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The coefficient of friction between the tyres and road is 0.4. The minimum distance covered before attaining a speed of 8 ms^(-1) starting from rest is nearly ( take g=10 ms^(-2)) |
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Answer» 8m using, `V^(2)=u^(2)+2AS` `(8)^(2)=(0)^(2)+2(4)(s)` `therefore s=8m` |
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