(666…. n digits)2 + (888… n digits) is equal to(a) (10n-1) x 4/9(

1.	(666…. n digits)2 + (888… n digits) is equal to(a) (10n-1) x 4/9(b) (102n-1) x 4/9(c) 4(10n-10n-1-1)/9(d) 4(10n+1)/9
Answer» Correct option (b) (10²ⁿ-1) x 4/9 Explanation: For 1 digit the sum would be 6² + 8, for 2 digits the sum would be 66² + 88 and so on. Checking the options gives us option (b) as the correct answer.

(666…. n digits)2 + (888… n digits) is equal to(a) (10n-1) x 4/9(b) (102n-1) x 4/9(c) 4(10n-10n-1-1)/9(d) 4(10n+1)/9

Answer»

Correct option (b) (10²ⁿ-1) x 4/9

Explanation:

For 1 digit the sum would be 6² + 8, for 2 digits the sum would be 66² + 88 and so on. Checking the options gives us option (b) as the correct answer.

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(666…. n digits)2 + (888… n digits) is equal to(a) (10n-1) x 4/9(b) (102n-1) x 4/9(c) 4(10n-10n-1-1)/9(d) 4(10n+1)/9

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