1.

Given, √(2)=1.414 and √(6)=2.449, find the value of 1/√(3)-√(2)-1 correct to 3 places of decimal.

Answer»

Hi ,

It is given that ,

√2 = 1.414 ,

√6 = 2.449 ,

Now ,

1/√3 - ( √2 )^-1

= 1/√3 - 1/√2

= ( √2 - √3 ) / √ 6

= [ √6 ( √2 - √3 ) ]/[ √6 × √6 ]

= [ √12 - √18 ]/6

= [ √(2×2×3) - √(3×3×2) ]

= [ 2√3 - 3√2 ] /6

= [ 2 × 1.732 - 3 × 1.414 ]/6

= [ 3.464 - 4.242 ]/6

= - 0.778/6

≈ - 0.129

≈ - 0.13

I HOPE this HELPS you.

: )


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