Saved Bookmarks
| 1. |
The electric field intensity at point near and outside the surface of a charged conductor of any shate is `E_(1)` the elecric field intensity due to uniformly charged conductor of any shape is `E_(1)` the electric field intensity due ot uniformly charged infinite thin plane sheet is `E_(2)` the relation between `E_(1)` and `E_(2)` isA. `2E_(1)=E_(2)`B. `E_(1)=E_(2)`C. `E_(1)=2E_(2)`D. `E_(1)=4E_(1)` |
|
Answer» Correct Answer - b Electric field intensity at a point near and outside the surface of any charged conductor is given by `E_(1)=(sigma)/(epsilon_(0))` where `sigma` is charge density (charge per unit area) at a point Electric field intensity due to uniformly charged infinite thin plane sheet is givne by `E_(2)=(sigma)/(2 epsilon_(0))` from eqs (i) and (ii) we have `e_(1)=2/2xx(sigma)/(epsilon_(0))=2xxE_(2)rarrE_(1)=2E_(2)` |
|