1.

Two rods A and B of same area of cross-section are joined together end to end The free end of the rod A is kept in melting ice at 300 K and free end of B rod at 400 K. The rods are of the same length. The conductivity of A is 3 times that of B. Calculate the temperature of the junction of the rods.

Answer»


Solution :`KA (400 - theta) // l = 3K XX A ( theta - 300) // l, theta = 375 "K"`


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