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The resultant of vectors `vec(OA) and vec(OB)` is peerpendicular to `vec(OA). Find the angle AOB. |
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Answer» Take the dotted lines as X,Y axes. x -component of `vec(OA)=4m, x-component of `vec(OB)=6 m costheta`. x- component of the resultant `=(4+6cos theta)` m. But it is given that the resultant is along Y-axis. Thus, the -component of the resultant =0 `4+6cos theta = 0, or, costheta = 2/3` |
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