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Find the sum of all numbers divisible by 6 in between 100 to 400. |
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Answer» Here 1st term = a = 102 (which is the 1st term greater than 100 that is divisible by 6.) The last term less than 400, which is divisible by 6 is 396. The number of terms in the AP; 102, 108, 114…396 is given by [(396 – 102)/6] +1= 50 numbers. Common difference = d = 6 So, S = 25 (204 + 294) = 12450 |
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