This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 28001. |
Which of the following is greater than \(15 \dfrac{2}{3} \ ?\)1. \(\dfrac{43}{5}\)2. \(\dfrac{20}{2}\)3. \(\dfrac{49}{4}\)4. \(\dfrac{49}{3}\) |
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Answer» Correct Answer - Option 4 : \(\dfrac{49}{3}\) Given: Number = \(15 \dfrac{2}{3} \ \)= 47/3 Concept Used: For 2 numbers a/b, c/d If a × d > b × c, then a/b > c/d Calculations: Checking option (1), we get Numbers = 47/3, 43/5 Now, 47 × 5 = 235 3 × 43 = 129 235 > 129 ⇒ 47/3 > 43/5 Similarly, Checking option (2), we get Numbers = 47/3, 20/2 Now, 47 × 2 = 94 3 × 20 = 60 94 > 60 ⇒ 47/3 > 20/2 Similarly, Checking option (3), we get Numbers = 47/3, 49/4 Now, 47 × 4 = 188 3 × 49 = 147 188 > 147 ⇒ 47/3 > 49/4 Similarly, Checking option (4), we get Numbers = 47/3, 49/3 Now, 47 × 3 = 141 3 × 49 = 147 141 < 147 ⇒ 47/3 < 49/3 ∴ The number greater than 47/3 is 49/3. |
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| 28002. |
What is the greatest length x such that \(3 \dfrac{1}{2}\) m and \(8 \dfrac{3}{4}\) m are integral multiplies of x?1. \(1 \dfrac{1}{2} \ m\)2. \(1 \dfrac{1}{3} \ m\)3. \(1 \dfrac{1}{4} \ m\)4. \(1 \dfrac{3}{4} \ m\) |
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Answer» Correct Answer - Option 4 : \(1 \dfrac{3}{4} \ m\) Formula used : HCF = Highest Common Factor HCF of fraction = (HCF of numerator/LCM of denominator) Calculations : For finding the HCF first convert mixed fraction to simple fraction ⇒ \(3\frac{1}{2}\;=\;\frac{7}{2}\) and \(8\frac{3}{4}\;=\;\frac{35}{4}\) Now HCF of 7/2 and 35/4 For numerator, HCF of 7 and 35 = 7 For denominator, LCM of 2 and 4 = 4 Fraction = 7/4 = \(1\dfrac{3}{4}\) So, x = \(1\dfrac{3}{4}\) (x is the greatest such length or HCF) ∴ The value of x will be \(1\dfrac{3}{4}\)m. |
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| 28003. |
The LCM of two numbers is 2400. Which of the following CANNOT be their HCF?(a) 300(b) 400(c) 500(d) 600 |
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Answer» Correct option is: (c) 500 |
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| 28004. |
If cube root of x is equal to square root of y then the relation between x and y is1. x3 = y22. x = y3. x5 = y64. x2 = y3 |
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Answer» Correct Answer - Option 4 : x2 = y3 Given: cube root of x is equal to the square root of y Calculation: A/Q ∛(x) = √(y) Take the power 6 on both the sides x(6/3) = y(6/2) x2 = y3 |
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| 28005. |
Find the cube root of 531441.1. 812. 913. 714. 895. None of these. |
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Answer» Correct Answer - Option 1 : 81 Concept used:- Trick to find cube root of a number. Method and Calculation:- • Find the unit digit of cube root by looking at unit digit of given number. For cube root of 531441, unit digit must be 1 (13 is 1) • Find other digit(s) by ignoring the last three digits of number and looking at remaining digits. 512 < 531 < 729 (512 and 729 are cubes of 8 and 9, so remaining part of cube root will be 8) Hence, 81 is our answer. |
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| 28006. |
Find the cube root of 5832.1. 182. 283. 164. 385. None of these. |
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Answer» Correct Answer - Option 1 : 18 Concept used:- Trick to find cube root of a number. Method and Calculation:- • Find the unit digit of cube root by looking at unit digit of given number. For cube root of 5832, unit digit must be 8 (83 is 512) • Find other digit(s) by ignoring the last three digits of number and looking at remaining digits. 1 < 5 < 8 (1 and 8 are cubes of 1 and 2, so remaining part of cube root will be 1) Hence, 18 is our answer |
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| 28007. |
Find the cube root of 74088000.1. 4202. 3203. 484. 5205. None of these. |
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Answer» Correct Answer - Option 1 : 420 Concept used:- Trick to find cube root of a number. Method and Calculation:- • Strike out last three zeros from number and put 1 zero at the end oc answer derived from remaining number • Find the unit digit of cube root by looking at unit digit of truncated number. For cube root of 74088, unit digit must be 2 (23 is 8) • Find other digit(s) by ignoring the last three digits of truncated number and looking at remaining digits. 64 < 74 < 125 (64 and 125 are cubes of 4 and 5, so remaining part of cube root will be 4) Hence, 420 is our answer (zero is added to final answer) |
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| 28008. |
Find the cube root of 85184.1. 442. 343. 544. 485. None of these. |
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Answer» Correct Answer - Option 1 : 44 Concept used:- Trick to find cube root of a number. Method and Calculation:- • Find the unit digit of cube root by looking at unit digit of given number. For cube root of 85184, unit digit must be 4 (43 is 64) • Find other digit(s) by ignoring the last three digits of number and looking at remaining digits. 64 < 85 < 125 (64 and 125 are cubes of 4 and 5, so remaining part of cube root will be 4) Hence, 44 is our answer |
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| 28009. |
The sum of three numbers is 264 if the first number be twice the second and third number be one-third of the first, then the second number is1. 482. 723. 544. 64 |
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Answer» Correct Answer - Option 2 : 72 Given: Sum of 3 numbers is 264 The first number is twice 2nd & 3 times the 3rd Calculations: Ratio of number = 1 : ½ : ⅓ = 6 : 3 : 2 So, Let the numbers be 6x, 3x & 2x According to the question 6x + 3x + 2x = 264 ⇒ 11x = 264 ⇒ x = 24 Second number = 3x = 3 × 24 = 72 ∴ The correct choice is option 2. |
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| 28010. |
Answer these questions based on the following information. There are 250 integers a1, a2,… a250, not all of them necessarily different. Let the greatest integer of these 250 integers be referred to as Max, and the smallest integer be referred to as Min. The integers a1 through a124 form sequence A and the rest form sequence B. Each member of A is less than or equal to each member of B.Every element of A is made greater than or equal to every clement of B by adding to each element of A an integer x. Then, x cannot be less than: (a) 210 (b) the smallest value of B (c) the largest value of B (d) (Maximm-Minimum) |
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Answer» Correct option (d) (Maximm-Minimum) Explanation: Since the minimum is in A and the maximum is in B, the value of x cannot be less than Maximum − Minimum. |
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| 28011. |
Answer these questions based on the following information. There are 250 integers a1, a2,… a250, not all of them necessarily different. Let the greatest integer of these 250 integers be referred to as Max, and the smallest integer be referred to as Min. The integers a1 through a124 form sequence A and the rest form sequence B. Each member of A is less than or equal to each member of B.Elements of A are in ascending order, and those of B are in descending order. a124 and a125 are interchanged. Then which of the following statements is true?(a) A continues to be in ascending order. (b) B continues to be in descending order. (c) A continues to be in ascending order and B in descending order. (d) None of the above |
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Answer» Correct option (a) A continues to be in ascending order. Explanation: If elements of A are in ascending order a124 would be the largest value in A. Also a125 would be the largest value in B. On interchanging a124 and a125, A continues to be in ascending order, but B would lose its descending order arrangement since a124 would be the least value in B. |
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| 28012. |
What will be the value of 21/3 x 21/6 x 21/12... to infinity. (a) 22 (b) 22/3 (c) 23/2 (d) 8 |
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Answer» Correct option (b) 22/3 Explanation: The expression can be written as 21/3+1/6+1/12+.… = 2INFINTE SUM OF THE GP = 22/3. |
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| 28013. |
Answer these questions based on the following information. There are 250 integers a1, a2,… a250, not all of them necessarily different. Let the greatest integer of these 250 integers be referred to as Max, and the smallest integer be referred to as Min. The integers a1 through a124 form sequence A and the rest form sequence B. Each member of A is less than or equal to each member of B.All values in A are changed in sign, while those in B remain unchanged. Which of the following statements is true? (a) Every member of A is greater than or equal to every member of B. (b) Max is in A. (c) If all numbers originally in A and B had the same sign, then after the change of sign, the largest number of A and B is in A. (d) None of these |
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Answer» Correct option (d) None of these Explanation: All members of A are smaller than all members of B. In order to visualise the effect of the change in sign in k assume that A is {1, 2, 3...124} and B is {126, 12.7...250}. It can be seen that for this assumption of values neither options (a), (b) or (c) is correct. |
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| 28014. |
Find the infinite sum of the series 1/1 + 1/3 + 1/6 + 1/10 + 1/15 …. (a) 2 (b) 2.25 (c) 3 (d) 4 |
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Answer» Correct option (a) 2 Explanation: If you look for a few more terms in the series, the series is: 1, 1/3, 1/6, 1/10, 1/15, 1/21, 1/28, 1/36, 1/45, 1/55, 1/66, 1/78, 1/91, 1/105, 1/120, 1/136. 1/153 and so on. If you estimate the values of the individual terms it can be seen that the sum would tend to 2 and would not be good enough to reach even 2.25. |
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| 28015. |
The sum of the series 3 × 5 + 5 × 7 + 7 × 9 +…. upto n terms will be: (a) n(4n2 +18n +23)/3(b) n(4n2 +18n +23)/6(c) n(4n2+18n+23)(d) None of these. |
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Answer» Correct option (a) n(4n2 +18n +23)/3 Explanation: Solve this using trial and error. For 1 term the sum should be 15 and we get 15 only from the first option when we put is n = 1. |
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| 28016. |
For the above question 35, what is the sum of the series if taken to infinite terms: (a) 1.1 (b) 1 (c) 14/13 (d) None of these |
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Answer» Correct option (b) 1 Explanation: The sum to infinite terms would tend to 1 because we would get (infinity)/(infinity + 2). |
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| 28017. |
The sum of an infinite G.P. whose common ratio is positive and is numerically less than 1 is 36 and the sum of the first two terms is 32. What will be the third term? (a) 1/3 (b) 4/3 (c) 8 /3 (d) 2 |
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Answer» Correct option (c) 8/3 Explanation: Trying to plug in values we can see that the infinite sum of the GP 24, 8, 8/3... is 36. Hence the third term is 8/3. |
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| 28018. |
X and Y invest Rs. 21,000 and Rs. 17,500 respectively in a business and at the end of the year they make a loss of Rs of 26,400. Find their individual shares of the loss.1. Rs. 12500, Rs. 139002. Rs. 14000, Rs. 124003. Rs. 12000, Rs. 144004. Rs. 13500, Rs. 129005. Rs. 11000, Rs. 15400 |
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Answer» Correct Answer - Option 3 : Rs. 12000, Rs. 14400 Given: X and Y invest Rs 21,000 and Rs 17,500 respectively. Total loss is Rs 26,400. Formula Used: L1 : L2 = I1 × T1 : I2 × T2 Here, L = Loss, I = Investment, T = Time Calculation: X and Y invest Rs. 21,000 and Rs. 17,500 respectively At the end of the year the ratio of loss = 21000 × 1 : 17500 × 1 = 6 : 5 The ratio of loss = 6 : 5 Total loss = 26400 The share loss of X = 6/11 × 26400 = Rs. 14400 The share loss of Y = 5/11 × 26400 = Rs. 12000 ∴ The share loss of X and Y is Rs. 14400 and Rs. 12000. |
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| 28019. |
A seller expects a 32% return on his purchase price. If its sales in one day were 528. What was his profit amount?A. Rs. 120B. Rs. 128C. Rs. 132D. Rs. 1401. A2. B3. C4. D |
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Answer» Correct Answer - Option 2 : B Given: The seller expects 32% return on his purchase price. The seller sell in one day was 528. Concept Used: Purchase price = 100/(100 + Return%) × Selling price Calculation: The seller expects 32% return on his purchase price. The seller sell in one day was 528. The purchase price = 100/(100 + 32) × 528 = 100/132 × 528 = 400 The profit amount = 528 - 400 = Rs.128 ∴ The profit amount is Rs.128. |
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| 28020. |
A salesman expects a gain of 25% on his cost price. If in a month his sale was Rs 45,500 what was his profit?1. Rs. 91002. Rs. 96003. Rs. 75004. Rs. 8600 |
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Answer» Correct Answer - Option 1 : Rs. 9100 Given: Gain percent = 25% on cost price Selling Price = Rs. 45,500 Formula used: Profit = SP - CP Calculation: Let the cost price be 100 unit According to the question Expected Selling price = 100 + 25 = 125 unit 125 unit → Rs. 45,500 1 unit → 45500/125 1 unit → 364 100 unit → 364 × 100 CP = 100 unit = Rs. 36,400 Now, Profit = SP - CP Profit = 45,500 - 36,400 Profit = Rs. 9100 ∴ Required profit is Rs. 9100. |
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| 28021. |
A man purchased 35 kg of rice at the rate of Rs. 9.50 per kg and 30 kg at the rate of Rs. 10.50 per kg. He mixed the two. Approximately, at what price (in Rs.) per kg should he sell the mixture to make 35% profit in the transaction?1. 12.502. 13.503. 124. 13 |
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Answer» Correct Answer - Option 2 : 13.50 Given: The cost price of 35 kg of rice = Rs. 9.50 per kg the cost price of 30 kg of rice = Rs. 10.50 per kg Formula Used: Profit = (Profit%/100 ) × CP Calculation: Total cost price of mixture of 35 kg and 30 kg of rice = (35 × 9.50 + 30 × 10.50) Total cost price of 65 kg mixture = (332.5 + 315) ⇒ Rs. 647.5 ⇒Rate per kg of mixture = 647.5/65 profit of the mixture per kg = (135/100) × (647.5/65) ⇒ Rs. 13.44 ∴ The selling price of the mixture of rice per kg is Rs.13.50 |
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| 28022. |
Find the sum to 200 terms of the series 1 + 4 + 6 + 5 + 11 + 6 +…(a) 30,200 (b) 29,800 (c) 30,200 (d) None of these |
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Answer» Spot that the above series is a combination of two A.P.s. The 1st A.P. is (1 + 6 + 11 +…) and the 2nd A.P. is (4 + 5 + 6 +…) Since the terms of the two series alternate, S = (1 + 6 + 11 +… to 100 terms) + (4 + 5 + 6 + … to 100 terms) = 100[2 x 1 +99 x 5]/2+ 100[2 x 4+99 x 1]/2 → (Using the formula for the sum of an AP = 50[497 + 107] = 50[604] = 30200 Alternatively, we can treat every two consecutive terms as one. So we will have a total of 100 terms of the nature: (1 + 4) + (6 + 5) + (11 + 6) …→ 5, 11, 17… Now, a = 5, d = 6 and n = 100 Hence the sum of the given series is S = 100/2 x [ 2 x 5 +99 x 6] = 50 [ 604] = 30200 |
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| 28023. |
Anita and Babita set out to meet each other from two places 200 km apart. Anita travels 20 km the first day, 19 km the second day, 18 km the third day and so on. Babita travels 8 km the first day, 10 km the second day, 12 km the third day and so on. After how many days will they meet? (a) 9 days (b) 8 days (c) 7 days (d) 6 days |
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Answer» Correct option (c) 7 days Explanation: The combined travel would be 28 on the first day, 29 on the second day, 30 on the third day, 31 on the fourth day, 32 on the fifth day and 33 on the sixth day, 34 on 7th day. They meet after 7 days. |
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| 28024. |
If a man saves Rs. 1000 each year and invests at the end of the year at 5% compound interest, how much will the amount be at the end of 15 years? (a) Rs 21,478 (b) Rs 21,578 (c) Rs 22,578 (d) Rs 22,478 |
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Answer» Correct option (b) Rs 21,578 Explanation: This is an intensive calculation, problem and you are not supposed to know how to do the calculations in this question mentally. The problem has been put here to test your concepts about whether you recogsize how this is a question of GPs. If you feel like, you can use a calculator/computer spreadsheet to get the answer to this question. The logic of the question would hinge on the fact that the value of the investment of the fifteenth year would be 1000. At the end of the 15th year, the investment of the 14th year would be equal to 1000 × 1.05, the 13th year’s investment would amount to 1000 × 1.052 and so on till the first year’s investment which would amount to 1000 × 1.0514 after 15 years. Thus, you need to calculate the sum of the GP: 1000, 1000 × 1.05, 1000 × 1.052 , 1000 × 1.053 for 15 terms. |
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| 28025. |
One side of a staircase is to be closed in by rectangular planks from the floor to each step. The width of each plank is 9 inches and their height are successively 6 inches, 12 inches, 18 inches and so on. There are 24 planks required in total. Find the area in square feet. (a) 112.5 (b) 107 (c) 118.5 (d) 105 |
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Answer» Correct option (a) 112.5 Explanation: The series of plank sizes would be: 0.75 × 0.5, 0.75 × 1, 0.75 × 1.5….0.75 × 12. The sum of this AP is 112.5. |
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| 28026. |
If sum to n terms of a series is given by (2n + 7) then its second term will be given by (a) 10 (b) 9 (c) 8 (d) 2 |
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Answer» Correct option (d) 2 Explanation: Since, sum to n terms is given by (2n + 7), Sum to 1 terms = 9 Sum to 2 terms = 11 Thus, the 2nd term must be 2, |
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| 28027. |
If the sum of n terms of a progression is 2n2 + 3. Then which term is equals to 78? |
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Answer» Going through the trial and error = 2(20)2 + 3 – 2(19)2 – 3 = 78. |
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| 28028. |
If y = tan–1 (2x/ 1 - x2), find (dy/dx). |
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Answer» Given y = tan–1 (2x/ 1 - x2) Put x = tan θ ⇒ θ = tan–1x y = tan–1 (2 tan θ/ 1 - tan2 θ) = tan–1 (tan 2θ) = 2θ = 2tan–1x differentiating w.r.to 'x' on both sides, we have (dy/dx) = 2(d/dx) = tan−1 x = 2(1/1 + x2) ∴ (dy/dx) = (2/ 1 + x2) |
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| 28029. |
How many natural numbers between 100 to 500 are multiples of 9? (a) 44 (b) 48 (c) 47 (d) 50 |
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Answer» Correct option (a) 44 Explanation: The series will be 108, 117, 126,…. 495. Hence, = 495 -108/9 +1 = 44 |
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| 28030. |
Find the value of 1 − 2 − 3 + 2 − 3 − 4 +... + upto 100 terms. (a) −694 (b) −626 (c) −624 (d) −660 |
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Answer» Correct option (b) −626 Explanation: The first 100 terms of this (1 − 2 − 3) + (2 − 3 − 4) + … + (33 − 34 − 35) + 34 The first 33 terms of the above series (indicated inside the brackets) will give an AP.−4, −5, −6.... −36 = 33 × −20 = −660 (sum of this A.P.). The required answer would be –660 + 34 = –626. |
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| 28031. |
Find the value of the expression 1 – 6 + 2 – 7 + 3 – 8 +……… to 100 terms (a) –250 (b) –500 (c) –450 (d) –300 |
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Answer» Correct option (a) –250 Explanation: The series (1 – 6 + 2 – 7 + 3 – 8 +… to 100 terms) can be rewritten as: ⇒ (1 + 2 + 3 + … to 50 terms) – (6 + 7 + 8 + … to 50 terms) Both these are AP’s with values of a and d as → a = 1, n = 50 and d = 1 and a = 6, n = 50 and d = 1, respectively. Using the formula for sum of an A.P. we get: → 25(2 + 49) – 25(12 + 49) → 25(51 – 61) = –250 Alternatively, we can do this faster by considering (1 – 6), (2 – 7), and so on as one unit or one term. 1 – 6 = 2 – 7 = … = –5. Thus the above series is equivalent to a series of fi fty –5’s added to each other. So, (1 – 6) + (2 – 7) + (3 – 8) + … 50 terms = –5 x 50 = –250 |
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| 28032. |
Find the area of the triangle formed by the straight line 3x – 4y + 12 = 0 with co-ordinate axes. |
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Answer» Given straight line equation is 3x – 4y + 12 = 0 ––––– (1) ⇒ 3x – 4y = –12 ⇒ (3x/-12) - (4y/-12) = 1 ⇒ (x/-4) + (y/3) = 1 X – intercept = – 4 Y – intercept = 3 Area of the triangle formed by the straight line (1) with the co-ordinate axes is (1/2) |(X – intercept) (Y – intercept)| = (1/2) |(–4) (3)| = 6 sq. units. |
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| 28033. |
Find the equation of straight line passing through (–2, 4) and making non-zero intercepts whose sum is zero. |
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Answer» Let X – intercept = a Y – intercept = b By hypothasis a + b = 0 ⇒ b = – a Intercept form (x/a) + (y/b) = 1 ⇒ (x/a) + (y/-a) = 1 ⇒ x – y = a But this straight line passing through (–2, 4). ∴ – 2 – 4 = a ⇒ a = – 6 ∴ Required straight line equation is x – y = – 6 ⇒ x – y + 6 = 0 |
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| 28034. |
Which among the following options is an advantage of using a vector image?1. Vector colour value and resolution remains undisturbed under scaling or de-scaling2. Web browser supports vector images mostly3. Vector supports smooth transitions4. Vector supports huge range of colour values |
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Answer» Correct Answer - Option 1 : Vector colour value and resolution remains undisturbed under scaling or de-scaling The correct answer is Vector color value and resolution remains undisturbed under scaling or de-scaling. Here are the most important advantages of vector graphics:
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| 28035. |
Consider a 33 MHz CPU-based system. What is the number of wait states required if it is interfaced with a 60ns memory ? Assume a maximum of 10 ns delay for additional circuitry like buffering and decoding. |
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Answer» Correct Answer - Option 4 : 3 The correct answer is "option 4". CONCEPT: When a computer processor accesses any external memory or the device that is slow to respond then the delay experienced by the processor is called Wait State. Since processor speed is faster than memory chips, the processor may sit idle for some cycles due to slow memory access. So, the total number of wait states can be defined as the total number of cycles needed by the CPU. CALCULATION: Memory access time = 60 ns Additional delay = 10 ns Total memory access time = Memory access time + Additional delay = 60 ns + 10 ns = 70 ns CPU Frequency = 33MHz Clock time = \(\frac{1}{33MHz}\) → \(\frac{1}{33*10^6}\)ns → \(\frac{1}{33}\) × 10-6 ns = 30.30 ns No. of wait states = \(\left\lceil\frac{70\ ns}{30.30\ ns} \right\rceil\)= 3 Hence , the number of wait states required is 3. 1. Clock rate or clock frequency is one of the important factors to measure processor performance. |
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| 28036. |
1 byte is equal to1. 10 bits2. 8 bits3. 16 bits4. 12 bits |
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Answer» Correct Answer - Option 2 : 8 bits The correct answer is 8 bits.
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| 28037. |
In computer terminology which of the following describes drivers?1. software that allows the user to control the operating system2. hardware that allows interaction between peripherical device and the operating system3. software that allows interaction between peripherical device and the operating system4. None of the above |
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Answer» Correct Answer - Option 3 : software that allows interaction between peripherical device and the operating system Concept: A Computer driver, is a set of files that tells a piece of hardware how to function by communicating with a computer's operating system. All pieces of hardware require a driver, from your internal computer components, such as your graphics card, to your external peripherals, like a printer. Or we can say that it is a Drivers are small programs that enable the operating system to communicate with peripheral devices Below is a list of hardware devices and peripherals that require drivers.
If the appropriate driver is not installed, the device may not function properly, if at all. With some devices, the device may work, but all of its features may not work. |
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| 28038. |
To whom does Ray Tomlinson go to the credit?1. send first email2. he built the first computer3. invention of calculator4. development of the internet |
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Answer» Correct Answer - Option 1 : send first email The correct answer is sending the first email.
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| 28039. |
The resultant of vectors `vec(OA) and vec(OB)` is peerpendicular to `vec(OA). Find the angle AOB. |
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Answer» Take the dotted lines as X,Y axes. x -component of `vec(OA)=4m, x-component of `vec(OB)=6 m costheta`. x- component of the resultant `=(4+6cos theta)` m. But it is given that the resultant is along Y-axis. Thus, the -component of the resultant =0 `4+6cos theta = 0, or, costheta = 2/3` |
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| 28040. |
Which of the following tasks is not performed by a computer's CPU?1. Fetching instructions2. Instruction interpretation3. Storing data permanently4. Data processing / processing |
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Answer» Correct Answer - Option 3 : Storing data permanently The correct answer is Storing data permanently.
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| 28041. |
What should be entered in the run command in order to open a Microsoft word document?1. MSWord2. OfficeWord3. Word4. Winword |
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Answer» Correct Answer - Option 4 : Winword The correct answer is Winword.
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| 28042. |
Binary language consists of how many digits?1. 22. 33. 44. 16 |
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Answer» Correct Answer - Option 1 : 2 The correct answer is 2.
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| 28043. |
Read the conversation and in the blank with correct ‘If clause’ choosing from the given alternatives : Ravi : Hi, Sanju, How are you ? Sanju : Fine, thank you.Ravi : What is your percentage in II PUC? Sanju : I got only’56% Ravi : Is it ! I expected more. Sanju : If I had studied hard I scored more marks. Ravi : It’s OK. Don’t worry, concentrate more on further studies. (A) would have (B) will have (C) might (D) would. |
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Answer» (A) Would have |
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| 28044. |
Read the conversation and rewrite the underlined sentences into Reported speech: Ayesha : How are you Salma? Salma : I’m fine, thank you. Ayesha : Did you see the film ‘Takur’? Salma : No, but I’m planning to see the film on Sunday. Ayesha : It’s fantastic. Don’t miss it. Salma : O. K.Ayesha asked Salma if ……………….. Salma replied that ……………......... |
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Answer» Ayesha asked Salma if she had seen the film ‘Takur’ Salma replied in the negative but added that she was planning to see the film on Sunday. Reference Skill |
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| 28045. |
Which of the following is the largest, fastest and costliest computer?1. Personal computer2. Super computer3. Laptop4. Note book |
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Answer» Correct Answer - Option 2 : Super computer The correct answer is Super Computer.
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| 28046. |
Which of the following Super Computers is the fastest Super Computer?1. Sun-way TaihuLight2. Titan3. Piz Daint4. Sequoia |
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Answer» Correct Answer - Option 1 : Sun-way TaihuLight The correct answer is "option 1". CONCEPT: A supercomputer is a computer that gives a high level of performance as compared to any general-purpose computer. The performance of a supercomputer is commonly measured in Floating-Point Operations Per Second (FLOPS). As per the recently released semiannual Top 500 list of supercomputers, Sunway TaihuLight has been named as the world’s fastest supercomputer title. EXPLANATION: option1: Sunway TaihuLight is the fastest Chinese supercomputer with a LINPACK speed of 105 Peta FLOPS available from 2016. option2: Titan / OLCF-2 is a supercomputer used for science research available from 2013 & have LINPACK speed of 17.59 Peta FLOPS. option3: Piz Daint is a supercomputer with a LINPACK speed of 25.3 Peta FLOPS. option4: Sequoia is a supercomputer developed by IBM as a part of the Advanced Simulation & Computing Program with a speed of 20.13 Peta FLOPS.
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| 28047. |
Shortcut command for align the text in centre?1. Ctrl+E2. Ctrl+T3. Ctrl+R4. Ctrl+C |
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Answer» Correct Answer - Option 1 : Ctrl+E The correct answer is Ctrl+E.
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| 28048. |
As on March 2018, which of the following is the India's fastest supercomputer?1. Summit2. Sierra3. Mihir4. Pratyush |
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Answer» Correct Answer - Option 4 : Pratyush The correct answer is Pratyush.
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| 28049. |
What is the full form of Bit?1. Binary tree2. Binary digit3. Binary term4. Binary task |
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Answer» Correct Answer - Option 2 : Binary digit The correct answer is Binary digit.
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| 28050. |
Read the conversations and rewrite the underlined sentences in reportedspeech:Kshama: Hi Deepthi, how are you?Deepthi: Hi, I am fine. Thank you. Kshama: Will you please help me cross the road?Deepthi: Sure, I don’t mind. Kshama asked Deepthi whether ..............Deepthi replied she ................. |
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Answer» Kshama asked Deepthi whether she would help her cross the road. Deepthi replied that she would surely help and that she did not mind. |
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