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Solubility product of `BaCl_(2)` is `4xx10^(-9)`. Its solubility in moles//litre would beA. `4xx10^(-3)`B. `3.2xx10^(-9)`C. `10^(-3)`D. `1xx10^(-9)` |
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Answer» Correct Answer - C `KsP=45^(3)=4xx10^(-9)rArr5=10^(-3)` |
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