Explore topic-wise InterviewSolutions in .

The correct answer is Cache Memory.

• ​Cache memory
  • It is a high-speed storage area for temporary storage.
  • It is the smaller and fastest memory component in the computer.
  • It is used during the reading and writing processes from the disk.
  • It acts as a buffer between RAM and the CPU.
• CD ROM
  • It is a pre-pressed optical compact disc that contains data.
  • It is read-only.
  • Computers can read but not write or erase data on CD-ROMs.
• Hard Disk
  • It is rigid magnetic disc that stores data.
  • It is located within a drive unit.
  • It is a non-volatile storage device that contains platters and magnetic disks rotating at high speeds.
• Auxiliary Memory
  • It is known as the lowest-cost, highest-capacity and slowest-access storage in a computer system.
  • It is where programs and data are kept for long-term storage or when not in immediate use.
  • The most common examples of auxiliary memories are magnetic tapes and magnetic disks.

• ROM: Read-Only Memory
  • It refers to computer memory chips containing permanent or semi-permanent data.
  • It is non-volatile.
  • The data remains intact even when the power is switched off.
  • It contains the programming needed to start a PC, which is essential for boot-up.
  • It performs major input/output tasks and holds programs or software instructions.
  • It is the permanent memory built into your computer.
• RAM: Random Access Memory
  • It is a hardware device that allows information to be stored and retrieved on a computer.
  • It is volatile.
  • The data is erased even when the power is switched off.
  • The programs and data that the CPU requires during the execution of a program are stored in this memory.

The correct answer is Port.

• A Computer Port is an interface or a point of connection between the computer and its peripheral devices. 
• Based on the type of protocol used for communication, computer ports can be of two types: Serial Ports and Parallel Ports.
• In Computers, communication ports can be divided into two types based on the type of protocol used for communication.

• A bus is a high-speed internal connection. Buses are used to send control signals and data between the processor and other components. Generally, three types of buses are used.
• The bus contains multiple wires (signal lines) with addressing information describing the memory location of where the data is being sent or retrieved.
• Zip is a common type of file compression. "Zipping" one or more files creates a compressed archive that takes up less disk space than the uncompressed version. It is useful for backing up files and reducing the size of data transferred over the Internet.
• ZIP is a common file format that's used to compress one or more files together into a single location. This reduces file size and makes it easier to transport or store. A recipient can unzip (or extract) a ZIP file after transport and use the file in the original format.
• A ring network is a network topology in which each node connects to exactly two other nodes, forming a single continuous pathway for signals through each node-a ring. Data travels from node to node, with each node along the way handling every packet.

The correct answer is Understanding.

• A computer can perform inputting, processing, and controlling but it can't perform understanding as it has no brain.
• It can't earn from its previous experiences.

• Computing is the process of using computer technology to complete a given goal-oriented task.
• Computing may encompass the design and development of software and hardware systems for a broad range of purposes - often structuring, processing and managing any kind of information - to aid in the pursuit of scientific studies, making intelligent systems, and creating and using different media for entertainment and communication.
• Computer processing is an action or series of actions that a microprocessor, also known as a central processing unit (CPU), in a computer performs when it receives information.
• There are four distinct states that processing goes through in order to produce meaningful data output for any program.
• Output is data that a computer sends. Computers only work with digital information. Any input that a computer receives must be digitized.

The correct answer is A @.

• Programming language -
  • It is an artificial language, programming languages ​​are used especially with computers.
  • It can also be used to write programs, to accurately express algorithms, or as a means of human communication.
  • There are about 2,500 programming languages ​​available at the moment.
  • Some programming languages ​​are Pascal, Basic, Fortran, C, C++, Java, JavaScript, Python, Lisp, etc.

• "C" is a commonly used computer programming language.
• It was developed by Dennis Ritchie in 1972 with the aim of creating the Unix operating system.
• "C++" is a programming language created by 'Bjarne Stroustrup'.
  • This language was initially standardized in 1998.

The correct answer is Paint Brush.

• BASIC:
  • This programming language was first designed by John G. Kemeny and Thomas E. Kurtz in 1964.
  • The full form of BASIC is - Beginner's All-Purpose Symbolic Instruction Code.
  • It is generally used for scientific and engineering operations.
  • The introduction of newer machines with far greater capabilities made this language nearly obsolete and its upgraded version called Visual BASIC was released by Microsoft in 1991.
• ​C++:
  • ​The programming language was created by Bjarne Stroustrup in the mid-1980s as an extension to the C language.
  • It is an object-oriented language having two main components - direct mapping of hardware and zero-overhead abstractions.
  • The other languages like Java etc were influenced by C++.
• ​JAVA:
  • ​The programming language was designed by James Gosling at Sun Microsystems and was first released in the year 1995.
  • Java language is not platform-dependent and can be used to develop android applications.
  • The most recent version of Java, i.e. Java SE 16 got released in March 2021.
• PAINT BRUSH:
  • Paint is software that enables users to create basic graphic art on their systems.
  • The software has been developed by Microsoft and is found in all the versions of Microsoft Windows.
  • Recently in April 2021, Microsoft has made Microsoft Paint updateable from the Microsoft Store.

The Correct Answer is Science.

• 'Fortran' is a computer programming language that is extensively used in numerical, scientific computing.
• 'Fortran' was originally developed by IBM in the 1950s for scientific and engineering applications. 

• 'Fortran' is used in computationally intensive areas such as numerical weather prediction, computational fluid dynamics, finite element analysis, geophysics, crystallography, computational physics and computational chemistry.
• 'Fortran' is a popular language for high-performance computing and is used for programs that benchmark and rank the world's fastest supercomputers.

lim_(x → 0)(e^3x - 1)/x = 3 

lim_(x →0) (e^3x - 1)/3x

= 3(1)

= 3

∴ lim_(x → 0) (e^3x - 1)/x = 3

Given A = (–2, 3, 4)

B = (1, 2, 3)

XZ - Plane divides the line joining AB in the ratio

= –y₁ : y₂

= –3 : 2

= 3 : 2 externally

Given straight line equations are

x + P = 0   ...... (1)

y + 2 = 0 ⇒ y = –2  ...... (2)

3x + 2y + 5 = 0  ....... (3)

Solving (2) & (3)

3x + 2(–2) + 5 = 0

⇒ 3x + 1 = 0

⇒ x = −1/3

Point of intersection of (2) & (3) is  (−1/3, - 2)

Since (1), (2), (3) are concurrent

This point lies on (1)

⇒ −1/3 + P = 0

⇒ P = 1/3

Let x – intercept = a

y – intercept = b

Given that a + b = 0 ⇒ b = –a

Intercept form x/a + y/b = 1 

⇒ x/a + y/(- a)  = 1

⇒ x – y = a

If this line passing through the point (–2, 4) then

–2 – 4 = a ⇒ a = –6

Hence required straight line equation is

x – y = –6

⇒ x – y + 6 = 0.

Correct option (c) 40

Explanation:

5r⁴ = 80 → r⁴ = 80/5 → r = 2. Thus, 4^th term = ar³ = 5 × (2)³ = 40.

Correct option (b) −100

Explanation:

View: 1 − 3 + 5 − 7 + 9 − 11 ..... 100 terms as (1 − 3) + (5 − 7) + (9 − 11) ...... 50 terms. 

Hence, −2 + −2 + −2 … 50 terms = 50 × −2 = −100. 

Correct option (a) 5

Explanation:

We get least term 5 and largest term 30 (since the largest term is 6 times the least term). 

The average of the A.P becomes (5 + 30)/2 = 17.5 Thus, 17.5 × n = 105 gives us: to get a total of 105 we need n = 6 i.e. 6 terms in this A.P. That means the A.P. should look like: 5, _, _, _, _, 30.

It can be easily seen that the common difference should be 5. The A.P, 5, 10, 15, 20, 25, 30 fits the situation. 

The same process used for option (b) gives us the A.P. 10, 35, 60. (10 + 35 + 60 = 105) and in the third option 15, 90 (15 + 90 = 105)

Hence, all the three options are correct. 

Correct option (a) 10

Explanation:

r = 3. 729 = 1/27 (3)^n-1,n − 1 = 9 or n = 10 

Correct option (c) 23

Explanation:

In order to count the number of terms in the AP, use the shortcut: 

[(last term − first term)/ common difference] + 1. In this case it would become: 

[(120 − 10)/5] + 1 = 23

Correct option (d) None of these

Explanation:

For this question too you would need to read the pattern of the values being followed. The given sum has 6 terms

It can be seen that the sum to 1 term = 1/3

Sum to 2 terms = 3/5

Sum to 3 terms = 5/7 

Hence, the sum to 6 terms would be 11/13. 

Correct option (b) 828

Explanation:

In a period of 1 day or 24 hours the clock would strike 1 + 2 + 3 + ….+ 23 = 276 times. 

In the course of 3 days the clock would strike 276 × 3 = 828 times.  

Correct option (b) −40

Explanation:

a + 5d = 8 and a + 19d = −20. Solving we get 14d 

= −28 → d = −2. 30th term = 20th term + 10d 

= −20 + 10 × (−2) = −40. 

Correct option (c) 756

Explanation:

Since this is a decreasing A.P. with first term positive, the maximum sum will occur upto the point where the progression remains non-negative. 54, 52, 50, ….. 0 

Hence, 28 terms × 27 = 756.

Here 1st term = a = 102 (which is the 1st term greater than 100 that is divisible by 6.) 

The last term less than 400, which is divisible by 6 is 396. 

The number of terms in the AP; 102, 108, 114…396 is 

given by [(396 – 102)/6] +1= 50 numbers. 

Common difference = d = 6 

So, S = 25 (204 + 294) = 12450

Correct option (b) 5586

Explanation:

The sum of the required series of integers would be given by 105 + 112 + 119 + ....294 = 28 × 199.5 = 5586.

Correct option (b) 7(10^{n + 1} −10 − 9n)/81

Explanation:

Solve this one through trial and error. For n = 2 terms the sum upto 2 terms is equal to 84. Putting n in the options it can be seen that for option (b) the sum to two terms would be given by 7 × (1000 − 10 − 18)/81 = 7 × 972/81 = 7 × 12 = 84.

Correct option (b) odd   

Explanation: 

If we take x = 4 and n = 1 then 1¹+ 2¹+ 3¹ = 6 is divisible by 1 + 2 + 3 =6. But for n = 2 

1² +2² +3² = 14 is not divisible by 6 again for n =3,1ⁿ + 2ⁿ + 3ⁿ  divisible by 6 and so on. 

So for every odd value of n, 1ⁿ +2ⁿ +3ⁿ +... +xⁿ  is always divisible by 1 + 2 + 3 + ….+ x.

Correct option (b) (10²ⁿ-1) x 4/9

Explanation: 

For 1 digit the sum would be 6² + 8, for 2 digits the sum would be 66² + 88 and so on. Checking the options gives us option (b) as the correct answer.

Correct option (b) G.P

Explanation:

2log b = log a+ log c or log b² = log ac or b² = ac, so a, b, c are in GP

Correct option (b) GP    

Explanation: 

You can try to fit in values to get the correct answer. a,b,c would be in GP. If we take x, y and z as 1,2,4 we get a,b,c as 4,2 and 1, respectively to keep a^x , b^y & c^z equal. 

Correct option (c) 99.2¹⁰¹ + 2    

Explanation: 

Solve this based on pattern of the options. The given series has 100 terms. For n = 100, the options can be converted as 

Option (a) = n × 2^{(n + 1)} + 2. This means that for 1 term, the sum should be 1 × 2² + 2 = 6. But we can see that for 1 term, the series has a sum of only 1 × 2 = 2. Hence, this option can be rejected. 

Option (c) satisfies the conditions.

Option (b) = (n − 1) × 2ⁿ + 2. For 1 term, this gives us a value of 2. For 2 terms, this gives us a value of 6, which does not match the actual value in the question.Hence, this option can be rejected.

Correct option(c) 44,550

Explanation:

The required sum would be given by the sum of the series 110, 121, 132, .... 990. The number of terms in this series = (990 − 110)/11 + 1 = 80 + 1 = 81. 

The sum of the series = 81 × 550 (average of 110 and 990) = 44,550.

Correct option(b) H.P

Explanation:

y² = xz, 1 + log x, 1 + log y, 1 + log z are in A.P. if 2 log y= log x + log z or y² = xz, 

Correct option (b) 48    

Explanation: 

Since the ratio of the 2nd to the fourth term is given as 1/4, we can conclude that the common ratio of the GP is 2. Also, a+ 8a= 108 → 9a = 108 → a = 12. Thus, x₃ = 48.

Correct option (c) 1098

Explanation:

6 × average of 113 and 253 = 6 × 183 = 1098.

Correct option (a) 19 years

Explanation:

We need the sum of the series 2000 + 2400 + 2800 to cross 100000. Trying out the options, we can see that in 20 years the sum of his savings would be: 2000 + 2400 + 2800 +…+ 9600. The sum of the series would be 20 × 5800 = 116000. If we remove the 20th year we will get the saving for 19 years. The series would be 2000 + 2400 + 2800 + … + 9200. Sum of the series would be 116000 − 9600 = 106400. If we remove the 19th year’s savings the savings would be 106400 − 9200 which would go below 100000. Thus, after 19 years his savings would cross 100000.

Correct option (a) 7,50,000

Explanation:

1001 + 1003 + 1005 + ... 1999 = 1500 × 500 = 7,50,000.

Correct option (d) 3/2

Explanation:

Solve this question by looking at hypothetical values for n and 2n terms. Suppose, we take the sum to 1 (n = 1) term of the first series and the sum to 2 terms (2n = 2) of the second series we would get B/A as 3/2 

For n = 2 and 2n = 4 we get A =5/2 and B = 15/4 and B/A = 15/4/5/2 = 3/2

Thus, we can conclude that the required ratio is always constant at 3/2 and hence the.

Correct option (d) 2nd term

Explanation: 

The corresponding AP would be 2.5, 1.0833,… This gives us a common difference of −1.4166. From the third term onwards, the AP and its reciprocal HP would both become negative. Hence, the largest term of the HP is the second term itself.

Correct option (b) 5000

Explanation:

We need to find the infinite sum of the GP: 1000, 800, 640….. (first term = 1000 and common ratio = 0.8) We get: infinite sum of the series as 1000/ (1 − 0.8) = 5000, 

Correct option (c) 56/225

Explanation:

Questions such as these have to be solved on the basis of a reading of the pattern of the question. The sum upto the first term is: 1/5. Upto the second term it is 2/9 and upto the third term it is 3/12. It can be easily seen that for the first term, second term and third term the numerators are 1, 2 and 3 respectively. Also, for 1/5 — the 5 is the second value in the denominator of 1/1 × 5 (the first term); for 2/9 also the same pattern is followed— as 9 comes out of the denominator of the second term of series and tar 3/13 the 13 comes out of the denominator of the third term of the series and so on. The given series has 56 terms and hence the correct answer would be 56/225. 

Given:

We have to find, (√ 676 - √ 576)/(√ 225 - √ 121) = ?

Calculations:

√ 676 = 26 and √ 576 = 24

√ 225 = 15 and √ 121 = 11

So, (√ 676 - √ 576)/(√ 225 - √ 121) 

= (26 - 24)/(15 - 11)

= 2/4 = 1/2

√ 5625 = 75 and √ 625 = 25

Now, √ 5625/√ 625 = 75/25 = 3

Correct option (a)15 -√3 

Explanation:

Solve this on the same pattern as Question 31 and you can easily see that for the first term sum of the series is 2 -√3, for 2 terms we have the sum as √5 -√3 and so on. For the given series of 120 terms the sum would be √225 -√3 = 15 -√3.

√ 2304 = 48 and √ 576 = 24

So √ 2304 ÷ √ 576 = 48 ÷ 24 = 2

Given:

Downstream distance : Upstream distance = 3 : 1

Speed of stream = 4 km/hr

Downstream time = Upstream time

Concept Used:

Componendo-dividendo Concept

If (a + b)/(a - b) = c/d, then

a/b = (c + d)/(c - d)

Formula Used:

Speed = Distance/Time

D = B + S

U = B - S

where, D → Downstream speed, U → Upstream speed, B → Speed of boat in still water, S → Speed of stream.

Calculations:

Let the time taken for downstream and upstream be t hours each.

Let the distance for downstream and upstream be d₁ and d₂ respectively.

Speed = Distance/Time

D = d₁/t

⇒ (B + S) =  d1/t

⇒ d1 = (B + 4) × t      ----(1)

Similarly, U = d2/t

⇒ (B - S) =  d2/t

⇒ d2 = (B - 4) × t      ----(2)

d₁ : d₂ = 3 : 1

From (1) and (2), we get

[(B + 4) × t]/[(B - 4) × t] = 3/1

⇒ (B + 4)/(B - 4) = 3/1

Using componendo-dividendo, we get

(B + 4) + (B - 4)/(B + 4) - (B - 4) = 3 + 1/3 - 1

⇒ B/4 = 2 / 1

⇒ B = 8 km/hr

∴ The speed of boy in still water is 8 km/hr.

Short Trick/Topper's Approach:

Let the distance for downstream and upstream be d₁ and d2 respectively.

Speed = Distance/Time

For Time = constant,

Speed ∝ Distance

d1 : d2 = 3 : 1

⇒ D : U = 3 : 1 

⇒ (B + S) : (B - S) = 3 : 1

⇒ (B + 4)/(B - 4) = 3/1

Using componendo-dividendo, we get

(B + 4) + (B - 4)/(B + 4) - (B - 4) = 3 + 1/3 - 1

⇒ B/4 = 2 / 1

⇒ B = 8 km/hr

∴ The speed of boy in still water is 8 km/hr.

√225 = 15

Now, (√225 × 5) ÷ 5

= (15 × 5) ÷ 5

= 15

√ 7803 = √ (3 × 3 × 3 × 17 × 17) = 17 × 3 × √ 3 = 51√ 3

Given:

Athlete = double distance, 1/3 of time

Formula used:

Speed = Distance / time

Calculations:

Let Distance covered by boy be D, speed be S and time be T,

⇒ Distance by athlete D’ = 2 × D

⇒ Time taken by athlete T’ = (1/3) × T

⇒ Speed of boy S = D / T     ____(1)

⇒ Speed of athlete = D’ / T’

⇒ Speed of athlete = 2 × D / ((1/3) × T)

⇒ S’ = 6 × (D / T)

⇒ S’ = 6 × S     ____(From Eqn (1))

⇒ S / S’ = 1 / 6

∴ The required ratio is 1 : 6 

√196 = 14 and √256 = 16

so, (√196 + √256)/15 

⇒ (14 + 16)/15

⇒  30/15

∴ 2

Given:

Length of first train = 70 m

Length of second train = 90 m

Speed of first train = 10 m/s

Speed of second train = 6 m/s

Formula Used:

Speed = Distance/Time

Concept Used:

When two trains are moving in opposite direction their length and speed be added.

Calculation:

Total length of both train = 70 + 90 =160 m

Total speed of both train = 10 + 6 = 16 m/s

∴ Time taken by trains to cross each other = 160/16 = 10 sec.

√ 144 = 12 and √ 256 = 16

(√ 144 × √ 256)/2 = (12 × 16)/2 = 96

Given:

Speed on vehicle = 36 kmph,

time = 20 minutes = 1200 seconds

Total distance = 25% cycle + 20% bike + 55% rickshaw

Formula used:

Speed = Distance / time

1 kmph = 5/18 m/s

Calculations:

Calculating total distance first

⇒ Distance = speed × time

⇒ D = 36 × 5 × 1200 / 18

⇒ D = 12000 m

Now,

⇒ Total distance D = 0.25D + 0.20D + 0.55D

⇒ Distance covered in rickshaw = 0.55 × 12000

⇒ Distance covered in rickshaw = 6600 m

∴ Distance covered in rickshaw by student is 6600 m

Calculation:

for a perfect cube the prime number comes three times 

17 × 17 × 17 = 4913