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Calculate the mass of hydrochloric acid in 200 cm3 of 0.2 N solution of it. What volume of this acid solution will react exactly with 25 cm3 of 0.14 N solution of sodium hydroxide? |
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Answer» Normality of hydrochloric acid = 0.2; Eq. mass of hydrochloric acid = 36.5 Mass of hydrochloric acid in one dm3 of the solution is given by W = N × E = 0.2 × 36.5 g ∴ mass of hydrochloric acid in 200 cm3 of the solution = 0.2 x 36.5/5 = 1.46 g V1 x N1 = V2 x N2 Acid Base Substituting we have V1 × 0.2 = 25 × 0.14 ∴ V1 = 25 x 0.14/0.2 = 17.5 cm3 |
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