5 C charge passes through a cross-section of a conductor in 5 s. find the current? a) 0.1 A b) 1 A c) 10 A d) 25 A |
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Answer» 0.1 AEXPLANATION: |
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| 47. |
Why bridge is constructed with one end resting on rollers |
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Answer» have rollers at one end then it is allowed to EXPAND FREELY WITHOUT any thermal stress.in summers the bridges may expand DUE to the increase in the temperature and in WINTERS the bridges may compress due to decrease in the temperature. |
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| 48. |
If an object is thrown from a cliff of unknown height, it’s final velocity is 100 m/s. What is the height of the cliff? |
| Answer» PE = KEPlease MARK my ANSWER the BRAINLIEST. | |
| 49. |
1. Write any two precautions to be taken while using LPG? 2. What is the main constituent of natural gas? |
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Answer» 1: main precaution of lpg is that we cannot take some fired SUBSTANCE like candle 2:the main CONSTITUENT of natural gas is butane |
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