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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 19901. |
A zinc plate was kept in a glass container having copper sulphate solution. On examining it was found that the blue colour of the solution is getting fader and fader. After a few days when the zinc plate was taken out of the solution, a number of small holes were noticed in it. State the reason and give chemical equation of the reaction involved |
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Answer» Zinc is more reactive than copper. Hence,'when a zinc plate is kept in a solution of copper sulphate, it slowly displaces copper from the solution and blue colour of the solution keeps fading away Because of zinc going into solution as zinc sulphate a number of holes are seen in the zinc plate. The reaction is |
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| 19902. |
`C_(4)H_(11)N` can represent :A. Total structural amines are eightB. `1^(@)` amines are fourC. `2^(@)` amines are threeD. `3^(@)` amine is one |
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Answer» Correct Answer - A::B::C::D `C_(4)-NH_(2)` so possible isomers are four. `C_(3)-NH-C_(1)` so possible isomers are two. `C_(2)-NH-C_(2)rarr1`, total `3` isomers are possible `C_(2)-underset(C_(1))underset(|)(N)-C_(1)` possible isomer is one. |
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| 19903. |
Which of the following following `IUPAC` names are correct :A. B. C. , `4-`formyl`-2-`sulphobenzoic acidD. , `2-`bromo`-6-`chlorophenol |
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Answer» Correct Answer - B::C::D Correct name of `(A)` is `2-`methylbutane`-1,4-`diamine. |
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| 19904. |
Prefix are correctly named for which of the following side-chain attached to the present chain/ring?A. , Prefix : Ethanoyloxy.B. , Prefix : MethoxycarbonylC. , Prefix : cyanoD. , Prefix : Carbamoyl |
| Answer» Correct Answer - A::B::D | |
| 19905. |
Which among the following compounds is used to decaffeinate coffee?A. lodoformB. Carbon tetrachlorideC. Methylene dichlorideD. Chloroform |
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Answer» Correct Answer - C Methylene dichloride is used as a solvent in the direct method of decaffeination of the coffee. |
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| 19906. |
Which among these is the unit of energy and work? |
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Answer» The SI unit of work is the joule (J), the same unit as for energy. |
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| 19907. |
In the reaction, `MnO_(4)^(-1)(aq)+Br^(-1)(aq)toMnO_(2)(s)+BrO_(3)^(-1)(aq)`, the correct change in oxidation number of the species involved isA. `Br^(+5)toBr^(-1)`B. `Mn^(+7)toMn^(+2)`C. `Mn^(+7)toMn^(+3)`D. `Br^(-1)toBr^(+5)` |
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Answer» Correct Answer - D `overset(+7)MnO_(4)^(-1)(aq)+Br^(-1)(aq)tooverset(+4)MnO_(2)(s)+overset(+5)BrO_(3)(aq)` In the above reaction, oxidation number of Mn in `MnO_(4)^(-1)`(aq) decreases from + 7 to+ 4 in `MnO_(2)` (s) and oxidation number of `Br^(-)` increase from -1 (in `Br^(-)` (aq) to + 5 (in `BrO_(3)^(-1)`(aq) ). Thus, the correct option is (d). |
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| 19908. |
A light is travelling from air a medium the velocity of light in a medium is reduced to to 0.75 times the velocity n air assume that angle of incidence I is very small the deviation of the ray isA. iB. `(i)/(3)`C. `(i)/(4)`D. `(3i)/(4)` |
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Answer» Correct Answer - b When a light travels from air into a medium then velocity of light in a medium is `V_(m)=V-0.75 V= 0.25 V` where v is velocity of light in air using snell law we have `(sini)/(sin r)= mu =(v)/(v_(m))` or `(i)/(r )=(v)/(v_(m))` or `(i)/(r )=(v)/(0.25 V)=4 rarr r=(i)/(4)` |
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| 19909. |
The electric field intensity at point near and outside the surface of a charged conductor of any shate is `E_(1)` the elecric field intensity due to uniformly charged conductor of any shape is `E_(1)` the electric field intensity due ot uniformly charged infinite thin plane sheet is `E_(2)` the relation between `E_(1)` and `E_(2)` isA. `2E_(1)=E_(2)`B. `E_(1)=E_(2)`C. `E_(1)=2E_(2)`D. `E_(1)=4E_(1)` |
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Answer» Correct Answer - b Electric field intensity at a point near and outside the surface of any charged conductor is given by `E_(1)=(sigma)/(epsilon_(0))` where `sigma` is charge density (charge per unit area) at a point Electric field intensity due to uniformly charged infinite thin plane sheet is givne by `E_(2)=(sigma)/(2 epsilon_(0))` from eqs (i) and (ii) we have `e_(1)=2/2xx(sigma)/(epsilon_(0))=2xxE_(2)rarrE_(1)=2E_(2)` |
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| 19910. |
Which of the following plant hormone substitutes for long photoperiod in flowering plant(1) Auxin (2) Gibberellin (3) Cytokinin (4) Ethylene |
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Answer» (2) Gibberellin |
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| 19911. |
IAA was isolated by(1) Kogl and Erxleben (2) Kogl and Haagen Smit (3) Erxleben and Haagen Smit (4) Kogl, Darwin and Haagen Smit |
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Answer» (2) Kogl and Haagen Smit |
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| 19912. |
Cholodnyl-Went theory is related with– (1) Turgor movement (2) Chemotropism (3) Phot-tropism (4) Phototropism & Geotropism |
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Answer» (4) Phototropism & Geotropism |
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| 19913. |
In a growing plant, the first phase during the process of growth is(1) Cell division (2) Cell enlargement (3) Cell differentiation (4) Cell maturation |
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Answer» (1) Cell division |
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| 19914. |
Maximum of growth occurs in(1) Exponential phase (2) Decline phase (3) Stationary phase (4) Lag phase |
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Answer» (1) Exponential phase |
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| 19915. |
The maximum growth rate occurs in(1) Exponential phase (2) Stationary phase (3) Senescent phase (4) Lag phase |
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Answer» (1) Exponential phase |
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| 19916. |
Isoprene monomer is present in which of the following?(a) Natural rubber(b) Terylene(b) Nylon – 6, 6(d) Polythene |
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Answer» Isoprene monomer is present in Natural rubber. |
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| 19917. |
One set of a plant was grown at 12 hrs. day and 12 hours night period cycles and it flowered. While in the other set night phase was interrupted by flash of light and it did not flower. Under which one of the following catagories will you place this plant(1) Short day (2) Long day (3) Darkness neutral (4) Day neutral |
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Answer» (1) Short day |
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| 19918. |
The distillation of calcium formate, gives -(a) CH3CHO(b) HCHO(c) HCOOH(d) CH3COOH |
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Answer» The distillation of calcium formate, gives HCHO. |
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| 19919. |
Cell elogation in internodel regions of the green plants takes place due to(1) Ethylene (2) Indole acetic acid (3) Cytokinin (4) Gibberellins |
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Answer» (4) Gibberellins |
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| 19920. |
The unit for rate constant for a reaction is mole L–1 sec–1. The order of the reaction is–(a) 0(b) 1(c) 2(d) 3 |
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Answer» The order of the reaction is 0. |
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| 19921. |
Prunning of plants promotes branching, because the axillary buds get sensitized to(1) Ethylene (2) Gibberellin (3) Cytokinin (4) IAA |
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Answer» (3) Cytokinin |
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| 19922. |
Spontaneous cell reaction will occur when(a) E° is negative.(b) ΔG° is negative(c) ΔG° is positive.(d) None of these |
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Answer» Spontaneous cell reaction will occur when ΔG° is negative |
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| 19923. |
Which is the critical period in short day plants ? (1) Duration of light (2) Duration of darkness (3) Duration of both (4) None of the above |
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Answer» (2) Duration of darkness |
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| 19924. |
Which has maximum boiling point at one atmosphoric pressure ?(a) 0.1 M NaCl(b) 0.1 M BaCl2(c) 0.1 M Sucrose(d) 0.1 M Glucose |
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Answer» The maximum boiling point at one atmosphoric pressure is 0.1 M BaCl2 |
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| 19925. |
The structure of a compound made of elements A and B is crystalised. The atom ‘A’ is situated at the corners and atom ‘B’ is situated at the centre of each face of the cube. What is the formula of this compound?(a) AB3(b) A3B(c) AB(d) AB2 |
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Answer» The formula of this compound is AB3 |
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| 19926. |
If x and y are two distinct real numbers such that x3 – xy2 = 0 then which of the following condition is correct?1. x = y2. x = 03. x = -y4. Either option 2 or 3 |
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Answer» Correct Answer - Option 4 : Either option 2 or 3 Given: x and y are two distinct real numbers which satisfied the given condition x3 – xy2 = 0 Concept Used: Concept of factorization Calculation: We can factorize the given condition ∴ x3 – xy2 = 0 ⇒ x (x2 – y2) = 0 ⇒ x = 0, x = y and x = -y But x and y are two distinct real numbers ∴ x ≠ y So, only two possibilities x = 0 and x = -y Hence, option (4) is correct |
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| 19927. |
The effect of red light in short day plants can be nullified by (1) Orange light (2) Far red light (3) Blue light (4) All the above |
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Answer» (2) Far red light |
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| 19928. |
The volume of one litre of a gas at NTP is–(a) 11.2 L(b) 22.4 L(c) 10.2 L(d) 22.8 L |
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Answer» The volume of one litre of a gas at NTP is 22.4 L |
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| 19929. |
Which one is not affected by temperature–(a) Normality(b) Malality(c) Molarity(d) Formality |
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Answer» Malality is not affected by temperature. |
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| 19930. |
The half life period of first order reaction is 10 minutes. The rate constant for the reaction is(a) 0.693 min-1(b) 0.00693 min-1(c) 0.0693 min-1(d) 693 min-1 |
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Answer» The rate constant for the reaction is 0.0693 min-1 |
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| 19931. |
Which of the following processes is used in the extractive metallurgy of magnesium ?A. Fused salt electrolysisB. Self reductionC. Aqueous solution electrolysisD. Thermite reduction. |
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Answer» Correct Answer - A is the correct answer. |
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| 19932. |
T cells can recognise |
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Answer» T cells can detect the presence of an intracellular pathogen because infected cells display on their surface peptide fragments derived from the pathogen's proteins. These foreign peptides are delivered to the cell surface by specialized host-cell glycoproteins. |
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| 19933. |
Create a terrestrial food chain depicting four trophic levels. |
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Answer» A terrestrial food chain depicting four trophic levels is as follows- grass (producer), eaten by a mouse (primary consumer), eaten by a snake (secondary consumer), eaten by a hawk (tertiary consumer). |
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| 19934. |
Which of the following is not an ore of iron ?A. LimoniteB. MagnetiteC. CaniteriteD. None of these |
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Answer» Correct Answer - C Caniterite is not an ore of iron. |
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| 19935. |
Two metals A and B have reduction potential values - 0.76 V and + 0.34 V respectively. Which of these will liberate H2 from dil. H2 SO4 ? |
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Answer» Metal having higher oxidation potential will liberate H2 from H2 SO4 . Thus, A will liberate H2 from H2 SO4 . |
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| 19936. |
How does conc. of sulphuric acid change in lead storage battery when current is drawn from it ? |
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Answer» Concentration of sulphuric acid decreases |
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| 19937. |
Eo values of MnO4-, Ce4+ and Cl2 are 1.507, 1.61 and 1.358 V respectively. Arrange these in order of increasing strength as oxidizing agent. |
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Answer» Cl2 < MnO4 _ < Ce4+ |
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| 19938. |
The common method for the extraction of metals from the oxide ore is :A. reduction with carbonB. reduction with hydrogenC. reduction with aluminiumD. electrolytic method. |
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Answer» Correct Answer - A Metals are commonly extracted by reduction with carbon. |
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| 19939. |
Why does mercury cell gives a constant voltage throughout its life ? |
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Answer» This is because the overall cell reaction does not have any ionic can concentration in it. |
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| 19940. |
All ores are minerals while all minerals are not ores because :A. the metal cannot be extracted economically from all the mineralsB. minerals are complex compoundsC. the minerals are obtained from minesD. all of these are correct. |
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Answer» Correct Answer - A is the correct answer. |
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| 19941. |
Why does the cell potential of mercury cell remain constant throughout its life ? |
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Answer» This is because the overall cell reaction does not involve any ion in the solution whose concentration changes during its life time |
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| 19942. |
A cuprous ore among the following is :A. MalachiteB. CupriteC. AzuriteD. Chalcopyrite |
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Answer» Correct Answer - B Cuprite `(Cu_(2)O)` is the cuprous ore whereas all other ores contain copper as cupric `(Cu^(2+))`. |
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| 19943. |
Which of the following is produced in stratostrophic clouds?(a) Smog(b) Ozone hole(c) Acid rain(d) Carbon dioxide |
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Answer» (b) Ozone hole Ozone hole is produced by stratostrophic cloud |
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| 19944. |
In `psi_(321)`, the sum of angular momentum, spherical nodes and angular node isA. `(sqrt6h + 4 pi)/(2 pi)`B. `(sqrt6h)/(2pi) + 3`C. `(sqrt6h + 2pi)/(2pi)`D. `(sqrt6h + 8 pi)/(2 pi)` |
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Answer» Correct Answer - A `Psi_(321) : n = 3 , l = 2 , m = 1` Angular momentum = `(h)/(2pi) sqrt(l (l+1)) = (sqrt(6h))/(2pi)` Spherical nodes = 3 - 2 - 1 = 0, Angular node = 2 Sum of all the above = `(sqrt6 h)/(2 pi) + 2 = (sqrt6 h + 4 pi)/(2 pi)` |
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| 19945. |
Select incorrect orderA. `NH_(3) gt PH_(3) gt AsH_(3) gt SbH_(3)` (order of acidic strength)B. `S gt Se gt Te gt O` (order of electron affinity)C. `Si lt S lt P lt Cl` (order of IE)D. `S^(-2) gt Cl^(-) gt K^(1) gt Ca^(+2)` (order of radius) |
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Answer» Correct Answer - A Correct order of acidic strength is `NH_(3) lt PH_(3) lt AsH_(3) lt SbH_(3)` |
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| 19946. |
Which one of the following ions exhibit highest magnetic moment ?A. `Cu^(+2)`B. `Ti^(+3)`C. `Ni^(+2)`D. `Mn^(+2)` |
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Answer» Correct Answer - D `Cu^(2+) = [Ar] 4s^(0) 3d^(9) ( 1 "unpaired " e^(-))` `Ti^(+3) = [Ar]4s^(0) 3d^(1) ( 1 "unpaired " e^(-))` `Ni^(+2) = [Ar] 4s^(0) 3d^(8) (2 " unpaired " e^(-))` `Mn^(+2) = [Ar]4s^(0) 3d^(5) ( 5 " unpaired " e^(-))` |
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| 19947. |
A six coordination complex of formula `CrCl_(3)*6H_(2)O` has green colour. A 0.1 M solution of the complex when treated with excess of `AgNO_(3)` gave 28.7g of white precipitate. The formula of the complex would be:A. ` [Cr(H_(2)O)_(6)]Cl_(3)`B. `[CrCl(H_(2)O)_(5)]Cl_(2).H_(2) O`C. `[CrCl_(2)(H_(2)O)_(4)]Cl.2H_(2)O`D. `[Cr(H_(2)O)_(3)Cl_(3)]` |
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Answer» Correct Answer - B `Crunderset(0.1 "mol")(Cl_(3))*6H_(2)O + AgNO_(3) ("excess") to underset(28.7 g) (AgCl)` No. of moles of AgCl = `(28.7)/(143.5)` = 0.2 mol |
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| 19948. |
Which of the following statement is/are correct ? I . The ligand thiosulphate , `S_(2)O_(3)^(2-)` can give rise to linkage isomers . II. In metallic carbonyls the ligand CO molecule acts both as donor and acceptor . III. The complex `[Pt(Py)(NH_(3))(NO_(2))ClBrI]` exists in eight different geometrical isomeric forms . IV. The complex ferricyanide ion does not follow effective atomic number (EAN) rule .A. I and II onlyB. II and IV onlyC. I , II and IIID. I , II and IV |
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Answer» Correct Answer - D As `[Pt(Py)(Nh_(3))(NO_(2))ClBr]` exists in 15 different geometrical isomers, each of which would also have an optical isomer so it is incorrect. |
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| 19949. |
The density of gas `A` is twice that of B at the same temperature the molecular weight of gas B is twice that of A. The ratio of pressure of gas A and B will be :A. `1 : 6`B. `1:1`C. `4 : 1`D. `1 : 4` |
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Answer» Correct Answer - C `d_(A) = 2 d_(B) , 2 M_(A) = M_(B) `, `because PM = d RT ` `therefore (P_(A))/(P_(B)) xx (M_(A))/(M_(B)) = (d_(A))/(d_(B)) xx (RT)/(RT)` `implies (P_(A))/(P_(B)) xx (1)/(2) = 2 ` `(P_(A))/(P_(B)) = (4)/(1)` |
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| 19950. |
For the redox reaction , `MnO_(4)^(-) + C_(2)O_(4)^(-2) + H^(+) toMn^(+2) + CO_(2) + H_(2)O` the correct coefficient of reactants `MnO_(4)^(-), C_(2)O_(4)^(-2)` `H^(+)` for the balanced reaction are respectively :A. 2, 5, 16B. 16 , 3, 12C. 15 , 16 , 12D. 2 , 16 , 5 |
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Answer» Correct Answer - A The balanced redox reaction is `2MnO_(4)^(-) + 5C_(2)O_(4)^(-2) + 16H^(+) to 2 Mn^(+2) + 10 CO_(2) + 8H_(2)O` |
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