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A student covers 25% of the distance to school on cycle, 20% of the distance on a bike, and rest in a rickshaw. While coming back he gets a lift from his father whose vehicle speed was 36 kmph and they reached home in 20 minutes. Calculate the distance covered by the boy in the rickshaw.1. 7200 m2. 6000 m3. 6600 m4. 5800 m |
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Answer» Correct Answer - Option 3 : 6600 m Given: Speed on vehicle = 36 kmph, time = 20 minutes = 1200 seconds Total distance = 25% cycle + 20% bike + 55% rickshaw Formula used: Speed = Distance / time 1 kmph = 5/18 m/s Calculations: Calculating total distance first ⇒ Distance = speed × time ⇒ D = 36 × 5 × 1200 / 18 ⇒ D = 12000 m Now, ⇒ Total distance D = 0.25D + 0.20D + 0.55D ⇒ Distance covered in rickshaw = 0.55 × 12000 ⇒ Distance covered in rickshaw = 6600 m ∴ Distance covered in rickshaw by student is 6600 m |
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