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`P(g)+2Q(g)toPQ_(2)(g),DeltaH=18kJmol^(-1)` The entropy change of the above reaction `(DeltaS_("system")` is 60 `JK^(-1)mol^(-1))`. At what temperature the reaction becomes spontaneous?A. Below 200 KB. Above 300 KC. Below 300 KD. Above 200 K and below 300 K. |
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Answer» Correct Answer - B For spontaneous process `DeltaGlt0` `thereforeDeltaH-TDeltaSlt0,DeltaHltTDeltaS` `thereforeTgt(DeltaH)/(DeltaS)=(18000)/(60)=300K` |
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