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1.0 mole of Fe reacts completely with 0.65 mole of `O_(2)` to give a mixture of only FeO and `Fe_(2)O_(3)` the mole ratio of ferrous oxide to ferric oxide isA. `2:2`B. `4:3`C. `1:2`D. `2:7` |
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Answer» Correct Answer - B `underset("a mole")(2Fe)+underset((a)/(2)"mole")(O_(2))tounderset(a)(2FeO)` `underset(b)(4Fe)+underset((3b)/(4))(3O_(2))tounderset((b)/(2))(2Fe_(2)O_(3))` `thereforea+b=1` `(a)/(2)+(3b)/(4)=0.65` `thereforea=0.4` mole `b=0.6` mole `therefore` moles of `FeO=0.4` moles of `Fe_(2)O_(3)=0.3` `therefore` ratio `=4:3` |
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