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In ΔABC, ∠A = 125°,BC = 8 cm. Find the diameter of the circumcircle. |
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Answer» Draw diameter BD and jon CD. In ΔBCD, sin55° = \(\frac{BC}{BD}\) BD = \(\frac{BC}{sin\,55^\circ}=\frac{8}{0.82}=9.76\) |
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