1.

Two particles of masses 1.0 Kg and 2.0 Kg are placed at a seperation of 50 cm. Assuming that only gravitational forces acting on the particles mutually, the initial acceleration of the first particle.

Answer»

Solution :Gravitational force between the two particles
`F=(Gm_1m_2)/r^2`
`F=(6.67xx10^(-11) XX 1xx2)/(0.5)^2 = 5.3xx10^(-10)`N
The acceleration of 1.0 Kg PARTICLE is
`a_1=F/m_1=(5.3xx10^(-10))/1=5.3xx10^(-10) m//s^2`
It is towards the 2.0 kg particle.


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