1.

Solubility product of `BaCl_(2)` is `4xx10^(-9)`. Its solubility in moles//litre would beA. `4xx10^(-3)`B. `3.2xx10^(-9)`C. `10^(-3)`D. `1xx10^(-9)`

Answer» Correct Answer - C
`KsP=45^(3)=4xx10^(-9)rArr5=10^(-3)`


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