A torque of 10 Nm is applied to a flywheel of mass 5 kg and radius of gyration 0.6 m. What is the resultant angular acceleration ?

A torque of 10 Nm is applied to a flywheel of mass 5 kg and radius of

1.	A torque of 10 Nm is applied to a flywheel of mass 5 kg and radius of gyration 0.6 m. What is the resultant angular acceleration ?
Answer» SOLUTION :Torque = `tau = 10 NM` Mass =m = 5kg Radius of GYRATION = K = 0.6 m Angular acceleration `=alpha`=? `tau = Ialpha = MK^(2)alpha, alpha = tau/(mK^(2)) = 10/(5 xx 0.6^(2)) = 5.5 "rad"//s^(2)`