1.

Calculate the mass of hydrochloric acid in 200 cm3 of 0.2 N solution of it. What volume of this acid solution will react exactly with 25 cm3 of 0.14 N solution of sodium hydroxide?

Answer»

Normality of hydrochloric acid = 0.2; 

Eq. mass of hydrochloric acid = 36.5

Mass of hydrochloric acid in one dm3 of the solution is given by 

W = N × E = 0.2 × 36.5 g

∴ mass of hydrochloric acid in 200 cm3 of the solution = 0.2 x 36.5/5 = 1.46 g

V1 x N1 = V2 x N2 

Acid       Base

Substituting we have V1 × 0.2 = 25 × 0.14

∴ V1 = 25 x 0.14/0.2 = 17.5 cm3



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