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find the area of isosceles triangle with equal sides A unit and third side B unit using herons formula. |
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Answer» AREA of a triangle by heron's formula is √(s(s-a)(s-b)(s-c)) given a=b=Aunit , c=Bunit so s=A+A+B/2 = (2A+B)/2 by SUBSTITUTING these values we get area = √[(2A+B)/2][(2A+B)/2-A]^2[(2A+B)/2-B] = 1/4B√(4A^2-B^2) HENCE the ANSWER is 1/4B√(4A^2-B^2)sq.units |
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