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A piece of iron floats in mercury. Given that the denisty of iron is 7.8 x 103 kg/m3 and that of mercury is 13.6 x 10 kg m. Calculate the fraction of the volume of iron piece that remains outside the mercury. |
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Answer» Let : V = Total VOLUME of the piece of iron.v = The volume of the portion of iron outside mercury.= > The piece of iron will FLOAT if weight of iron piece = wt. of mercury displaced by immersed portion of iron.= > ( V × 7.8 × 10³ × G ) = ( V - v ) × 13.6 × 10³ × g= > ( V × 7.8 × 10³ ) = ( V - v ) × 13.6 × 10³= > ( V × 7.8 ) = ( V - v ) × 13.6 = > v / V =0.43Therefore , FRACTION of the volume of iron piece that remains outside the mercury is 0.43. |
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