1.

If 1n + 2n + 3n + … + xn is always divisible by 1 + 2 + 3 + ….+ x then n is (a) Even (b) odd (c) Multiple of 2 (d) None of these

Answer»

Correct option (b) odd   

Explanation: 

If we take x = 4 and n = 1 then 11+ 21+ 31 = 6 is divisible by 1 + 2 + 3 =6. But for n = 2 

12 +22 +32 = 14 is not divisible by 6 again for n =3,1+ 2n + 3n  divisible by 6 and so on. 

So for every odd value of n, 1n +2n +3n +... +xn  is always divisible by 1 + 2 + 3 + ….+ x.



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