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At `40^(@)C` the vapour pressure of pure liquids, benzene and toluene, are `160 mm Hg` and `60 mm Hg` respectively. At the same temperature, the vapour pressure of an equimolar solution of the liquids, assuming the ideal solution will be:A. 140 mm of HgB. 110 mm of HgC. 220 mm of HgD. 100 mm of Hg |
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Answer» Correct Answer - B `P_(s)=P_(B)^(@)+X_(T)(P_(P)^(@)-P_(P)^(@))=160+(1)/(2)(60-160)=160-50=110`. |
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