1.

Find the area of the triangle formed by the straight line 3x – 4y + 12 = 0 with co-ordinate axes.

Answer»

Given straight line equation is 3x – 4y + 12 = 0 ––––– (1) 

⇒ 3x – 4y = –12 

⇒ (3x/-12) - (4y/-12) = 1

⇒ (x/-4) + (y/3) = 1 

X – intercept = – 4 

Y – intercept = 3 

Area of the triangle formed by the straight line (1) with the 

co-ordinate axes is (1/2) |(X – intercept) (Y – intercept)| 

= (1/2) |(–4) (3)| 

= 6 sq. units.



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