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In `psi_(321)`, the sum of angular momentum, spherical nodes and angular node isA. `(sqrt6h + 4 pi)/(2 pi)`B. `(sqrt6h)/(2pi) + 3`C. `(sqrt6h + 2pi)/(2pi)`D. `(sqrt6h + 8 pi)/(2 pi)` |
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Answer» Correct Answer - A `Psi_(321) : n = 3 , l = 2 , m = 1` Angular momentum = `(h)/(2pi) sqrt(l (l+1)) = (sqrt(6h))/(2pi)` Spherical nodes = 3 - 2 - 1 = 0, Angular node = 2 Sum of all the above = `(sqrt6 h)/(2 pi) + 2 = (sqrt6 h + 4 pi)/(2 pi)` |
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