40048 + Interview Questions in Physics in Class 11

1.	Two particles of masses 1.0 Kg and 2.0 Kg are placed at a seperation of 50 cm. Assuming that only gravitational forces acting on the particles mutually, the initial acceleration of the first particle.
Answer» Solution :Gravitational force between the two particles `F=(Gm_1m_2)/r^2` `F=(6.67xx10^(-11) XX 1xx2)/(0.5)^2 = 5.3xx10^(-10)`N The acceleration of 1.0 Kg PARTICLE is `a_1=F/m_1=(5.3xx10^(-10))/1=5.3xx10^(-10) m//s^2` It is towards the 2.0 kg particle.

Discussion

2.	2 moles of an ideal monoatomic gas undergoes a cyclic process ABCA as shown in the figure. R is the univers l gas constant. ("givenln 2"=0.693) Answer the following questions Percentage efficiency of the cycle is (approximately)
Answer» `10.38%` `13.2%` `40.38%` `25.2%` ANSWER :B

Discussion

3.	In a human pyramid in a circus, the entire weight of the balanced group is supported by the legs of a performer who is lying on his back. The combined mass of all the persons performing the act, and the tables, plaques etc. involved is 280 kg. The mass of the performer lying on his back at the bottom of the pyramid is 80 kg. Each thighbone (femur) of this performer has a length of 50 cm and an effective radius of 2.0 cm. Determine the amount by which each thighbone gets compressed under the extra load. (g=9.8 ms^(-2)) Young's Modulus for bone Y =9.4 xx 10 ^(9) Nm ^(-2)
Answer» Solution :COMPRESSION of bone `DELTA L = 4.15 XX 10 ^(-5) m`

Discussion

4.	Select the correct alternative(s)
Answer» work DONE by static friction is always zero work done by kinetic friction can be POSITIVE also kinetic energy of a system cannot be INCREASED without applying any external force on the system work energy theorem is valid in non inertial frames also Answer :B::D

Discussion

5.	Is stress is a vector or scalar or tensor ?
Answer» SOLUTION :TENSOR, because it.s MAGNITUDE is DIFFERENT in different DIRECTION.

Discussion

6.	The coefficient of friction between the tyres and road is 0.4. The minimum distance covered before attaining a speed of 8 ms^(-1) starting from rest is nearly ( take g=10 ms^(-2))
Answer» 8m 4m 10m 16m Solution :(d) Retardation, `a=(MU MG)/(m)=mug=4ms^(-2)` using, `V^(2)=u^(2)+2AS` `(8)^(2)=(0)^(2)+2(4)(s)` `therefore s=8m`

Discussion

7.	For a given acceleration - time graph, there exist ………………………… velocity - timegraph
Answer» 1 2 3 many Answer :D

Discussion

8.	Let A and B the two gases and given T_A/M_A=4 T_B/M_B where T is the temperature and M is molecular mass. If v_A and v_B are the r.m.s speed then the ration v_A/v_B will be equal to
Answer» 2 4 1 0.5 Answer :A

Discussion

9.	An increase in pressure of 100 kPa causes a certain volume of water to decrease by 0.005% of its original volume . (a) Calculate the bulk modulus of water ? (b) Compute the speed of sound (compressional waves) in water ?
Answer» Solution :Bulkmodulus ` B=v \|(Delta p)/( Delta v)\| = ( 100 xx10^3 )/( 0.005 xx 10^(-2))` ` B= 2000Mpa` (b) ` V=sqrt((B)/( RHO)) = sqrt(( 2000xx 10^(6) )/( 1000))` ` V = 1414 ms^(-1)`

Discussion

10.	The pair conatining a scalar quantity and vector quantity is
Answer» Impulse and Angular momentum Work and FREQUENCY ELECTROMOTIVE FORCE and force Electric POWER and Energy Answer :C

Discussion

11.	A body weighs 90 kg on the surface of the earth. How much will it weighs on the surface of mars whose mass is 1/9 and the radius is 1/2 of that of the earth.
Answer» `r^6` `r^4` `r^2` `r^-2` ANSWER :B

Discussion

12.	The period of a piston in an engine, moving simple harmonically is 2 s. A body of mass 10 kg is placed on the piston. Calculate the maximum amplitude of the piston such that the mass is not thrown out from the platform.
Answer» SOLUTION :`MG = momega^2 a , a = g//4pi^2n^2xx(0.5)^2=0.99` SECOND.

Discussion

13.	The mean radius of the earth.s orbitaround the sun is 1.5 xx 10^(11)m and that of the orbit of mercury is 6 xx 10^(10)mThe mercury will revolve around the sun in nearly
Answer» `SQRT((2)/(5))` YR `(2)/(5)` yr `((2)/(5))^(2)` yr `((2)/(5))^(3//2)` yr ANSWER :D

Discussion

14.	The mean radius of the earth.s orbitaround the sun is 1.5 xx 10^(11)m and that of the orbit of mercury is 6 xx 10^(10)m The ratio of the orbital of mercury to that of the earth is (assumig orbits to be circular )
Answer» `SQRT((10)/(4))` `(4)/(sqrt(10))` `2sqrt(10)` `(1)/(2)sqrt(10)` ANSWER :A

Discussion

15.	A bob of mass M is hung using a string of length 2. A mass m moving with a velocity u pierces through the hot and emerges out with velocity u/3 horizontally. The frequency of small oscillations of the bob, considering A as amplitude is,
Answer» `1/(2pi) sqrt((3 m u)/(2MA))` `1/(2pi) sqrt((3 m)/(3MA))` `1/(2pi) ((2 m u)/(3 MA))` `1/(2pi)((3 m u)/(2 M A))` Answer :C

Discussion

16.	State with reason whether Pascal's law is applicable to the water in a pond.
Answer» SOLUTION :Pascal.s LAW is not applicable to the WATER in a pond. The law is applicable only in the CASE of confined fluids. As a pond.s water is not confined, the law cannot be APPLIED here.

Discussion

17.	An experimenter measured the diameter of a wire without noting zero error. This error is
Answer» RANDOM errors Systematic error Gross error Personal error Answer :B

Discussion

18.	The ratio of the accelerations for a solid sphere (mass .m. and radius .R.) rolling down and incline of angle or without slipping and slipping down the incline without rolling is
Answer» `2:3` `2:5` `7:5` `5:7` ANSWER :D

Discussion

19.	A hole is drilled in a copper sheet. The diameter of the hole is4.24 " cm at " 27.0 ^(@) C. What is the change in the diameter of the hole when the sheet is heated to227^(@) C ? Coefficient of Imear expansion of copper = 1.70 xx 10^(-5) K^(-1).
Answer» Solution :The diameter INCREASES by an amount ` = 1.44 xx 10^(-2) CM`.

Discussion

20.	Assertion Pressure of a gas id given as p=2/3E. Reason In the above expession, E represnts kinetic energy of the gas per unit volume.
Answer» If both Assertion and REASON are CORRECT and Reason is the correct explanation of Assertion. If both Assertion and Reason are correct but Reason is not the correct explation OS Assertion. If Assertionis true bur Reason is false. If Assertion is false but Reason is true. Solution :E REPRESENTS translational kinetic energy per unit volume.

Discussion

21.	The velocity of a body is 20 m/s making an angle of 30^(@) with the horizontal, the vertical component of velocity is
Answer» 20m/s 17.32m/s 10m/s 7m/s Answer :C

Discussion

22.	The molar specific heat at constant pressure of an ideal gas is (7//2)R. The ratio specific heats at constant pressure to that at constant volume is ………. .
Answer» `8//7` `5//7` `9//7` `7//5` SOLUTION :`C_(P)=(7)/(2)R, C_(V)=(7)/(2)R-R=(5)/(2)R, gamma=(C_(P))/(C_(V))=(7)/(5)`

Discussion

23.	“ Velocity can not be added to temperature".Check the dimensional correctness of the equation PV = Fx where P is the pressure, V is volume, F is force and x is displacement
Answer» Solution :`[P]=[ML^-1],[V]=[L^3][F]=[MLT^-2],[x]=[L][PV]=[ML^2T^-2]=[Fx]` So the EQUATION is DIMENSIONALLY CORRECT.

Discussion

24.	A body of mass 100 kg is moving with an acceleration of 50 cm s^(-2). Calculate the force experienced by it.
Answer» SOLUTION :Mass m = 100 kg Acceleration a = 50 cm s 2 = `0.5 MS^(-2)` Using newton.s SECOND law ` F = 100 kg xx 0.5 ms^(-2) = 50N`

Discussion

25.	Why do we use a wrench of long arm to unscrew a unit tightly fitted to a bolt?
Answer» Solution :Unscrewing a nut means a rotation about the axis of the nut. Application of a higher MOMENT of force will FACILITATE this rotation. If the force applied remains the same, the moment of force is higher when the arm is longer. So we USE a wrench of long arm to unscrew a nut tightly fitted to a BOLT.

Discussion

26.	If the length and breadth of a thin rectangular sheet are measured, using a metre scale as 16.2 cm and 10.1 cm respectively. What is the area of the rectangular sheet.
Answer» SOLUTION :There are THREE significant figures in each measurement. It means that the length l may be WRITTEN as `l= 16.2 +- 0.1cm= 16.2 cm +- 0.6%` Similarly, the BREADTH b may be written as `b= 10.2 +- 0.1cm= 10.1 cm +- 1%` Then, the error of the PRODUCT of two (or more) experimental values, using the combination of errors rule, will be `lb= 163.62 cm^(2) +- 1.6% - 163.62 +- 2.6cm^(2)` This leads use to quote the final result as `lb= 164 +- 3 cm^(2)` Here `3cm^(2)` is the uncertainty or error in the estimation of area of rectangular sheet.

Discussion

27.	Two metre scales, one of steel and the other of aluminium, agree at 20^C. Calculate the ratio aluminium-centimetre/steel-centimeter at (a) 0^C, (b) 40^C and (c) 100^C. alpha for steel = 1.1 xx 10^(-5) o^C(-1) and for aluminium =2.3 xx 10^(-5) 0^C(-1).
Answer» Solution :`L_st=L_al at 20^0C` `ALPHA _al= 2.3xx10^-5/^0C` `alpha _st =1.1xx 10^-5/^0C` so `L_0st(1-alpha_st xx 20)` `=L_0al(1-alpha_al xx20)` (a) `L_0st/L_0al= (1-alpha_al xx 20)/(1-alpha_st xx20 )` `= (1-2.3xx 10^-5xx 20)/ (1-1.1xx10^-5xx20)` ` 0.99954/0.99978=0.999759` (b) ` L_40Al/L_40st=L_0Al(1+alpha_al xx 40)/(L_0st(1+alpha_st xx 40)` `RARR `L_40Al/L_40st=L_0Al/L_0st xx (1+2.3xx 10^-5 xx 40)/(1+1.1xx 10^5 xx 40)` `=0.99977xx1.00092/1.00044 = 1.0002496` (c) `L_100Al/L_100st=L_0Al(1+alpha_Al xx 100)/L_0st(1+alpha_st xx 100)` `=0.99977xx 1.0023/1.0023=1.00096`

Discussion

28.	Let vec(F ) be the force acting on a particle having position vector vec(r ) and vec(tau) be the torque of this force about the origin. Then
Answer» `vec(R ).vec(F)=0 and vec(r ).vec(TAU) NE 0` `vec( r).vec(tau) ne 0 and vec(F).vec(tau)= 0` `vec(r ).vec(tau) ne - and vec(F).vec(tau) ne-` `vec(r ).vec(tau) = 0 and vec(F).vec(tau)= 0` Answer :D

Discussion

29.	A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum of radius 3 m rotating about its vertical axis with 200 rev/min. The coefficient of friction between the wall and his clothing is 0.15. What is the minimum rotational speed of the cylinder to enable the man to remain stuck to the wall (without falling) when the floor is suddenly removed ?
Answer» Solution :Radiusof drumr= 3m `epsilon = 200(rev )/( MIN)` `=(400 pi)/( 60)= (20pi)/(3 ) ` `MU= 0.15` Asshownin figurethe normalreaction(n ) ofthe wall on themanactshorizontaldirectionactverticallyupwareds therequiredcentripetalforce will beprovidedby horizontalreactionN ofthe wallon man `N= (mv^(2))/( r ) = (m(repsilon)^(2))/( r )` Ifweigth of man`(mg ) LE ` limitingfrictionmanremainstuckto wallafterflooris removed`mg le mu m pi epsilon ^(2)` Minimumangular ROTATIONAL speedrequired `epsilon _(min)= sqrt((g )/( mu r))` `=4.67 rads^(-1)` `=5 rads^(-1)`

Discussion

30.	Two forcesof magnitudes 30, 60 and Pnewtonacting at apoint are in equilibrium. If the angle betweenthe firsttwo is 60 ^(@) , thevalue of P is :
Answer» `(mv)/(sqrt(2))` 2 mv `sqrt(2)mv` `sqrt(2)/(mv)` SOLUTION :`P= sqrt( 60^(2) + 30^(2) + 2.60.30 cos60^(@))`

Discussion

31.	The amplitude of a system moving inshm is doubled . Determine the change in (a) total energy (b) the maximum speed (c) the maximum acceleration and (d) the period .
Answer» ANSWER :(a)quadrupled (b) DOUBLED (C) doubled (d) no change

Discussion

32.	A block of mass m slides down on a wedgeof mass M as shown infigure .Let a_(1) be the asseleration of the acceleration of and a_(2) the the acceleration od block 1N_(1) is the normal reaction between block and wedge and N_(2) the normal reaction between wedge and gound .frication is absent everwhere .Select the correct alternative(s)
Answer» `N_(2)lt(M+m)g` `N_(2)LTM(g COS theta-\|a_(1)\|SINTHETA)` `N_(1)sin theta=M\|a_(1)\|` `ma_(2)=-Ma_(1)` Answer :a,b,c

Discussion

33.	The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second overtone of an organ pipe open at both the ends. The length of organ pipe open at both the ends is :
Answer» 80 CM 100 cm 120 cm 140 cm Solution :For closed pipe, fundamental frequency is `f _(1) = (v)/(4L)` For open pipe, secon overtone `= f _(3) = (3v)/(2L.)` Here it is given that `f _(1) =f _(3)` `therefore (v )/(4L)=(3v)/( 2L.) implies L. = 6L = 6 xx 20 = 120 cm`

Discussion

34.	Hydrostatic pressure is a scalar quantity even though pressure is force divided by area.
Answer» SOLUTION :DUE to applied force on liquid , the pressure is TRANSMITTED equally in all DIRECTIONS INSIDE the liquid . That is why there is no fixed direction for the pressure due to liquid . Hencehydrostastic pressure is a scalar quantity.

Discussion

35.	A pitot tube is mounted in a main pipe of diameter 40 cm. If the difference in pressure indicated by the gauge ie 6cm of water column, calculate the volume of air passing through the main pipe in two minutes.
Answer» <P> Solution :GIVEN, `r=(40 cm)/(2) =20 cm =0.2 m` `h=6cm =0.06m` The given situation is shown below: At A, the plane of aperture is parallel to the direction of air flow, so velocity of air flow at A in the pipe (say v). At B, the stane of aperture is perpendicular to the direction of air flow. So, velocity of air entering the tube is reduced to zero. Applying Bernoulli.s THEOREM at points A and B, we get `p_(A)+1/2 pv_(A)^(2)=p_(B)+1/2 pv_(B)^(2)` Here,` v_(A)=v and v_(B)=0` `1/2 pv^(2)=p_(B)-p_(A)-HPG` (U-tube contains water) `rArr v=sqrt(2gh) =sqrt(2 xx 9.8 xx 0.06) [therefore h=0.06m]` =1.08m/s Volume of air flowing per second, `Q=av=pir^(2) v` `=3.14 xx (0.2)^(2) xx 0.832` `=0.1045m^(3)//s` Volume of air passing in 2 mins is `v=Qt=0.1045 xx 2 xx 60` `=12.54 m^(3)`

Discussion

36.	A body is projected with an initial Velocity 20 m/s at 60° to the horizontal. Its velocity after 1 sec is
Answer» `10 I + 7.32 j` `10i - 7.32 j` `10i + SQRT(3)j` `10i - sqrt(3)j` Answer :A

Discussion

37.	Two rods A and B of same area of cross-section are joined together end to end The free end of the rod A is kept in melting ice at 300 K and free end of B rod at 400 K. The rods are of the same length. The conductivity of A is 3 times that of B. Calculate the temperature of the junction of the rods.
Answer» Solution :`KA (400 - theta) // l = 3K XX A ( theta - 300) // l, theta = 375 "K"`

Discussion

38.	If two soap bubbles of different radii are connected by a tube, then
Answer» AIR flows from BIGGER to the SMALLER bubble TILL the sizes becomes equal air flows bigger bubble to the smaller bubble till the size are interchanged air flows from the smaller bubble to the bigger there is number FLOW of air Answer :C

Discussion

39.	A body is thrown horizontally from the top of a tower of 5m height. It touches the ground at a distance of 10 m from the foot of the tower. Then initial velocity of the body is (g = 10 ms^(-2))
Answer» `2.5 MS^(-1)` `5 ms^(-1)` `10 ms^(-1)` `20 ms^(-1)` ANSWER :C

Discussion

40.	A torque of 10 Nm is applied to a flywheel of mass 5 kg and radius of gyration 0.6 m. What is the resultant angular acceleration ?
Answer» SOLUTION :Torque = `tau = 10 NM` Mass =m = 5kg Radius of GYRATION = K = 0.6 m Angular acceleration `=alpha`=? `tau = Ialpha = MK^(2)alpha, alpha = tau/(mK^(2)) = 10/(5 xx 0.6^(2)) = 5.5 "rad"//s^(2)`

Discussion

41.	The scalar product of force and displacement gives work. It can be nagative, zero or positive The work done in sliding a load is ……….with respect to frictional force. (zero,positive, nagative,infinity)
Answer» SOLUTION :NEGATIVE

Discussion

42.	A circular disc of radius R is removed from a bigger circular disc of radius 2R such that the circumferences of the discs touch. The centre of mass of the new disc is at a distance aR from the centre of the bigger disc. The value of a is
Answer» `1//3` `1//2` `1//6` `1//4` ANSWER :A

Discussion

43.	If gravitation of Earth becomes invisiblesuddenly, then mass and weight of object become zero.
Answer» ANSWER :FALSE, only WEIGHT BECOMES ZERO.

Discussion

44.	AB is a cylinder of length 1.0m fitted with a thin flexible diaphragm C at the middle and two others thin portions AC and BC contains hydrogen and oxygen gases , respectively . The diaphragms A and B are set into vibrations of same frequency . What is the minimum frequency of these vibrations for which the diaphragm C is a node ? Under the conditions of the experiment , the velocity of sound in hydrogen is 1100 m//s and in oxygen is 300 m//s.
Answer» SOLUTION :When diaphragms `A` and `B` are set in oscillations , ANTINODES are formed at `A` and `B` while a node is formed at `C` ( given) Also `AB = 1.0 m` and ` AC = CB = l (say) = 1//2 = 0.5 m` The portions `AC and BC` behave as closed pipes . In a closed pipe , the modes of vibrations are given by `l =(lambda)/(4) , ( 3lambda)/(4), ( 5 lambda)/(4) , ....` i.e., ` l= ( 2 r + 1) (lambda)/( 4) , r = 0 , 1 , 2 , 3 ,...` or ` lambda = ( 4l)/(2 r + 1) r = 0 , 1 , 2, 3 ,....` Forhydrogen ` lambda_(1) = 4l//( 2 r_(1) + 1)` For oxygen ` lambda_(2) = 4 l//( 2r_(2) + 1)` In both gases the frequency is same As ` n_(1) = n_(2)` or `(v_(1))/( lambda_(1)) = (v_(2))/(lambda_(2))` `(v_(1))/(v_(2)) = (lambda_(1))/( lambda) = (l_(1))/(l_(2)) XX (( 2 r_(2) + 1))/(( 2 r_(1) + 1))` As `l_(1) = l_(2) = 0.5 m` i.e., ` (v_(1))/( v_(2)) =( 2 r_(2) + 1) /( 2 r_(1) + 1)` ` = (1100)/(300) = ( 2r_(2) + 1)/( 2 r_(1) + 1)` i.e., `( 2 r_(1) + 1)/( 2 r_(2) + 1) = (3)/(11)` For minimum frequency , the integer`r_(1) and r_(2)` should be least . Therefore by the inspection ` r_(1) = 1 and r_(2) = 5` Therefore , the frequency of oscillations is given by `n_(min) = (v_(1))/( lambda_(1)) = ( 2 r_(1) + 1) ( v_(1))/( 4 l)` `= ( 2xx 1 + 1) xx ( 1100)/(4 xx 0.5) = ( 3 xx 1100)/(2) = 1650 HZ` i.e., `( 2 r_(1) + 1)/( 2 r_(2) + 1) = (3)/(11)` For minimum frequency , the INTEGERS `r_(1) and r_(2)`should be least. Therefore by inspection `r_(1) = 1and r_(2) = 5` Therefore , the frequency of oscillations is given by `n_(min) = (v_(1))/( lambda_(1)) = ( 2 r_(1) + 1) v_(1)/( 4 l)` ` = ( 2 xx 1 + 1) xx ( 1100)/( 4 xx 0.5) = ( 3 xx 1100)/(2) = 1650 Hz`

Discussion

45.	Write the law of conservation of angular momentum.
Answer» Solution :The time rate of the total angular momentum of a SYSTEM of particles about a point (taken as the origin of frame of reference) is equal to the sum of the external torque `therefore (dvecL)/(dt)=vectau_(("ext"))` If `vectau_(("ext"))=0" then "(dvecL)/(dt)=0` `therefore dvecL=0`,so `vecL` = constant Law of conservation of angular momentum : ..If the RESULTANT external torque on the system is zero, then its angular moment remains constant... Here `vecL` = constant, is equivalent to three scalar equations `L_(X)=K_(1),L_(y)=K_(2)andL_(Z)=K_(3)` Here `K_(1),K_(2)andK_(3)` are constant, `L_(x),L_(y)andL_(z)` are the components of the total angular momentum `vecL` ALONG X, Y and Z axes respectively. The total angular momentum is conserved means that each of these components is conserved.

Discussion

46.	Two waves y_1 = A sin (omegat - kx) andy_2 = A sin (omegat + kx) superimpose to produce a stationary wave, then
Answer» `x =0` is a node `x = 0` is an antinode. `x= pi/k` is a node. `pi = (2PI)/k` is an antinode SOLUTION :`y= y_1 + y_2 = (2A cos kx) SIN omegat ` `=A_(x) sin omegat ` Here, `A_x = 2A cos kx` At`x=0 , A_x` is maximum or `2A`. So, it is an antinode. Next antinode will occur at `x = LAMBDA/2, lambda` ………….etc ` or ` x = pi/ k , (2pi)/k` ..........etc. `

Discussion

47.	A boat travels between two points and B on the banks of a river along live AB, Distance between A and B is 1200m. Velocity of river water is 1.9ms^(-1). Line AB makes alpha=60^(0) with direction of water folw . With what velocity and at what angle beta boat must move to cover AB and back in 5 minutes? Angle beta remains the same from A to B an while moving from B to A
Answer» ANSWER :`8MS^(-1),beta=12^(0)`

Discussion

48.	Which is the important physical quantity required for the description of any force field ?
Answer» SOLUTION :POTENTIAL

Discussion

49.	At which of the following temperatures, the value of surface tension of water is minimum ?
Answer» `4^@C` `25^@C` `50^@C` `75^@` ANSWER :D

Discussion

50.	A ball is projected vertically down with a velocity of 10sqrt(3) m//s from a height of 20 m. On hitting the ground if it loses 40 % of its energy, the height to which it bounces is (g = 10 ms^(-2))
Answer» 20 m 30 m 19 m 21 m Answer :D

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Two particles of masses 1.0 Kg and 2.0 Kg are placed at a seperation of 50 cm. Assuming that only gravitational forces acting on the particles mutually, the initial acceleration of the first particle.

2 moles of an ideal monoatomic gas undergoes a cyclic process ABCA as shown in the figure. R is the univers l gas constant. ("givenln 2"=0.693) Answer the following questions Percentage efficiency of the cycle is (approximately)

Select the correct alternative(s)

Is stress is a vector or scalar or tensor ?

The coefficient of friction between the tyres and road is 0.4. The minimum distance covered before attaining a speed of 8 ms^(-1) starting from rest is nearly ( take g=10 ms^(-2))

For a given acceleration - time graph, there exist ………………………… velocity - timegraph

Let A and B the two gases and given T_A/M_A=4 T_B/M_B where T is the temperature and M is molecular mass. If v_A and v_B are the r.m.s speed then the ration v_A/v_B will be equal to

An increase in pressure of 100 kPa causes a certain volume of water to decrease by 0.005% of its original volume . (a) Calculate the bulk modulus of water ? (b) Compute the speed of sound (compressional waves) in water ?

The pair conatining a scalar quantity and vector quantity is

A body weighs 90 kg on the surface of the earth. How much will it weighs on the surface of mars whose mass is 1/9 and the radius is 1/2 of that of the earth.

The period of a piston in an engine, moving simple harmonically is 2 s. A body of mass 10 kg is placed on the piston. Calculate the maximum amplitude of the piston such that the mass is not thrown out from the platform.

The mean radius of the earth.s orbitaround the sun is 1.5 xx 10^(11)m and that of the orbit of mercury is 6 xx 10^(10)mThe mercury will revolve around the sun in nearly

The mean radius of the earth.s orbitaround the sun is 1.5 xx 10^(11)m and that of the orbit of mercury is 6 xx 10^(10)m The ratio of the orbital of mercury to that of the earth is (assumig orbits to be circular )

A bob of mass M is hung using a string of length 2. A mass m moving with a velocity u pierces through the hot and emerges out with velocity u/3 horizontally. The frequency of small oscillations of the bob, considering A as amplitude is,

State with reason whether Pascal's law is applicable to the water in a pond.

An experimenter measured the diameter of a wire without noting zero error. This error is

The ratio of the accelerations for a solid sphere (mass .m. and radius .R.) rolling down and incline of angle or without slipping and slipping down the incline without rolling is

A hole is drilled in a copper sheet. The diameter of the hole is4.24 " cm at " 27.0 ^(@) C. What is the change in the diameter of the hole when the sheet is heated to227^(@) C ? Coefficient of Imear expansion of copper = 1.70 xx 10^(-5) K^(-1).

Assertion Pressure of a gas id given as p=2/3E. Reason In the above expession, E represnts kinetic energy of the gas per unit volume.

The velocity of a body is 20 m/s making an angle of 30^(@) with the horizontal, the vertical component of velocity is

The molar specific heat at constant pressure of an ideal gas is (7//2)R. The ratio specific heats at constant pressure to that at constant volume is ………. .

“ Velocity can not be added to temperature".Check the dimensional correctness of the equation PV = Fx where P is the pressure, V is volume, F is force and x is displacement

A body of mass 100 kg is moving with an acceleration of 50 cm s^(-2). Calculate the force experienced by it.

Why do we use a wrench of long arm to unscrew a unit tightly fitted to a bolt?

If the length and breadth of a thin rectangular sheet are measured, using a metre scale as 16.2 cm and 10.1 cm respectively. What is the area of the rectangular sheet.

Two metre scales, one of steel and the other of aluminium, agree at 20^C. Calculate the ratio aluminium-centimetre/steel-centimeter at (a) 0^C, (b) 40^C and (c) 100^C. alpha for steel = 1.1 xx 10^(-5) o^C(-1) and for aluminium =2.3 xx 10^(-5) 0^C(-1).

Let vec(F ) be the force acting on a particle having position vector vec(r ) and vec(tau) be the torque of this force about the origin. Then

Two forcesof magnitudes 30, 60 and Pnewtonacting at apoint are in equilibrium. If the angle betweenthe firsttwo is 60 ^(@) , thevalue of P is :

The amplitude of a system moving inshm is doubled . Determine the change in (a) total energy (b) the maximum speed (c) the maximum acceleration and (d) the period .

The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second overtone of an organ pipe open at both the ends. The length of organ pipe open at both the ends is :

Hydrostatic pressure is a scalar quantity even though pressure is force divided by area.

A pitot tube is mounted in a main pipe of diameter 40 cm. If the difference in pressure indicated by the gauge ie 6cm of water column, calculate the volume of air passing through the main pipe in two minutes.

A body is projected with an initial Velocity 20 m/s at 60° to the horizontal. Its velocity after 1 sec is

Two rods A and B of same area of cross-section are joined together end to end The free end of the rod A is kept in melting ice at 300 K and free end of B rod at 400 K. The rods are of the same length. The conductivity of A is 3 times that of B. Calculate the temperature of the junction of the rods.

If two soap bubbles of different radii are connected by a tube, then

A body is thrown horizontally from the top of a tower of 5m height. It touches the ground at a distance of 10 m from the foot of the tower. Then initial velocity of the body is (g = 10 ms^(-2))

A torque of 10 Nm is applied to a flywheel of mass 5 kg and radius of gyration 0.6 m. What is the resultant angular acceleration ?

The scalar product of force and displacement gives work. It can be nagative, zero or positive The work done in sliding a load is ……….with respect to frictional force. (zero,positive, nagative,infinity)

A circular disc of radius R is removed from a bigger circular disc of radius 2R such that the circumferences of the discs touch. The centre of mass of the new disc is at a distance aR from the centre of the bigger disc. The value of a is

If gravitation of Earth becomes invisiblesuddenly, then mass and weight of object become zero.

Write the law of conservation of angular momentum.

Two waves y_1 = A sin (omegat - kx) andy_2 = A sin (omegat + kx) superimpose to produce a stationary wave, then

Which is the important physical quantity required for the description of any force field ?

At which of the following temperatures, the value of surface tension of water is minimum ?

A ball is projected vertically down with a velocity of 10sqrt(3) m//s from a height of 20 m. On hitting the ground if it loses 40 % of its energy, the height to which it bounces is (g = 10 ms^(-2))