This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 17801. |
Assertion: `0.1 M NaCN+0.05 M HCl` solution on mixing in equal volume forms a buffer solution. Reason : The solution after mixing contains a weak acid and its conjugate base and thus acts as buffer.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertiion.C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False |
| Answer» Correct Answer - A | |
| 17802. |
One mixing `500 mL` of `10^-6 M Ca^(2+)` ion and `500 mL` of `10^-6 MF^-` ion, no precipitate of `CaF_2` will be obtained. `K_(sp) (CaF_2 = 10^-18)`. If `K_(sp)` is greater than ionic product, a percipitate will develop.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertiion.C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False |
| Answer» Correct Answer - C | |
| 17803. |
Assertion : The `pH` of pure water is less than `7` at `60^(@)C`. Reason : As the temperature increases, pure water becomes slightly acidic.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertiion.C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False |
| Answer» Correct Answer - C | |
| 17804. |
For which of the following salt pH of its aqueous solution is independent of concentration of salt.A. `Na_(2)HPO_(3)`B. `NaH_(2)PO_(2)`C. `CH_(3)COONH_(4)`D. `CH_(3)COONa` |
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Answer» Correct Answer - C `2AB_(2)iff2AB +B_(2)` `"1 0 0"` `"1-x x "x//2` Total moles at equilibrium = `1 + (x)/(2)` `k_(p)=(((x)/(1+x//2)xxP)^(2)((x//2)/(1+x//2)xxP))/(((1-x)/(1+x//2)xxP)^(2)), k_(p)=(x^(3)P)/(2) " , "x^(3)=(2k_(p))/(P)implies x=((2k_(p))/(P))^(1//3)` |
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| 17805. |
If pH of an acidic indicator solution when `50%` ionized is 2. Calculate % of basic form in the solution when `[H^(+)]` = `5xx10^(-3)` in solution at same temperatureA. `33.33%`B. `66.66%`C. `50%`D. `75%` |
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Answer» Correct Answer - D `AlF_(3) rarr` ionic solid (following octet rule) `PCl_(3).NH_(4)^(+)rarr` following actet rule `SF_(4) rarr` Hypervalent `(10e^(-))` |
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| 17806. |
Order of rate of electrophilic substitution reaction is : A. `1gt2gt3gt4`B. `4gt3gt2gt1`C. `2gt1gt4gt3`D. `2gt1gt3gt4` |
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Answer» Correct Answer - B `h=sqrt((kw)/(k_(b)xxc))=sqrt((10^(-14))/(10^(-5)xx0.1))=10^(-4)` |
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| 17807. |
Which one of the following characteristics belongs to an electrophile?A. It is any species having electron deficiency, which reacts at an electron rich C-centreB. It is any species having electron enrichment, that reacts at an electron deficient C-centreC. It is cationic in natureD. It is anionic in nature |
| Answer» Correct Answer - A | |
| 17808. |
Carbocation as an intermediate is likely to be formed in the reaction :A. `"Hexene"overset("Anhyd. AlCl"_(3)//HCl)rarr"2-chloro-2-methylpentane"`B. `"Propene"+Cl_(2)overset(hv)rarr"2-chloropropane"`C. `"Ethyl bromide"+KOH(aq.)overset(Delta)rarr"ethyl alcohol"`D. `"Acetone + HCN"overset(.^(-)OH)rarr"acetonecyanohydrin"` |
| Answer» Correct Answer - A | |
| 17809. |
Which of the following `pK_(a)` values, represents the strongest acid?A. `10^(-4)`B. `10^(-8)`C. `10^(-5)`D. `10^(-2)` |
| Answer» Correct Answer - D | |
| 17810. |
The heat of atomization of a compound `XY_(3)` in gaseous state is E kJ `mol^(-1)` what is the X-Y bond energy of kJ `mol^(-1)` unit?A. `E`B. `3E`C. `(E)/(3)`D. `(E)/(6)` |
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Answer» Correct Answer - C `XY_(3)(g)toX(g)+3Y(g):DeltaH=E` kJ `mol^(-1)` `therefore` B.E of `XY=(E)/(3)` as `XY_(3)` contains three X-Y bonds. |
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| 17811. |
`P(g)+2Q(g)toPQ_(2)(g),DeltaH=18kJmol^(-1)` The entropy change of the above reaction `(DeltaS_("system")` is 60 `JK^(-1)mol^(-1))`. At what temperature the reaction becomes spontaneous?A. Below 200 KB. Above 300 KC. Below 300 KD. Above 200 K and below 300 K. |
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Answer» Correct Answer - B For spontaneous process `DeltaGlt0` `thereforeDeltaH-TDeltaSlt0,DeltaHltTDeltaS` `thereforeTgt(DeltaH)/(DeltaS)=(18000)/(60)=300K` |
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| 17812. |
Solubility product of `BaCl_(2)` is `4xx10^(-9)`. Its solubility in moles//litre would beA. `4xx10^(-3)`B. `3.2xx10^(-9)`C. `10^(-3)`D. `1xx10^(-9)` |
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Answer» Correct Answer - C `KsP=45^(3)=4xx10^(-9)rArr5=10^(-3)` |
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| 17813. |
Which of the following represent(s) bidentate ligand(s)?A. `o x^(-2)`B. `gly^(-)`C. dienD. `acac^(-)` |
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Answer» Correct Answer - A::B::C Oxalato, glycinato, acetylacetonato are bidentate ligands. Dien stands for dietheylenetriamine, a tridentate ligand. |
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| 17814. |
Calculate the entropy change for vaporization of water if latent heat of vaporization for water is 2.26 kJ/gram. The `K_(b)` for `H_(2)O` is 0.51 K/molalityA. 26.33cal/moleB. 23.33cal/moleC. 1KJ/moleD. 30cal/mole |
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Answer» Correct Answer - A `DeltaS_(V)=(RT_(b)M)/(1000K_(b))` |
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| 17815. |
Suppose that in any Bohr atom or ion orbits are only in even number like 2, 4, 6……. The maximum wavelength of radiation emitted in the visible region of gydrogen spectrum should be,A. `4//R`B. `R//4`C. `36//5R`D. `16//3R` |
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Answer» Correct Answer - D `E alpha (1)/(lambda)` Maximum wavelength radiation means minimum energy radiation which is emitted when transition occurs from `4 rarr 2`. `(1)/(lambda) = R((1)/(4) - (1)/(16))` |
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| 17816. |
Compound which is added to soap to impart antiseptic properties isA. sodium laurylsulphateB. sodium dodecylbenzenesulphonateC. RosinD. Bithional |
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Answer» Correct Answer - D Bithionol/Bithional is added to the toilet wsoap to remove the bad odour produced by bacterial decomposition of organic matter on the skin. |
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| 17817. |
1.0 mole of Fe reacts completely with 0.65 mole of `O_(2)` to give a mixture of only FeO and `Fe_(2)O_(3)` the mole ratio of ferrous oxide to ferric oxide isA. `2:2`B. `4:3`C. `1:2`D. `2:7` |
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Answer» Correct Answer - B `underset("a mole")(2Fe)+underset((a)/(2)"mole")(O_(2))tounderset(a)(2FeO)` `underset(b)(4Fe)+underset((3b)/(4))(3O_(2))tounderset((b)/(2))(2Fe_(2)O_(3))` `thereforea+b=1` `(a)/(2)+(3b)/(4)=0.65` `thereforea=0.4` mole `b=0.6` mole `therefore` moles of `FeO=0.4` moles of `Fe_(2)O_(3)=0.3` `therefore` ratio `=4:3` |
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| 17818. |
Mark the correct statements(s) regarding AzeotropesA. At azeotropic composition, vapour phase composition is same as the liquid phase composition.B. Water and `HNO_(3)` can form minimum boiling azeotrope.C. Azeotropes are formed by non-ideal solution.D. Boiling point of azeotropic solutions does not change while boiling thhe solution at constant external pressure. This bahavious is similar to ideal solution. |
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Answer» Correct Answer - B::C Water and `HNO_(3)` solution shows negative deviation from raoults law and forms maximum boiling azeotrope at a particular composition. Azeotropes are constant boiling mixtures but boiling point of ideal solution changes while boiling. In ideal solution, vapor phase becomes richer in more volatile component,vapour pressure of remaining solution decreases and hence BP increases continuously while boiling. |
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| 17819. |
Which of the following IUPAC names(s) is/are not correctly matched with its formula?A. Dichloridobis(ethane-1,2-diamine)cobalt(III) ion: `[CoCl_(2)(en)_(2)]^(+)`B. Sodium (ethylenediaminetetraacetato)chromate(II): `Na_(2)[Cr(en)(CH_(3)COO)_(4)]`C. Tris(bipyridyl)iron(II) ion: `[Fe(NH_(4)C_(5)-C_(5)H_(4)N)_(3)]^(2+)`D. Ammineaquadibromidocopper(II): `[Cu(NH_(3))(H_(2)O)Br_(2)]` |
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Answer» Correct Answer - A (A). `Na_(2)[Cr(edta)]` is te correct formula for given name. |
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| 17820. |
Which of the following ion has the highest coagulation power for the sol. Which is obtained by the following reaction? `FeCl_(3)("excess")+NaOHtoSol`A. `Al^(3+)`B. `SO_(4)^(2-)`C. `l^(-)`D. `Na^(+)` |
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Answer» Correct Answer - B The sol becomes positively charged dur to excess of `Fe^(3+)` ions. |
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| 17821. |
the overall charge present on the cyclic silicate anion `[Si_(6)O_(18)]^(n-)` is:A. 6B. 12C. 18D. 24 |
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Answer» Correct Answer - B Given silicate anion is `[(SiO_(3))^(2-)]_(6)` `:. n = 12` |
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| 17822. |
In the dissociation of N2O4 into NO2, (1+x) varies with the vapour densities ratio D/d as given by |
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Answer» Correct answer: (D) |
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| 17823. |
Which of the following statement is correct about the cyclic silicate `[Si_(6)O_(18)]^(n-)`?A. the value of n is 12B. each Si atom is bonded with three oxygen atomsC. each oxygen atom is bonded with two Si atomsD. All of these |
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Answer» Correct Answer - A A |
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| 17824. |
A system works under cyclic process as follow Heat absorbed during the process isA. `(22)/(7)xx10^(2)J`B. `(22)/(7)xx10^(3)J`C. `(22)/(7)xx10^(4)J`D. `(22)/(7)xx10^(5)J` |
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Answer» Correct Answer - A for cyclic process, du=0 as `q=-ve` `therefore` work is done by the system `thereforeq=-w=` area occupied by circle `=pir^(2)=(22)/(7)xx10^(2)` |
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| 17825. |
What is the unit of rate constant of the reaction for which the above graph is given?A. `s^(-1)`B. `molL^(-1)s^(-1)`C. `molL^(-1)s`D. `mol^(-1)L^(2)s^(-1)` |
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Answer» Correct Answer - B It is a zero order reaction |
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| 17826. |
Which of the following is a colourless complex ion?A. `[Cu(NH_(3))_(4)]^(2+)`B. `[Cr(H_(2)O)_(6)]^(3+)`C. `[FeF_(6)]^(3-)`D. `[Mn(H_(2)O)_(6)]^(3+)` |
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Answer» Correct Answer - C Due to stable `t_(2g)^(2)e_(g)^(2)` configuration of `Fe^(3+)` ion. |
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| 17827. |
Which of the following metallurgical process is not needed in order to extract Zn from `ZnCO_(3)`?A. CalcinationB. RoastingC. Carbon reductionD. Distillation. |
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Answer» Correct Answer - B Roasting is carried out for sulphide ores. |
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| 17828. |
A five digit number divisible by 3 has to be formed using the numerals 0,1,2,3,4 and 5 without repetition. What is the total number of ways in which this can be done? |
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Answer» A five digit number is divisible by 3 if the sum of the digits constituting the number is divisible by 3. On mental summing up we see that 1,2,3,4,5 is a group and 0,1,2,4,5 another group. First group can form 5! =120 numbers which are divisible by 3 And effective 5 digit number formed by 2nd group will be 5!-4!=96, where 4! is the number of numbers which start with zero. So neglected. Hence required number of 5 digit numbers divisible by 3 is (120+96)=216 |
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| 17829. |
For the equilibrium in a closed vessel`" "PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g)`, `K_(p)` is found to be double of `K_(e)` . This is attained when `:`A. `T=24.36K`B. `T=12.18K`C. `T=36.54K`D. `T=27.3K` |
| Answer» Correct Answer - C | |
| 17830. |
The first and second dissociation constants of a weak diacidic base `B(OH)_(2)` are `1xx10^(-7)` and `1.3xx10^(-14)` respectively. Approximate pH of `0.1M` solution of this base isA. `10`B. `11`C. `8`D. `12` |
| Answer» Correct Answer - A | |
| 17831. |
predict the product.A. B. C. D. |
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Answer» Correct Answer - A Nitrous acid reaction with `2^(@)` amine. |
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| 17832. |
Which of the following salt can increase te boiling point of water by maximum extent? (Assume equimolar quantities are added) (Assume complete dissociation of the salts)A. `NaCl`B. `CaCl_(2)`C. `AlCl_(3)`D. `KCl` |
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Answer» Correct Answer - C It produces maximum number of ions as compared to other salts. |
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| 17833. |
Find the sum of the series 0.9 + 0.91+ 0.92+....to 100 terms |
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Answer» The given series is in A.P, a=0.9, d=0.91-0.90=0.01, n=100 a100 = a1+(n−1)d a100 = 0.9+(100-1)*0.01 a100 = 0.9+99*0.01 a100 = 0.9+0.99 a100 = 1.89 S100 = n(a1+an)/2 S100 = 100(0.9+1.89)/2 S100 = 139.5 Therefore sum of 100 terms of the given series is 139.5 |
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| 17834. |
What is the median of 7, 3, 5, 8, 6, 10, 9, 12(a) 8 (b) 7 (c) 6 (d) 7.5 |
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Answer» What is the median of 7, 3, 5, 8, 6, 10, 9, 12 7.5 |
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| 17835. |
Volume of cuboid |
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Answer» Volume of the cuboid = (length × breadth × height) |
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| 17836. |
The perimeter of the base of square pyramid is 40 centimetres and the total length of all its edges is 92 centimetres. Calculate its surface area. |
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Answer» Base perimeter = 4a = 40 a = 10cm Total length of edges = 92 cm Length of total laterals edge = 92 – 40 = 52 Length of one laterals edge = \(\frac{52}{4}\) = 13 cm Slant height of lateral surfaces is l = \(\sqrt{13^{12} - 5^2}\) = \(\sqrt{169-25}\) = \(\sqrt{144}\) = 12 cm Surface area of pyramid = Base area + 2 x Perimeter of base x length of slant height of lateral surfaces = a2 + 1/2 pl = 102 + 1/2 x 40 x 12 = 100 + 240 = 340 cm2 OR Surface area of pyramid = a2 + 2 al = 102 + 2 × 10 × 12 = 100 + 240 = 340 cm2 |
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| 17837. |
The volume of a solid right circular cone is 4928 cm3. If its height is 24 cm, them find the radius of the cone. |
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Answer» V = 4928 cm3 and h = 24 cm Thus, \(\frac{1}{3}\pi r^2h=4928\) r2 = 196 \(\Rightarrow\) r = 14cm |
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| 17838. |
The figure given below has the total length 20cm height and common diameter 6cm. Find the volume of the figure. |
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Answer» volume of solid = \(\frac{2}{3}\pi r^3+r^2h+\frac{1}{3}\pi r^2h\) = \(\frac{2}{3}\pi\times3^3+\pi\times3^2\times12+\frac{1}{3}\pi\times3^2\times5\) = \(18\pi+108\pi+15\pi\) = \(141\pi\) cm3 |
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| 17839. |
Calculate the surface area and volume of a sphere of radius 3 cm. |
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Answer» Surface area of sphere = 4 π (3)2 = 36π cm2 Volume = \(\frac{4}{3}\pi r^3\) = \(\frac{4}{3}\times\pi\times(3)^3\) = 36π cm3 |
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| 17840. |
Calculate the volume of a sphere of surface area 144 π square centimetre. |
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Answer» \(4\pi r^2=144\pi,\) \(r^2=\frac{144}{4}=36,\) r = 6 cm Volume of sphere = \(\frac{4}{3}\pi r^3\) = \(\frac{4}{3}\times\pi\times(6)^3=288\pi\) cm3 |
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| 17841. |
In a photoelectric experiment, the frequency and intensity of a light source are both doubled. Then consider the following statements. (i) The saturation photocurrent remains almost the same. (ii) The maximum kinetic energy of the photoelectrons is doubled.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1.B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is False, Statement-2 is TrueD. Statement-1 is False, Statement-2 is False |
| Answer» The number of photons incident per unit time remains same hence saturation photo current remains same. If frequency is doubled then kinetic energy of photo electrons is more than doubled. | |
| 17842. |
(d/dx) [sin-1 x] = ?(a) 1/√(1 - x2)(b) -1/√(1 - x2)(c) 1/√(1 + x2)(d) √(1 - x2) |
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Answer» Answer is (a) 1/√(1 - x2) |
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| 17843. |
∫secx dx=?(a) log|secx|+c (b) log|secx+tanx|+c (c) log|secx-tanx|+c (c) secx tanx+c |
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Answer» (b) log|secx+tanx|+c |
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| 17844. |
(d/dx)[sin2 x] = ?(a) 2 sin x cos x (b) 2 sin x (c) cos2 x (d) sin x cos x |
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Answer» Answer is (a) 2 sin x cos x |
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| 17845. |
If A=[(1,2,3),(4,5,6)], then which one of the following is equal to A'?(a) [(2,1,3),(5,4,6)] (b) [(4,5,6),(1,2,3)] (c) [(1,4),(2,5),(3,6)] (d) [(3,6),(2,5),(1,4)] |
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Answer» (c) [(1,4),(2,5),(3,6)] |
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| 17846. |
Integrating factor (I.F.) of the differential equation (dy/dx) - y cos x = sin x cos x(a) e-sin x (b) esin x(c) e- cos x (d) ecos x |
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Answer» Answer is (a) e-sin x |
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| 17847. |
An objective function in general LPP is(A) Linear function(B) Constant function(C) Non-collinear function(D) None of these |
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Answer» (A) Linear function |
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| 17848. |
Give the relationship between molecular mass and density of a gas. |
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Answer» The relationship between molecular mass and density of a gas. d = PM/RT |
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| 17849. |
In ΔABC, ∠A = 125°,BC = 8 cm. Find the diameter of the circumcircle. |
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Answer» Draw diameter BD and jon CD. In ΔBCD, sin55° = \(\frac{BC}{BD}\) BD = \(\frac{BC}{sin\,55^\circ}=\frac{8}{0.82}=9.76\) |
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| 17850. |
P(A) + P(A') = ?(a) 0 (b) 1 (c) -1 (d) P(E) |
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Answer» Answer is (a) 0 |
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