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The sum of the series 3 × 5 + 5 × 7 + 7 × 9 +…. upto n terms will be: (a) n(4n2 +18n +23)/3(b) n(4n2 +18n +23)/6(c) n(4n2+18n+23)(d) None of these. |
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Answer» Correct option (a) n(4n2 +18n +23)/3 Explanation: Solve this using trial and error. For 1 term the sum should be 15 and we get 15 only from the first option when we put is n = 1. |
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