1.

Find the sum of the series 0.9 + 0.91+ 0.92+....to 100 terms

Answer»

The given series is in A.P,

a=0.9,

d=0.91-0.90=0.01,

n=100

a100 = a1+(n−1)d

a100 = 0.9+(100-1)*0.01

a100 = 0.9+99*0.01

a100 = 0.9+0.99

a100 = 1.89

S100 = n(a1+an)/2

S100 = 100(0.9+1.89)/2

S100 = 139.5

Therefore sum of 100 terms of the given series is 139.5



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