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Find x^3+y^3-12xy+64 ,when x+y= -4 |
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Answer» SINCE it is given that x+y=-4 by cubing on both SIDES we get x^3+y^3+3xy(x+y) = -64 x^3+y^3+3xy(-4) = -64 x^3+y^3-12xy = -64 hence SUBSTITUTING this we get -64+64 = 0 hence the ANSWER is 0 |
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