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19951.

Compare & arrange the following anlons in increasing order of ionic radius `(N^(3-),P^(3-),O^(2-),S^(2-))`A. `O^(2-)gtS^(2-)gtP^(3-)gtN^(3-)`B. `S^(2-)gtO^(2-)gtN^(3-)gtP^(3-)`C. `P^(3-)gtS^(2-)gtN^(3-)gtO^(2-)`D. `P^(3-)gtN^(3-)gtS^(2-)gtO^(2-)`

Answer» Correct Answer - C
Negative charge `prop` size.
19952.

Write general equation for preparation of ether by Williamson synthesis.

Answer»

R – X + R1ONa → R – O – R1 + NaX

19953.

Among alcohols and phenols which one is more acidic?

Answer»

The answer is phenol.

19954.

Calculate the total number of electrons present in one mole of methane.

Answer»

(i) Number of electrons present in 1 molecule of methane (CH4)
{1(6) + 4(1)} = 10
Number of electrons present in 1 mole i.e., 6.023 × 1023 molecules of methane

6.022 × 1023 × 10 = 6.022 × 1024

19955.

Complete the following equations(i) RCH2OH \(\overset{1.Alk.KmnO_4}{\underset{2.H_3O^+}{\longrightarrow}}\)(ii) CH3COONa \(\overset{NaOH.CaO}{\underset{\Delta}{\longrightarrow}}\)

Answer»

(i) RCH2OH \(\overset{1.Alk.KmnO_4}{\underset{2.H_3O^+}{\longrightarrow}}\) RCOOH

(ii) CH3COONa \(\overset{NaOH.CaO}{\underset{\Delta}{\longrightarrow}}\) CH4

19956.

Calculate the mass and charge of one mole of electrons.

Answer»

Mass of one electron = 9.10939 × 10–31 kg
Mass of one mole of electron = (6.022 × 1023) × (9.10939 ×10–31 kg)
= 5.48 × 10–7 kg
Charge on one electron = 1.6022 × 10–19 coulomb
Charge on one mole of electron = (1.6022 × 10–19 C) (6.022 × 1023)
= 9.65 × 104 C

19957.

What is Formalin solution?

Answer»

40% aqueous solution of formaldehyde.

19958.

Write the general formula of diazonium salt.

Answer»

RN2+ X R = Aryl group OR ArN/X

19959.

Name a naturally occuring amino acid which is optically inactive.

Answer»

The answer is Glycine.

19960.

At `40^(@)C` the vapour pressure of pure liquids, benzene and toluene, are `160 mm Hg` and `60 mm Hg` respectively. At the same temperature, the vapour pressure of an equimolar solution of the liquids, assuming the ideal solution will be:A. 140 mm of HgB. 110 mm of HgC. 220 mm of HgD. 100 mm of Hg

Answer» Correct Answer - B
`P_(s)=P_(B)^(@)+X_(T)(P_(P)^(@)-P_(P)^(@))=160+(1)/(2)(60-160)=160-50=110`.
19961.

Dissolving `120g` of urea `(Mw = 60)` in `1000 g` of water gave a solution of density `1.15 g mL^(-1)`. The molarity of solution is:A. 1.78 MB. 2.00 MC. 2.05 MD. 2.22 M

Answer» Correct Answer - C
`m=(1000M)/(1000d-MMw)`
`(120)/(60)xx(1000)/(1000)=(1000M)/(1000xx1.5-M(60))`
`2.30xx1000-120M=1000M`
`M=(2.30xx1000)/(1120)=2.05`
19962.

Which of the following forms strong pπ - pπ bonding?(A) S8(B) Se8(C) Te8(D) O2

Answer»

Option : (D) O2

In O2 molecule has strong pπ - pπ bond.

S8,Se8 and Te8 have only single bonds.

19963.

All elements of Group 15 show allotropy except: (a)Nitrogen (b)Arsenic (c)Antimony (d)Bismuth

Answer»

Answer is (a) Nitrogen

(due to small size and high electronegativity N-N is weak)

19964.

Solubility of gases in liquids decreases with rise in temperature because dissolution is an: (a) endothermic and reversible process (b) exothermic and reversible process (c) endothermic and irreversible process (d) exothermic and irreversible process

Answer»

Answer is (b) exothermic and reversible process

(according to Le -Chatlier principle Solubility of gases in liquids decreases with rise in temperature)

19965.

Askandan ki hardi sulje niyam kya hai

Answer»

अधिक मात्रा में वैद्युत-अपघट्य मिलाकर किसी कोलॉइडी विलयन की स्कन्दन (अवक्षेपण) क्रिया के लिए हार्डी-शुल्जे  ने निम्नलिखित दो नियम दिये, जिन्हें हार्डी-शुल्जे नियम कहते हैं |

1. कोलॉइडी विलयन के स्कन्दन के लिए मिलाये गये वैद्युत-अपघट्य के वे आयन सक्रिय होते हैं, जिनका आवेश कोलॉइडी कणों के आवेश के विपरीत होता है।

2. सॉल को स्कन्दित करने वाले आयन की शक्ति आयन की संयोजकता पर निर्भर होती है। समान संयोजकता वाले आयनों की स्कन्दित करने की शक्ति तथा मात्रा समान होती है। अधिक संयोजकता वाले आयनों की स्कन्दन क्षमता अधिक होती है, अर्थात् हार्डी-शुल्जे नियम के अनुसार, ‘आयनों की स्कन्दन शक्ति आयन की संयोजकता बढ़ने के साथ बढ़ती है।

19966.

Which of the following statement is correct: (a) Fibrous proteins are generally soluble in water (b) Albumin is an example of fibrous proteins (c) In fibrous proteins, the structure is stabilised by hydrogen bonds and disulphide bonds (d) pH does not affect the primary structure of protein.

Answer»

Answer is (d) pH does not affect the primary structure of protein.

(pH effects the tertiary structure)

19967.

Major product obtained on reaction of 3-Phenyl propene with HBr in presence of organic peroxide (a) 3- Phenyl 1- bromopropane (b) 1 –Phenyl -3- bromopropane (c) 1-Phenyl -2-bromopropane (d) 3-Phenyl -2- bromopropane

Answer»

Answer is (b) 1 – Phenyl -3- bromopropane

((C6H5)CH2CH = CH2 + HBr (organic peroxide) \(\rightarrow\) (C6H5)CH2CH2CH2Br anti-Markovnikov addition)

19968.

Covalency of nitrogen is restricted to: (a) 2 (b) 3 (c) 4 (d) 5

Answer»

Answer is (c) 4

(Covalency of nitrogen is restricted to 4 due to non availability of d orbitals)

19969.

Among the cyclic ions the aromatic character is shown by :-A. P and SB. Q and SC. Q and RD. P,Q,R and S

Answer» Correct Answer - C
19970.

Which of the following is a correct statement for C2H5Br? (a) It reacts with metallic Na to give ethane. (b) It gives nitroethane on heating with aqueous solution of AgNO2 (c) It gives C2H5OH on boiling with alcoholic potash. (d) It forms diethylthioether on heating with alcoholic KSH.

Answer»

Answer is (b) It gives nitroethane on heating with aqueous solution of AgNO2

(C2H5Br reacts with metallic Na to give butane , gives ethene on boiling with alcoholic potash. and forms C2H5SH (thiol) on heating with alcoholic KSH)

19971.

Among the cyclic ions the aromatic character is shown by :-A. P and SB. Q and SC. Q and RD. P,Q,R and S

Answer» Correct Answer - C
19972.

Chemical reaction for C2H5Br reacts with aqueous KOH

Answer»

\(C_2H_5Br + KOH(aq.) \rightarrow C_2H_5OH + KBr\\C_2H_5Br + KOH(alc.)\rightarrow C_2H_4 + KBr + H_2O\)

19973.

Number of chiral center of the given compound:- A. oneB. twoC. threeD. four

Answer» Correct Answer - C
19974.

The IUPAC name for the compound A. Ethyl acetateB. Ethyl methacrylateC. Ethyl 20methylbut-2-enoateD. Ethyl 3-methylbut-3-enoate

Answer» Correct Answer - D
19975.

The IUPAC name for the compound A. Ethyl acetateB. Ethyl methacrylateC. Ethyl 20methylbut-2-enoateD. Ethyl 3-methylbut-3-enoate

Answer» Correct Answer - D
19976.

The decreasing order of stability of following cations is :- A. QgtRgtPgtSB. SgtQgtRgtPC. SgtRgtPgtQD. RgtPgtQgtS

Answer» Correct Answer - B
19977.

The decreasing order of stability of following cations is :- A. `QgtRgtPgtS`B. `SgtQgtRgtP`C. `SgtRgtPgtQ`D. `RgtPgtQgtS`

Answer» Correct Answer - B
19978.

If equal masses of oxygen and nitrogen are placed in separate containers of equal volume at the same temperature, which one of the following statements is true ?(Mol wt. `N_2=28, O_2=32`)A. Both flasks contain the same number of moleculesB. The pressure in the nitrogen flask is greater than in the oxygen flask.C. More molecules are present in the oxygen flaskD. Molecules in the oxygen flask are moving faster on the average than the ones in the nitrogen flask

Answer» Correct Answer - B
`PV=nRT implies P=(nRT)/V implies n_(N_2)gtn_(O_2)implies P_(N_2)gtP_(O_2)`
19979.

A mixture of carbon monoxide and carbon dioxide is found to have a density of 1.7g/lit at S.T.P. The mole fraction of carbon monoxide isA. 0.37B. `0.40`C. `0.30`D. `0.50`

Answer» Correct Answer - A
`M_("mix")=(dRT)/P_("mix")implies M_("mix")=(1.7xx0.0821xx273)/1=1.7xx22.4` gms
`M_("mix")=X_(CO)xxM_(CO)+(1-X_(CO).M_(CO_2)=X_(CO)xx18+(1-X_(CO))xx44 implies X_(CO)=0.37`
19980.

At a certain temperature for which RT=25 lit.atm. `"mol"^(-1)`., the density of a gas, in gas `lit^(-1)`, is d=2.00 P+0.020 `P^2`, where P is the pressure in atmosphere.The molecular weight of the gas in gm `"mol"^(-1)` isA. 25B. 50C. 75D. 100

Answer» Correct Answer - B
Lt `d/p=M/(RT)implies M=2RT=50`
`Pto0`
19981.

The volume occupied by 2.0 mole of `N_2` at 200 K and 8.21 atm pressure, if `(P_CV_C)/(RT_C)=3/8 and (P_rV_r)/T_r=2.4`, isA. 1.8 LB. `(5/8)` LC. 12.8 LD. 3.6 L

Answer» Correct Answer - D
`(P_rV_r)/T_r=P/T_c V_m/V_c.T_c/T=(PV_m)/(RT).(RT_C)/(P_CV_C)`
`(PV_m)/(RT)=2.4xx(3/8)`
So `V_m=(0.0821xx200)/8.21xx0.9=1.82` So Volume of 2 moles =3.6 L
19982.

`SO_2 and CH_4` are introduced in a vessel in the molar ratio 1:2.The ratio of molecules of two gases present in the container when their rate of effusion becomes equal is :A. `1:2`B. `2:1`C. `4:1`D. `1:4`

Answer» Correct Answer - B
`r=prop p/sqrtM`
`p_1/sqrtM_1=p_2/sqrtM_2`
`p_1/p_2=sqrtM_1/sqrtM_2=n_1/n_2 implies n_(SO_2)/n_(CH_4)=sqrt(M_(SO_2)/M_(CH_4))=sqrt(64/16)=2`
19983.

Three gases A,B and C are at same temperture if their r.m.s speed are in the ratio 1:`1/sqrt2:1/sqrt3` then their molar masses will be in the ratio :A. `1:2:3`B. `3:2:1`C. `1:sqrt2:sqrt3`D. `sqrt3:sqrt2:1`

Answer» Correct Answer - A
`V_("rms")^2=(3RT)/(M)`
`V_A:V_B:V_C=1:1//sqrt2:1//sqrt3`
`V_A^2:V_B^2:V_C^2=1:1//2:1//3`
`1/M_A:1/M_B:1/M_C=1:1/2:1/3`
`M_A:M_B:M_C=1:2:3`
19984.

Identify the monosaccharide containing only one asymmetric carbon atom in its molecule.A. RibuloseB. RiboseC. ErythroseD. Glyceraldehyde

Answer» Correct Answer - D
`H-overset(CHO)overset(|)underset(CH_(2)OH) underset(|)C-OH`
Asymmetric atom glyceraldehyde
19985.

Identify the oxidation states of titanium (Z=22) and copper (Z=29) in their colourless compounds.A. `Ti^(3+), Cu^(2+)`B. `Ti^(2+), Cu^(2+)`C. `Ti^(4+), Cu^(1+)`D. `Ti^(4+), Cu^(2+)`

Answer» Correct Answer - C
`Ti : [Ar] 4s^(2) 3d^(2), Cu:[Ar] 4s^(1) 3d^(10)`
`Ti^(+4): [Ar] 4s^(0) 3d^(0), Cu^(+1): [Ar] 4s^(0) 3d^(10)`
19986.

With which halogen the reactions of alkanes are explosives?A. FluorineB. ChlorineC. BromineD. Iodine

Answer» Correct Answer - A
`R-H +F_(2) overset("dark")to R-F + HF`
Highly exothernmic
19987.

In case of R,S configuration the group having highest priority isA. `-NO_(2)`B. `-NH_(3)`C. `-CN`D. `-OH`

Answer» Correct Answer - D
Atomic mass of oxygen is more than that of C and N
19988.

Lactic acid and glycolic acid are the monomers used for preparation of polymerA. Nylon -2-nylon -6B. DextronC. PHBVD. Buna-N

Answer» Correct Answer - B
`underset("Lactic acid")(HO -underset(CH_(3))underset(|)overset(H)overset(|)C-COOH) + HO - underset("glycolic acid")(CH_(2) - COOH) to underset("Dextron")[[O-underset(CH_(3))underset(|)(CH)-overset(O)overset(||)C-O-CH_(2) -overset(O)overset(||)C]]-+nH_(2)O`
19989.

For 10 minutes each, at `0^(@)C`, from two identical holes nitrogen and an unknown gas are leaked into a common vessel of 4 litre capacity. The resulting pressure is 2.8 atm and the mixture contains 0.4 mole of nitrogen. What is the molar mass of unknown gas ? (Take `R = 0.821 "L-atm mol"^(-1)K^(-1)`]A. `448 g mol^(-1)`B. `224 g mol^(-1)`C. `226 g mol^(-1)`D. None of these

Answer» Correct Answer - A
`n_(N_2)/n_x=sqrt(m_x/M_(N_2))`…(i)
`P_TV_P=n_T RT`..(ii)
`n_T=(2.8xx4)/(0.0821xx273)=0.5`
`n_x+n_(N_2)=0.5`
`n_x=0.1`
From (1)
`0.4/0.1=sqrt(M_x/28),M_x=448`
19990.

From two identical holes, nitrogen and an unknown gas are leaked into a common vessel of `3 L` capacity for `10 min`, at `27^(@)C`. The resulting pressure is `4.18` bar and the mixture contains `0.4 mol` of nitrogen. What is the molar mass of the unknown gas?

Answer» Calculate of the number of moles of the unknown gas
`P=4.18 "bar"=4.18xx0.987=4.12 atm`
`V=3 L, T=27+273=300 K`
`R=0.0821 L "bar" K^(-1) mol^(-1)`
Total number of moles of the two gases can be calculated with the help of ideal gas equation.
`PV=nRT` or `n=(PV)/(RT)`
`n=((4.12 "atm")xx(3L))/((0.082 L "atm" K^(-1) "mol"^(-1))xx300K)=0.503 "mol"`
`r_(N_(2))=0.4/10 mol min^(-1), n_(gas)=0.5-0.4=0.1`
`r_(gas)=0.1/10 mol min^(-1)`
`r_(N_(2))/r_(gas)=sqrt(M_(gas)/M_(N_(2)))`,
`0.04/0.01=sqrt(M_(gas)/28)`
`(4xx4xx28)/(1xx1)=M_(gas) rArr M_(gas)=448`
19991.

A particle starts from rest from point P and follow a path PQ on the three smooth surfaces as shown in figures. If time taken by the particle in three cases are `t_(1), t_(2)` and `t_(3)` then A. `t_(1) gt t_(2) gt t_(3)`B. `t_(3) gt t_(2) gt t_(1)`C. `t_(3) gt t_(1) gt t_(3)`D. `t_(1) = t_(2) = t_(3)`

Answer» Correct Answer - B
`L = (H)/(sin theta) = (1)/(2)g sin theta xx t^(2)`
19992.

A metallic circular disc having a circular hole at its centre rotates about an axis passing through its centre and perpendicular to its plane. When the disc is heated:A. its moment of inertia increasesB. its angular velocity increases.C. its angular velocity decreasesD. its diameter increases.

Answer» Correct Answer - A::B::C
As the disc is heated the diamter of the hole as weill as the disc increases due to thermal expansion. Consequently the moment of inertial increases. From conservation of angular momentum `I_(1)omega_(1)=I_(2)omega_(2)` angular velocity decreases due to increase in moment of inertia.
19993.

A metallic circular disc having a circular hole at its centre rotates about an axis passing through its centre and perpendicular to its plane. When the disc is heated, choose the wrong statementA. its speed will decreaseB. its diameter will decreaseC. its moment of inertia will increaseD. angular momentum will increase

Answer» Correct Answer - B::D
No external force, momentum will remain corses
19994.

Which of the following is NOT a nocturnal animal?1. Bat2. Rabbit3. Mouse4. Cockroach

Answer» Correct Answer - Option 2 : Rabbit

The correct answer is Rabbit.

  • Nocturnal animal
    • An animal behaviour where it is active during the night and sleeping during the day.
    • The common understanding is "nocturnal", versus diurnal meaning the opposite.
    • Examples-
      • Owls
      • Bats
      • Raccoon
      • Badger
      • Mouse
      • Cockroach
      • Moth
      • Firefly
      • Loris
      • Pangolins
      • Kibi
      • Wildcat 
19995.

Which kitchen product will help to neutralise a bee sting?1. Salt2. Lemon juice3. Baking soda4. Pepper

Answer» Correct Answer - Option 3 : Baking soda

The correct answer is Baking soda.

  • Baking soda will help to neutralise a bee sting.

  • Other Kitchen Remedies:
    • Cool compress - The cold decreases the swelling and redness.
    • Apple cider vinegar – It can neutralize the venom like baking soda.
    • Honey – The anti-oxidants in it may help with wound healing and pain - similar to its healing tendency for allergies.
    • Meat tenderizer - An enzyme in the seasoning counteracts the toxicity of the venom.
19996.

Which of the following herbs grows from the stem?1. Mint2. Cilantro3. Bill4. Parsley

Answer» Correct Answer - Option 1 : Mint

The correct answer is Mint.

  • Mint herb grows from the stem.

  • Herb
    • It has a short-sized plant with a soft, green stem without woody tissues.
    • Cycle - One or two seasons.
    • Branches -  few branches or branchless.
    • It is easily uprooted from the soil.
    • Nutritional benefits - Vitamins and minerals.
    • Examples - Tomato, wheat, paddy, grass and bananas.
19997.

The fear of night or darkness is known as ___________.1. Cherophobia2. Nyctophobia 3. Autophobia4. Hodophobia

Answer» Correct Answer - Option 2 : Nyctophobia 

The correct answer is Nyctophobia.

  • Nyctophobia is the extreme fear of night or darkness.

​ 

  • Cherophobia- It is the fear or phobia of being happy.
  • Autophobia- It is the fear of being alone.
  • Hodophobia- It is the fear of traveling or of Journey
19998.

The fear of confined or crowded spaces is known as ____________.1. Claustrophobia2. Astraphobia3. Ophidiophobia4. Acrophobia

Answer» Correct Answer - Option 1 : Claustrophobia

The correct answer is Claustrophobia.

  •  The fear of confined or crowded spaces is known as Claustrophobia.

  • The fear of thunder and lightning is known as Astraphobia.
  • The fear of snakes is known as Ophidiophobia.
  • The fear of heights is known as Acrophobia.
19999.

Rewrite the following sentences by using the correct homophones for the underlined words:1. Your excuse is excepted, you may go and sit in your place.2. The government often adopted policies that made the poor and middle-class people to suffer.3. My mother’s aid made a lot of different dishes and surprised us.4. Are you all ready for the show?5. Many experts believe it may be too late to prevent averse consequences to the world’s climate system.

Answer»

1. Your excuse is accepted, you may go and sit in your place.

2. The government often adopted policies that made the poor and middle-class people to suffer.

3. My mother’s aide made a lot of different dishes and surprised us.

4. Are you all ready for the show?

5. Many experts believe it may be too late to prevent adverse consequences to the world’s climate system.

20000.

The branch of physics which deals with the study of sound is called ________.1. Numismatics2. Acoustics3. Phonology4. Kymatology

Answer» Correct Answer - Option 2 : Acoustics

The correct answer is Acoustics.

  • Acoustics is the branch of physics that is concerned with the study of sound.

  • Numismatics is the study of coins and other currency units.
  • Phonology is the study of sound structure in language. 
  • Kymatology is the study of waves or wave motions.

  • Phonology is used for the sound structure of words in language i.e. how a word is to pronounced.
  • Acoustics is the branch of physics that is concerned with the study of sound i.e. properties of sound, sound waves and their motion, etc.