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Find the sum of the series 0.9 + 0.91+ 0.92+....to 100 terms |
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Answer» The given series is in A.P, a=0.9, d=0.91-0.90=0.01, n=100 a100 = a1+(n−1)d a100 = 0.9+(100-1)*0.01 a100 = 0.9+99*0.01 a100 = 0.9+0.99 a100 = 1.89 S100 = n(a1+an)/2 S100 = 100(0.9+1.89)/2 S100 = 139.5 Therefore sum of 100 terms of the given series is 139.5 |
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