1.

In ΔABC, ∠A = 125°,BC = 8 cm. Find the diameter of the circumcircle.

Answer»

Draw diameter BD and jon CD.

In ΔBCD, sin55° = \(\frac{BC}{BD}\)

BD = \(\frac{BC}{sin\,55^\circ}=\frac{8}{0.82}=9.76\)



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