Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

2/5 of total number of student of a school come by car while 1/4 students come by bus to school. all the other students walk to school of which 1/3 walk on their own and the rest are escorted by their parents. If 224 students come to school walking on their own, how many students study in that school?

Answer»

Let the total no. of students be X
number of students who come by car = 2x/5
number of students who come by bus = x/4
number of students who come by WALK = x - (2x/5 + x/4) = x - 13x/20 = 7x/20
number of students who come by walk on their own = (7x/20)/3 = 224
7x/60 = 224
x = 224×60÷7 = 1920


Hope this will help U

2.

Please guys solve it it's urgent ...

Answer» C is the ANSWER of the QUESTION
3.

Simplify 2 + root 3 / 2 minus root 3 + 2 minus root 3 / 2 + root 3 + root3 - 1 / root 3 + 1

Answer»

Hey friend,
Here is the ANSWER you were looking for:
\frac{2 +  \sqrt{3} }{2 -  \sqrt{3} }  +  \frac{2 -  \sqrt{3} }{2 +  \sqrt{3} }  +  \frac{ \sqrt{3}  - 1}{ \sqrt{3} + 1 }  \\  \\ on \: rationalizing \: the \: denominator \: we \: get \\  \\  =  \frac{2 +  \sqrt{3} }{2 -  \sqrt{3} }  \times  \frac{2 +  \sqrt{3} }{2 +  \sqrt{3} }  +  \frac{2 -  \sqrt{3} }{2 +  \sqrt{3} }  \times  \frac{2 -  \sqrt{3} }{2 -  \sqrt{3} }  +  \frac{ \sqrt{3}  - 1}{ \sqrt{3}  + 1}  \times  \frac{ \sqrt{3} - 1 }{ \sqrt{3}  - 1}  \\  \\ using \: the \: identity \\  {(a + b)}^{2}  =  {a}^{2}  +  {b}^{2}  + 2ab \\  {(a - b)}^{2}  =  {a}^{2}  +  {b}^{2}  - 2ab \\ (a + b)(a - b) =  {a}^{2}  -  {b}^{2}  \\  \\  =  \frac{ {(2)}^{2} +  {( \sqrt{3}) }^{2}   + 2(2)( \sqrt{3} )}{ {(2)}^{2}  -  {( \sqrt{3} })^{2} }  + \frac{ {(2)}^{2} +  {( \sqrt{3}) }^{2}    -  2(2)( \sqrt{3} )}{ {(2)}^{2}  -  {( \sqrt{3} })^{2} }  +  \frac{ {( \sqrt{3} )}^{2} +  {(1)}^{2}  - 2( \sqrt{3})(1)  }{ {( \sqrt{3}) }^{2} -  {(1)}^{2}  }  \\  \\  =  \frac{4 + 3 + 4 \sqrt{3} }{4 - 3}  + \frac{4 + 3  -  4 \sqrt{3} }{4 - 3}  +  \frac{3  + 1 - 2 \sqrt{3} }{3 - 1}  \\  \\  = 7 + 4 \sqrt{3}  + 7 - 4 \sqrt{3}  +  \frac{4 - 2 \sqrt{3} }{2}  \\  \\  = 7 + 7 + 2 -  \sqrt{3}  \\  \\  = 16 -  \sqrt{3}

HOPE this helps!!!

If you have any doubts regarding to my answer, feel free to ask in comment SECTION or inbox me.

@Mahak24

Thanks...
☺☺

4.

A newspaper contains 124 columns Each column contains 136 lines Each line has 36 letters how many letters are there in the newspaper

Answer»

Total no. of letters = 124 × 136 × 36 = 607,104

Hope it helps you.

Have a GOOD DAY.

5.

Pls solve this question 80 no

Answer»

Lloooooilll...the ANSWER is NOTHING ...QUEATION is WRONG

6.

What is the value of log5 base 25

Answer» HI put x = log 5 to the base 25
Then
{25}^{x}  = 5
i.e. x = 1/2
HOPE this HELPS.
7.

Find x^3+y^3-12xy+64 ,when x+y= -4

Answer» SINCE it is given that x+y=-4 by cubing on both SIDES we get
x^3+y^3+3xy(x+y) = -64
x^3+y^3+3xy(-4) = -64
x^3+y^3-12xy = -64
hence SUBSTITUTING this we get -64+64 = 0
hence the ANSWER is 0
8.

Solve these questions in detaik

Answer» HEY apply rationalization in each term and then SOLVE it
its very EASY
9.

The product of two numbers x6 - y6 if one of the numbers is x-y then find the other number

Answer»

Given: the product of two numbers X^6 - y^6.

To FIND: if one of the numbers is x-y then find the other number

Solution:

  • Now we have given that the one of the numbers is x-y .
  • Let the other number be Z.

                    (x³)² - (y³)²

  • Now according to the formula a² - b² = (a-b)(a+b), we get:

                    ( x³ - y³)(x³ + y³)

  • Now according to the formula a³ - b³ = (a-b)(a²+ab+b²), we get:

                    (x - y)(x² + XY + y²)(x³ + y³)

  • Now according to the question, we have:

                    z × (x - y) = (x - y)(x² + xy + y²)(x³ + y³)

                    z = (x² + xy + y²)(x³ + y³)

Answer:

          So the other number is (x² + xy + y²)(x³ + y³).

10.

Given, √(2)=1.414 and √(6)=2.449, find the value of 1/√(3)-√(2)-1 correct to 3 places of decimal.

Answer»

Hi ,

It is given that ,

√2 = 1.414 ,

√6 = 2.449 ,

Now ,

1/√3 - ( √2 )^-1

= 1/√3 - 1/√2

= ( √2 - √3 ) / √ 6

= [ √6 ( √2 - √3 ) ]/[ √6 × √6 ]

= [ √12 - √18 ]/6

= [ √(2×2×3) - √(3×3×2) ]

= [ 2√3 - 3√2 ] /6

= [ 2 × 1.732 - 3 × 1.414 ]/6

= [ 3.464 - 4.242 ]/6

= - 0.778/6

≈ - 0.129

≈ - 0.13

I HOPE this HELPS you.

: )

11.

Please solve it. it is the ouestion of 9 class topic number system in exponents

Answer»

Rationalise the following no.

ROOT 11 - root 7/ root 11 + root 7
root 11 - root 7/ root 11 + root 7 * root 11 - root 7/ root 11 -root 7

(root 11- root7) whole square / root 11 square - root 7 square

11+7 - 2 root 77 / 11-7 = 18-2root77/4 = 18/4 - 2root77/4

= 9/2 - root77 /2 = a - b root 77

Therefore a = 9/2 ,

 -broot 77 = -root77/2.
that is equal too 1/2

12.

Find two numbers whose product is a 1digit number and sum is a 2digit number of

Answer»

We have to find TWO NUMBERS whose product is a 1 digit number and the sum is a two digit number.

These two numbers are 1 and 9

Now product of 1 and 9 = 1*9 = 9

and sum of 1 and 9 = 1 + 9 = 10

13.

A cylindrical container mounted on a hemispherical bowl. the diameter of the hemispherical bowl is 10cm. if the figure has height 14cm, find the height of the cylinder. the radius of the cylinder, total surface area of the whole figure, and the volume of the whole figure. please help!

Answer» H(CYLINDER)=14-5=9cm
r (cylinder)=5
TSA=3pi r^2+2pi rh
vol=2/3pi r^3 + PI r^3 h
14.

What is the LCM of 861 &1353

Answer»

861=3x7x41
1353=3x11x41
now .l.c.m = 3x41x7x11= 9471....
ANSWER = 9471

15.

Simplify the following into a fraction 5Highway 17 class big bracket 3 minus curly bracket 4 by 2 minus

Answer»
your answeet is my MATE is a 4M

16.

Simplify 3¾ and 3^ 1/4 , 5⅓/5^1/6 and 3^2/3×7⅔.

Answer» 5 , 6 and 4 are the ANSWERS
17.

Derivation of y equal to cos square x with respect to x

Answer»

It is the ANSWER with all CORRECT steps
use the PRODUCT RULE

18.

Definition of non mutually exclusive event in probability

Answer»

I HOPE this ANSWER HELP you

19.

If {{x}^{2}}+2ax+10-3a>0for all x\in R, then [IIT Screening 2004]A) -55 D) 2

Answer»

According to given condition

4A SQUARE - 4(10-3A) < 0
a square +3a - 10 <0
(a+5)(a-2) < 0

-5

20.

How will you distinguish rational and irrational no through decimal form

Answer» RATIONAL number will be in the FORM of p/q(ex.1.5,2.4)
IRRATIONAL number will be in the form of decimal form there will be REPEATING one(ex:1.212121........)
21.

50 people consume an average of 110 kg of rice in a week. If 20 more people join this group, how many kilogram of rice will be needed for a week?

Answer»

50 people    X1                110 kg  yi

50+20 =70      x2                   ?? Y2

no of people and no of kgs are in direct proportion

x1/y1 = x2/y2

when we cross multiply the formulae changes to 

x1y2 = x2y1

50 * y2 = 110 *70


y2 = 110 * 70/ 50

y2 = 154

therfore 154 kgs of rice is NEEDED for 70 people for a week


22.

K(k+1)(2k+1)/6+(k+1)whole square

Answer»

Here is your ANSWER...
HOPE this will HELP you....

23.

A rectangular field is to be fenced on 3 sides leaving a side of 20 m uncovered. If the area of the field is 680 m^{2} , how many meters of fencing is required?NOTE: PLEASE DISPLAY THE STATEMENTS!

Answer» UNCOVERED part=breadth of rectangle=20m
area of field=680
area=l*b
∴length=34m
∴Fencing REQUIRED = (34+34+20)m
=90m
24.

Suneeta types 1080 words in an hour.What is her GWAM (gross words a minute rate)?

Answer» 18 WORDS PER HOUR will be her GWAM
25.

What is matrix invertion method....

Answer»


MaMarices, there is no such thing as division. You can add, subtract, and multiplymatrices, but you cannot divide them. There is a related concept, though, which is called "inversion". First I'll discuss why inversion is useful, and then I'll show you how to do it.

Think back to when you first learned about how to solve linear equations. If you were given something like "3x = 6", you would solve by dividing both sides by 3. Since multiplying by1/3 is the same as dividing by 3, you could also multiply both sides by 1/3 to get the same answer: x = 2. If you needed to solve something like "(3/2)x = 6", you could still divide both sides by 3/2, but it was probably easier to multiply both side by 2/3. The reciprocal fraction2/3 is the inverse of 3/2 because, if you multiply the two fractions, you get 1, which is, in this context, called "the (multiplicative) identity": 1 is called the identity because multiplying something by 1 doesn't change its VALUE.

 

This terminology and these facts are very important for matrices. If you are given a matrix equation like AX = C, where you are given A and C and are TOLD to figure out X, you would like to "divide off" the matrix A. But you can't do division with matrices. On the other hand, what if you could find the inverse of A, something similar to finding the reciprocal fraction above? The inverse of A, written as "A–1" and pronounced "A inverse", would allow you to cancel off the A from the matrix equation and then solve for X.

AX = C 
A–1AX = A–1C 
IX = A–1C 
X = A–1C 

How did "A–1AX" on the left-hand side of the equation turn into "X"? Think back to the nature of inverses for regular numbers. If you have a number (such as 3/2) and its inverse (in this case, 2/3) and you multiply them, you get 1. And 1 is the identity, so called because 1x = x for any number x. It works the same way for matrices. If you multiply a matrix (such as A) and its inverse (in this case, 
A–1), you get the identity matrix I. And the point of the identity matrix is that IX = X for any matrix X (meaning "any matrix of the correct size", of course).

It should be noted that the order in the multiplication above is important and is not at all arbitrary. Recall that, for matrices, multiplication is not commutative. That is, AB is almost NEVER equal to BA. So multiplying the matrix equation "on the left" (to get A–1AX) is not at all the same thing as multiplying "on the right" (to get AXA–1). And you can not say that the product AXA–1 equals A–1AX, because you can't switch around the order in the multiplication. Instead, you have to multiply A–1 on the left, putting it right next to the A in the original matrix equation. And since you have to do the same thing to both sides of an equation when you're solving, you mustmultiply "on the left" on the right-hand side of the equation as well, resulting in A–1C. You cannot be casual with your placement of the matrices; you must be precise, correct, and consistent. This is the only way to successfully cancel off A and solve the matrix equation.

As you have seen above, inverse matrices can be very useful for solving matrix equations. But, given a matrix, how do you invert it? How do you find the inverse? The technique for inverting matrices is kind of clever. For a given matrix A and its inverse A–1, we know we have A–1A = I. We're going to use the identity matrix I in the process for inverting a matrix.

Find the inverse of the following matrix.



First, I write down the entries the matrix A, but I write them in a double-wide matrix:



In the other half of the double-wide, I write the identity matrix:



Now I'll do matrix row operations to convert the left-hand side of the double-wide into the identity. (As always with row operations, there is no one "right" way to do this. What follows are just the steps that happened to occur to me. Your calculations could easily look quite different.)



Now that the left-hand side of the double-wide contains the identity, the right-hand side contains the inverse. That is, the inverse matrix is the following:



Note that we can confirm that this matrix is the inverse of A by multiplying the two matrices and CONFIRMING that we get the identity:   Copyright © Elizabeth Stapel 2003-2011 All Rights Reserved



Be advised that, in "real life", the inverse is rarely a matrix filled with nice neat whole numbers like this. With any luck, though, especially if you're doing inverses by hand, you'll be given nice ones like this to do.

hope it helps you

26.

Advantage disadvantage and application of topology optimization

Answer»

A topology optimization problem can be written in the general form of an
optimization problem as:
The problem statement includes the following:
An OBJECTIVE FUNCTION . This function represents the QUANTITY that is being minimized for best performance. The most common objective function is compliance, where minimizing compliance leads to MAXIMIZING the stiffness of a STRUCTURE.

27.

class VIII sold tickets for 12 days by selling 250 tickets each days. class IX sold tickets for 10 days by selling 300 tickets each days. who sold more tickets?

Answer»

BOTH SOLD EQUAL NUM OF TICKETS BUT 8TH CLASS TOOK TWO DAYS THAN 9TH CLASS. SO BOTH SOLD 3000 TICKETS

28.

Find the smallest number by which 2560 must be multiplied so that the product is a perfect cube

Answer» MUST MULTIPLY by 25 to MAKE 2560 a perfect cube...!
29.

The number of roots of the equation \log (-2x)=2\log (x+1)are [AMU 2001]A) 3 B) 2 C) 1 D) None of these

Answer»

Option "B" is the CORRECT ANSWER


so 2 ROOT of the equation..

I think my answer is CAPABLE to CLEAR your confusion..

30.

Express each of the following in p/q form q is not zero and p and q are integers 7.125

Answer»

7.125 can be EXPRESSED in p/q FORM as.....7125/1000 0R 57/8

31.

Units of magnetic flux density......

Answer»

Hello friend your answer!!!
The UNIT's of MAGNETIC flux DENSITY is Tesla.
so that a flux density of 1 Wb/m2 is 1 tesla.

The SI unit is (newton. second)/(coulomb. metre).

hope it helps you
mark me as brainliest PLZZ ♥♥♥♥♥♥♥♥

32.

Question number 2no smapping

Answer» 0
33.

If 24 men's do any work in 16 days then how much he work in 12 days

Answer» 24 MEN       x1                          16 DAYS     Y1

??                x2                           12 DAYS     y2

no of men and no of days are in inverse proportion

x1y1 = x2y2

24 * 16 = x2 * 12

x2 = 24 *16/12

x2 = 32


HOPE U LIKE





34.

Express each of the following in p/q form q is not zero and p and q are integers

Answer»

But where are the QUESTIONS....

35.

If 3 and -3 are two zeros of the polynomial x^4+x^3-11x^2-9x+18

Answer»

Hey

Here is your answer

In attachment

Hope it HELPS you!

36.

find the area of isosceles triangle with equal sides A unit and third side B unit using herons formula.

Answer» AREA of a triangle by heron's formula is
√(s(s-a)(s-b)(s-c))
given a=b=Aunit , c=Bunit
so s=A+A+B/2 = (2A+B)/2
by SUBSTITUTING these values we get
area = √[(2A+B)/2][(2A+B)/2-A]^2[(2A+B)/2-B]
= 1/4B√(4A^2-B^2)
HENCE the ANSWER is 1/4B√(4A^2-B^2)sq.units
37.

the age of two boys A and B are 6 years 8 months and 7 years 4 months respectively divide 3150 in the ratio of their age

Answer»

According to QUESTION

A and b

A= 6 year 8 month=6 8/12=6 2/3=20/3 year


B=7 year 4month=7 4/12=7 1/3=22/3 year
20/3+22/3=42/3=14


Rs 3150/14= 225

A 20/3= 1500

B 22/3=1650

1500:1650 = 10:11

hope it will HELP you..

38.

places A and B are 30 km apart and they are on a straight road. Hamid travels from A to B on bike.At the same time Joseph starts from B on bike towards A. They meet each other after 20 minutes.If Joseph would have started from B at same time but in the opposite direction (instead of towards A) Hamid would have caught him after 3hours. Find the speed of Hamid and Joseph

Answer»

Hello,

PLEASE refer the above photograph for the USED PROCESS

Hope this will be HELPING you ✌️

39.

Plz solve 9th 2nd question

Answer» LET x=0.1363636.....
10x=1.363636.....
1000x=136.363636.....
SUBTRACTING eq.2from3
1000x-10x=136.36....-1.36....
990x=135
x=135/990
x=27/198
x=3/22
40.

There are 1869 students on the rolls of a school if each student pays 27650 as fees annually how much money is collected in a year

Answer» ANSWER is
1869×27650=₹51677860
41.

in a town,1 out of 27 people owns a car.if the total population of the town is 49,626, then how many people have cars?

Answer»

No. Of TOTAL population=49626
No . of PEOPLE own a CAR =1/27
Peoples own CARS in the TOWN = 49626÷27=1838

42.

A couple has two children, one of which is a boy. what is the probability that they have two boys

Answer» SEE the image which I have ATTACHED and comment if there is any PROBLEM with the SOLUTION.
43.

A and b are two given sets then prove that a intersection (a intersection b)' = a intersection b'

Answer» AINT(AintB)'

=Aint [A'uB']

=(AintA')U (AintB')

=(PHI)u(AintB')

=AintB'


int__intrsection
u__union
44.

Represent -4/11 in decimal form

Answer»

-0.363 APPROX is UR ANS

45.

Represent-13/16 in decimal form

Answer»

Here's your answer :

-13.000 / 16 will be the DECIMAL FORM of -13/16.

Hope this helps you. ..
THANK YOU. .

46.

The dis between two stationsA and B is 540 km. Two trains start simultaneously from these stations on parallel tracks to cross each other. The speed of one of them is greater than the other by 5 km per hour. If the distance between these two trains after 3hours of their start is 165 km find the speed of each train?

Answer»

Let the speed of one train is X km/h

then the speed of ANOTHER train is (x+5)km/h

distance travelled by first train in three hour is x*3=3x

distance travelled by another train is(3(x+5)=3x+15

the TOTAL distance travelled by two trains are 3x+3x+15=6x+15

acc.to.ques.

6x+15=540

6x=540-15=525

x=525/6=175/2 km/h

speed of another train=175/2+5=185/2 =92.5 km/h

47.

X^3-4x2-7x+10 divided by x^2+x-2

Answer»

The ANS for this is x-5 and REMAINDER is ZERO

48.

(x)2+5√5x+30. class 9

Answer» 0
49.

A boy covers a distance of 20 km in 2/5 hours, partly on foot at the rate of 5 km per hr and partly on bicycle at the rate of 10km per hour. Find the distance covered on foot?

Answer»

Let TIME taken to travel on foot = X
Then, time taken to travel on bicycle = (2.5 - x)

So,
5(x) + 10(2.5 - x) = 20
Solving, we get
x = 1

So, distance TRAVELLED on foot = 5 km

Hence, the boy covered 5 km on foot.

Hope this helps! :P

50.

there are 20 bowls. each bowl has 12 candies . if 4 candies are taken away from each bowl, then how many candies are left in the bowls?

Answer»

Given,
No. of BOWLS = 20 bowls
No. of candies in each BOWL = 12 candies
To FIND:
If 4 candies are taken away from each bowl then how many candies are left in bowls.
Solution:
Total no. of candies in total bowls = 20 × 12
= 240 candies
if we REMOVE 4 candies from each bowl then= 4 × 20 = 80
we have to remove 80 candies
Remaining candies = 240 -80
= 160.

Hope it helps...

PLS mark as brainliest...