1.

The coefficient of friction between the tyres and road is 0.4. The minimum distance covered before attaining a speed of 8 ms^(-1) starting from rest is nearly ( take g=10 ms^(-2))

Answer»

8m
4m
10m
16m

Solution :(d) Retardation, `a=(MU MG)/(m)=mug=4ms^(-2)`
using, `V^(2)=u^(2)+2AS`
`(8)^(2)=(0)^(2)+2(4)(s)`
`therefore s=8m`


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