Two waves y_1 = A sin (omegat - kx) andy_2 = A sin (omegat + kx) superimpose to produce a stationary wave, then

Two waves y_1 = A sin (omegat - kx) andy_2 = A sin (omegat + kx) su

1.	Two waves y_1 = A sin (omegat - kx) andy_2 = A sin (omegat + kx) superimpose to produce a stationary wave, then
Answer» `x =0` is a node `x = 0` is an antinode. `x= pi/k` is a node. `pi = (2PI)/k` is an antinode SOLUTION :`y= y_1 + y_2 = (2A cos kx) SIN omegat ` `=A_(x) sin omegat ` Here, `A_x = 2A cos kx` At`x=0 , A_x` is maximum or `2A`. So, it is an antinode. Next antinode will occur at `x = LAMBDA/2, lambda` ………….etc ` or ` x = pi/ k , (2pi)/k` ..........etc. `