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For a `1^(st)` order reaction (gaseous) (constant V, T) : `aAto(b-1)B+1 C` (with `bgta`) the pressure of the system rose by `50(b/a-1)` % in a time of 10 min. The half life of the reaction is therefore.A. 10 minB. 20 minC. 30 minD. 40 min |
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Answer» Correct Answer - A `{:(aA,to,(b-a)B,+C),(t=0,P_0,0,0),(t=t,P_3x,((b-a)x)/a,x/a):}` Total pressure `P_0-x+b/ax=P_0+(b/a-1) 1/2 P_0` `P_0+(b/a-1)x=P_0+(b/a-1)P_0/2` `x=P_0/2` `P_A=P_0-x=P_0-P_0/2=P_0/2` `P_A` reduces to half in 10 min, so `t_(t//2)`=10 min |
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