This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 19851. |
Figure shows `4` identical masses of mass `m`, arranged on a cube as shown. The potential energy of the system is A. it will collide with one of the massesB. It execute an oscillatory motion (not SHM)C. It executes SHMD. none of these |
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Answer» `PE=6xx(GM^(2))/(sqrt(2)a)` `=-3sqrt(2)(GM^(2))/(a)` `F=3xx(GM^(2))/(2a^(2))xx(sqrt(2))/(sqrt(3))=sqrt((3)/(2))(GM^(2))/(a^(2))` |
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| 19852. |
When we raise the temperature of a body, the molecules and atoms move with greater kinetic enery. Assume that "the temperature" is the manifestation of only the kinetic energy is atomic and subatomic levels and no mass change (excess//defect) occurs due to heating. Now a solid material is supplied with heat at a constant rate. The temperature of the material is changing with the heat input as shown in the graph. `BC` and `DE` are parallel to the Heat-input axis In `AB`, `CD` and `EF`, the energy of the system increases. Here "energy" refers to A. kinetic energyB. potential energyC. both kinetic and potential energyD. none of these |
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Answer» In `AB`, `CD` and `EF` Temperature increases `rArr K.E.` increases |
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| 19853. |
When we raise the temperature of a body, the molecules and atoms move with greater kinetic enery. Assume that "the temperature" is the manifestation of only the kinetic energy is atomic and subatomic levels and no mass change (excess//defect) occurs due to heating. Now a solid material is supplied with heat at a constant rate. The temperature of the material is changing with the heat input as shown in the graph. `BC` and `DE` are parallel to the Heat-input axis In which of the following phase the assumption made in the above comprehension is most precise ? A. solidB. liquidC. gasD. not predictable |
| Answer» In gases, there is no appreciable molecular interaction. | |
| 19854. |
When we raise the temperature of a body, the molecules and atoms move with greater kinetic enery. Assume that "the temperature" is the manifestation of only the kinetic energy is atomic and subatomic levels and no mass change (excess//defect) occurs due to heating. Now a solid material is supplied with heat at a constant rate. The temperature of the material is changing with the heat input as shown in the graph. `BC` and `DE` are parallel to the Heat-input axis In `BC` and `DE` A. kinetic energy increasesB. potential energy increasesC. kinetic energy decreasesD. potential energy remains constant |
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Answer» In `BC` and `DE` temperature remains constant `rArr K.E.` remains constant `rArr` Heat goes to increasing the `P.E.` |
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| 19855. |
The figure that is not a direct manifestation of the quantum nature of atoms |
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Answer» Answer is (1) Photoelectric effect (option 2), atomic spectrum (option 3) and Black body radiations (option 4) may be explained by quantum theory. As on increasing temperature, all the values of internal energy becomes possible, it is not directly explained from quantum theory. |
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| 19856. |
For the following Assertion and Reason, the correct option isAssertion (A) : When Cu (II) and sulphide ions are mixed, they react together extremely quickly to give a solid.Reason (R) : The equilibrium constant of Cu2+ (aq) + S2- (aq) ⇌ CuS(s) is high because the solubility product is low.(1) Both (A) and (R) are true and (R) is the explanation for (A)(2) Both (A) and (R) are false(3) (A) is false and (R) is true (4) Both (A) and (R) are true but (R) is not the explanation for (A) |
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Answer» Answer is (4) Both (A) and (R) are true but (R) is not the explanation for (A) Slow or fast process is kinetic parameter but extent less or more is thermodynamic parameter. |
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| 19857. |
At least how many half-lives should elapse for a `1^(st)` order reaction `Ato` products so that the reaction is at least `95%` completed? `(log2=0.3)`A. 4B. 5C. 6D. 7 |
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Answer» Correct Answer - B `underset(0%)(100)overset(t_((1)/(2)))tounderset(50%)(50)overset(t_((1)/(2)))tounderset(75%)(25)overset(t_((1)/(2)))to` `underset(87.5%)(12.5)overset(t_((1)/(2)))tounderset(93.75%)(6.25)overset(t_((1)/(2)))tounderset(96.875%)(3.125)` |
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| 19858. |
For the reaction `2A+BtoC` with the rate low `(d[C])/(dt)=k[A]^(1)[B]^(-1)` and started with A and B in stoichiometric proportion.Which is/are true ?A. unit of k is `Ms^(-1)`B. [A],[B] and [C] all will be linear functions of timeC. [C]=2ktD. [C]=kt |
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Answer» Correct Answer - A,B,C `{:(" ",2A" " +,B" " to,C),(t=0,2a,a,0),(t=t,2a-2x,a-x,x):}` `(d[C])/dt=k2(a-x)(a-x)^(-1)=2kimplies intd[c]=intk dtimplies [C]=2kt` unit of k=`Ms^(-1)` `[A]=2(a-x) and [C]=x` `[B]=(a-x)` |
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| 19859. |
For a certain reaction `Ato` products, the `t_(1//2)` as a function of `[A]_0` is given as below: `{:([A]_0(M),0.1,0.025),(t_(1//2),100,50):}` Which of the following is true :A. The order of `1/2`B. `t_(1//2)`would be `100sqrt10` min for `[A]_0=1` MC. The order is 1D. `t_(1//2)`would be `100` min for `[A]_0=1` M |
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Answer» Correct Answer - A,B `100prop(0.1)^(t-n)` `50prop(0.025)^(1-n)` Divide `2=4^(1-n)` `2=2^(2-2n) implies " " 2-2n=1` `n=1/2` `100 prop (0.1)^(1//2) implies t^(1//2)prop(1)^(1//2)` Divide `t_(1//2)/100=(1/0.1)^(1//2)` `t_(1//2)=100sqrt10` min. |
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| 19860. |
Extra pure `N_2` can be obtained by heatingA. `NH_(3)` with calcium hypochloriteB. `NH_(4)Cl+NaNO_(3)`C. `(NH_(4))_(2)Cr_(2)O_(7)`D. `Ba(N_(3))_(2)` |
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Answer» Correct Answer - 4 `Ba(N_(3))_(2)(s)overset(Delta)rarrBa(s)+3N_(2)(g)` |
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| 19861. |
A graph between `log t_((1)/(2))` and log a (abscissa), a being the initial concentration of A in the reaction For reaction `Ato`Product, the rate law is : A. `(-d[A])/(dt)=K`B. `(-d[A])/(dt)=K[A]`C. `(-d[A])/(dt)=K[A]^2`D. `(-d[A])/(dt)=K[A]^3` |
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Answer» Correct Answer - C `t_(1//2)=Ka^(1-n)`,n being order K=Rate constant log `t_(1//2)=log K+(1-n) log a` 1-n=-1 n=2 |
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| 19862. |
A gaseous reaction `A_(2)(g) rarr B(g) + (1)/(2) C(g)` shows increase in pressure form `100 mm` to `120 mm` in `5 min`. What is the rate of disappearance of `A_(2)` ?A. 4B. 8C. 16D. 2 |
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Answer» Correct Answer - A `{:(,A_2(g)to,B(g)+,1/2C(g)),(t=0,100,0,0),(t=5,100-p,p,p//2),("At" "t"=5 "min",,underset(p=20)(100+p//2=110),):}` rate of disappearence of `A_2=20/5=4` |
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| 19863. |
For a `1^(st)` order reaction (gaseous) (constant V, T) : `aAto(b-1)B+1 C` (with `bgta`) the pressure of the system rose by `50(b/a-1)` % in a time of 10 min. The half life of the reaction is therefore.A. 10 minB. 20 minC. 30 minD. 40 min |
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Answer» Correct Answer - A `{:(aA,to,(b-a)B,+C),(t=0,P_0,0,0),(t=t,P_3x,((b-a)x)/a,x/a):}` Total pressure `P_0-x+b/ax=P_0+(b/a-1) 1/2 P_0` `P_0+(b/a-1)x=P_0+(b/a-1)P_0/2` `x=P_0/2` `P_A=P_0-x=P_0-P_0/2=P_0/2` `P_A` reduces to half in 10 min, so `t_(t//2)`=10 min |
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| 19864. |
`[Cr(NH_(3))_(6)][Cr(SCN)_(6)]` and `[Cr(NH_(3))_(2) (SCN)_(4)][Cr(NH_(3))_(4) (SCN)_(2)]` are the examples of what type of isomerism?A. Ionisation isomerismB. Linkage isomerismC. Coordination isomerismD. Solve isomerism |
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Answer» Correct Answer - C These are co-ordianates isomers, which s arises due to exchange ofligands between positive and negative ions. |
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| 19865. |
For a certain reaction the variation of rate constant with temperature is given by the equation `ln k_(t) = lnk_(0) + ((ln 3)t)/(10) (t ge 0^(@)C)` The value of temperature coefficient of the reaction isA. 0.1B. `1.0`C. 10D. 3 |
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Answer» Correct Answer - D `k_t/k_o=(TC)^(t-0//10)` Taking log gives `"log"_e k_t-"log"_e k_0=t/10 "log"_e(TC)` `implies "In" k_t="In" k_o+(("In"(TC))/10)t` Comparison indicates `("In"(TC))/10=("In"3)/10implies TC=3` |
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| 19866. |
The correct IUPAC name `[Co(NH_(3))_(3)(NO_(2))_(3)]` isA. Triammine trinitro N cobalt (III)B. Triammine trinitro N cobalt (II)C. Triammine cobalt (III) nitriteD. Triammine trinitro N cobaltate (III) |
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Answer» Correct Answer - a The IUPAC na e of `[Co(NH_(3))_(3)(NO)(2)_(3)]` is triammine trinitro N cobalt (III) |
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| 19867. |
The correct IUPAC name of `[Co(NH_(3))_(3)(NO_(2))_(3)]`A. Triammine trinitrito - N cobalt (III)B. Triammine trinitrito - N cobalt (II)C. Triammine cobalt (III) nitriteD. Triammine trinitrito-N cobaltate (III) |
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Answer» Correct Answer - A IUPAC name of `[Co(NH_(3))_(3)(NO_(2))_(3)]` is triamminetrinitritio-N-cobalt (III). |
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| 19868. |
Potassium dichromate is a good oxidizing agent, in acidic medium the oxidation state of chromium changes byA. 2B. 3C. 4D. 5 |
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Answer» Correct Answer - B It acts as oxidising agent in acidic medium by gain of six electrons and oxidation state of Cr `Cr_(2)O_(7)^(2-) + 14H^(+) + 6e^(-) to 2Cr^(3+) + 7H_(2)O` |
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| 19869. |
In fig, PA, QB and RC are each perpendicular to AC. If x = 8 cm and z = 6 cm, then y is equal to(a) 56/7 cm(b) 7/56 cm(c) 25/7 cm(d) 24/7 cm |
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Answer» Correct option is (d) 24/7 cm |
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| 19870. |
The only radioactive element among the lanthanoids isA. gadoliniumB. holmiumC. promethiumD. neodymium |
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Answer» Correct Answer - c Among the lanthanioids promethium is the only radioactive element |
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| 19871. |
The increasing order of basic strength of Cl–, CO32-, CH3COO-, OH-, F- is : |
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Answer» Correct option: (a) Explanation: More is the acidic character, lesser is basic character of conjugate base. |
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| 19872. |
What are Strong electrolyte ? Give an examples. |
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Answer» Those ionic conductors which are completely ionized in aqueous solution are called as strong electrolyte. Ex . Na+ Cl– , K+ Cl– , etc. For strong electrolyte the value of degree of dissociation is 100%. i.e. α = 1 Ex : (a) Strong acid → H2SO4, HCl, HNO3 HClO4, H2SO5, HBr, HI (b) Strong base → KOH, NaOH, Ba(OH)2 CsOH, RbOH (c) All Salts → NaCl, KCl, CuSO4 .......... |
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| 19873. |
Which one is greater α1 or α2 for the following equation :(i) NH4OH + H2O → α1 (ii) NH4OH + D2O → α2 |
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Answer» Dielectric constant of H2O is more than that of D2O , so α1 > α2 |
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| 19874. |
Which one of the following is strongest acid ?A. `H_2S`B. `H_2Se`C. `H_2O`D. `H_2Te` |
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Answer» Correct Answer - (d) ``HNO_(2)+HNO_(3) rarrNO_(2)+H_(2)O` Hecne `NO_(2)` mixd anhydride of Te-H bond strength , acts as the strongest acid. |
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| 19875. |
The mixed anhydride of nitrous and nitric acid is.A. ` N_2O`B. ` NO_2`C. `NO`D. `N_2O_5` |
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Answer» Correct Answer - B When oxidation state of central atom is same , with the decrease in elctornegativity of central atom acidic character decreases. Hence `H_(3)PO_(4)` is most acidic . `H_(3)PO_(4) ft H_(3) AsO_(4) gt H_(3) SbO_(4) gtH_(3) BiO_(4)` |
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| 19876. |
Of the follwing , the most acidic is .A. ` H_3 PO_4`B. ` H_3AsO_4`C. `H_3SbO_4`D. `H_3BiO_4` |
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Answer» Correct Answer - A `CH_(3)CH_(2)NO_(2) overset(HNO_(2))(rarr) CH_(3)underset("nitrolic acid")underset((blue))underset(" N-OH")underset(||)(C)-ON_(2) overset(NaOH)(rarr) CH_(3)underset((red))underset(" NONa")underset(||)C-NO_(2)` `overset(CH_(3))overset(|)(CH_(3)CHNO_(2))overset(HNO_(2))(rarr)-overset(CH_(3))overset(|)underset(("blue"))underset("pseudonitrol")underset(" N=O")underset(|)(C)-NO_(2) overset(NHO_(2))(rarr)underset((blue))("noreaction")` `(CH_(3))_(3)CNO overset (HnO_(2))(rarr)`. |
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| 19877. |
Assertion `:-` Adding inert gas at equilibrium to dissociation of `PCL_(3)` at constant pressure increases the degree of dissociation. Reason `:-` Since degree of dissociation `x` `alphasqrt(v)`A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertiion.C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False |
| Answer» Correct Answer - A | |
| 19878. |
Assertion `:-` `K_(c)` for process `2H_(2)O(l)hArr2H_(2)O_((g))+O_(2(g))`may be written as `:K_(c)=[H_(2)]^(2)[O_(2)]` Reason `:-` Concentration of pure liquid is fixed and cannot vary (Taken as `1`)A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertiion.C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False |
| Answer» Correct Answer - A | |
| 19879. |
Write the IUPAC name of the following coordination compounds:I. K4[Fe(CN)6]II. Ni(CO)4III. K2[Pt(Cl)6]IV. CO(NH3)3V. Fe4[Fe(CN)6]3 |
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Answer» I. K4[Fe(CN)6] - Potassium hexacyanoferate((II) II. Ni(CO)4 - Tetracarbonyl Nickel III. K2[Pt(Cl)6] - Potassium tetra cyano platinate (III) IV. CO(NH3)3 - Tri Tramine Cobalt (II) V. Fe4[Fe(CN)6]3 - Iron hexa cyanoferrate (Il) |
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| 19880. |
Which of the following is related to steroid ? (A) Vitamin E (B) Vitamin K (C) Vitamin B (D) Vitamin D |
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Answer» Correct answer is (D) Vitamin D |
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| 19881. |
Which of the following is the sweetest sugar ? (A) Sucrose (B) Fructose (C) Maltose (D) Lactose |
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Answer» Correct answer is (B) Fructose |
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| 19882. |
State Werner's coordination theory. |
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Answer» The first systematic attempt at explaning the formation, reactions, structure and bonding of a coordination compound was made by A. Werner His theory postulated the use of two types of linkages (primary and secondary) by a metal atom/ion in a coordination. In the modern language of chemistry these linkages are recognised as the ionisable (ionic) and non-ionisable (covalent) bonds respectively. |
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| 19883. |
In which of the following alkylation is possible ? (A) In primary amine only (B) In secondary amine only (C) In tertiary amine only (D) In both primary and secondary amines |
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Answer» Correct answer is (D) In both primary and secondary amines |
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| 19884. |
Find total number of species in which Zn metal is soluble under oridnary condition (R.T.). `H_(2)O,"dil".H_(2)SO_(4),"conc". H_(2)SO_(4),"dil".HNO_(3),"conc".HNO_(3),"dil". HCl,NaOH(aq),AgNO_(3)(aq.),CuSO_(4)(aq.)` |
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Answer» Correct Answer - 8 `Zn+"dil".H_(2)SO_(4)rarrZnSO_(4)(aq)+H_(2)uarr` `Zn+"conc".H_(2)SO_(4)rarrZnSO_(4)(aq)+SO_(2)uarr` `Zn+"dil". HNO_(3)rarrZn(NO_(3))_(2)(aq)+N_(2)Ouarr` `Zn+"conc."HNO_(3)rarrZn(NO_(3))_(2)(aq)+NO_(2)uarr` `Zn+"dil". HClrarrZnCl_(2)(aq)+H_(2)rarr` `Zn+NaOHrarrNa_(2)Zn(OH)_(4)(aq)+H_(2)uarr` `Zn+AgNO_(3)rarrZn(NO_(3))_(2)+Agdarr` `Zn+CuSO_(4)rarrZnSO_(4)+Cudarr` |
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| 19885. |
x = Number of compounds for which formaldehyde is necessary as reactant to obtained them by aldol reaction or condensation `HO-CH_(2)-CH_(2)-CHO` |
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Answer» Correct Answer - 4 `III, VI, VII and VIII` |
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| 19886. |
The functional group of primary amine is – (A) – NH - (B) – NH2 (C) NH3 (D) NH4+ |
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Answer» Correct answer is (B) – NH2 |
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| 19887. |
Acetamide on reaction with Br2 and NaOH gives – (A) Acetone (B) Methylamine (C) Acetaldehyde (D) Ammonia |
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Answer» Correct answer is (B) Methylamine |
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| 19888. |
Ethylamine on reaction with nitrous acid gives – (A) C2H5OH (B) CH3COOH (C) C2H5NO2 (D) None of these |
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Answer» Correct answer is (A) C2H5OH |
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| 19889. |
Match the statement given in Column I with the phenomenon given in Column II.Column I Column II(i) Dispersion medium moves in an (a) Osmosiselectric fleld(ii) Solvent molecules pass through semi (b) Electrophoresispermeable membrane towards solvent side(iii) Movement of charged colloidal particles (c) Electro osmosisunder the inuence of applied electric potentialtowards oppositely charged electrodes(iv) Solvent molecules pass through semi permeable (d) Reverse osmosismembranes towards solution side |
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Answer» (i) (c) (ii) (d) (iii) (b) (iv) (a) |
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| 19890. |
CuSO4 is colourless while CuSO4.5H2O is coloured. Why ? |
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Answer» CuSO4 does not has any ligand, so splitting of d-orbital take place while CuSO4.5H2O has water ligand. |
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| 19891. |
How is stability of coordination compound determined in aqueous solution ? |
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Answer» By using stability constant. More stability constant, more stability. |
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| 19892. |
What is the difference between inner and outer orbital complexes ? |
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Answer» Inner sphere complex : When d-orbital of inner shell take part in hybridisation. |
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| 19893. |
Calculate the mass of hydrochloric acid in 200 cm3 of 0.2 N solution of it. What volume of this acid solution will react exactly with 25 cm3 of 0.14 N solution of sodium hydroxide? |
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Answer» Normality of hydrochloric acid = 0.2; Eq. mass of hydrochloric acid = 36.5 Mass of hydrochloric acid in one dm3 of the solution is given by W = N × E = 0.2 × 36.5 g ∴ mass of hydrochloric acid in 200 cm3 of the solution = 0.2 x 36.5/5 = 1.46 g V1 x N1 = V2 x N2 Acid Base Substituting we have V1 × 0.2 = 25 × 0.14 ∴ V1 = 25 x 0.14/0.2 = 17.5 cm3 |
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| 19894. |
Give example of a material used for making semi permeable membrane for carrying out reverse osmosis. |
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Answer» Cellulose acetate, potassium ferrocyanide, etc. are used as semipermeable membrane for carrying out reverse osmosis. |
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| 19895. |
what happens when gelatin is mixed with gold SOL. |
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Answer» When gelatin is mixed with gold sol then Gold sol is stabilized and no coagulating takes place. |
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| 19896. |
How is lake test for aluminium ion based upon adsorption ? |
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Answer» [Hint : Al2O3.xH2O has the capacity to adsorb the colour of blue litmus from the solution. |
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| 19897. |
correct order of basicity is |
| Answer» in A lone pair are in sp^2 hybridisation,B lone pair are in sp^3 hybridisation C lone pair are in resonance of the molecule | |
| 19898. |
Consider the ΔG°f and ΔH°f (kJ/mol) for the following oxides. Which oxide can be most easily decomposed to form the metal and oxygen gas?(a) ZnO (ΔG° = - 318.4, ΔH° = - 348.3)(b) Cu2O(ΔG° = - 146.0, ΔH° = - 168.8)(c) HgO (ΔG° = - 58.5, ΔH° = - 90.8)(d) PbO (ΔG° = - 187.9, ΔH° = - 217.3) |
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Answer» Correct option (c) HgO (ΔG° = - 58.5, ΔH° = - 90.8) Oxide with lowest –ve ΔG° |
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| 19899. |
Which of the following instruments has a property of quick response time?1. Analogue instrument2. Electrical instrument3. Electronic instrument4. Mechanical instrument |
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Answer» Correct Answer - Option 3 : Electronic instrument Explanation: Measurement generally involves using an instrument as a physical means of determining a quantity or variable. The instrument serves as an extension of human faculties and enables the man to determine the value of an unknown quantity that unaided human faculties cannot measure. An instrument may be defined as a device for determining the value or magnitude of a quantity or variable. Measuring instruments, and formal test methods which define the instrument's use, are the means by which the variables and the relations between variables are obtained The various types of measuring instruments are:
Electronic Instruments have the fastest response time among all.
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| 19900. |
Reaction of ‘magnesium’ with air is |
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Answer» The reaction of magnesium with air is an exothermic reaction as magnesium burns with dazzling brilliance in the air forming white shiny magnesium oxide with the evolution of a lot of heat. 2Mg + O2 → 2MgO + heat |
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